Matplotlib.pyplot.gci() in Python

# Implementation of matplotlib function 
import matplotlib.pyplot as plt 
import numpy as np 
import matplotlib.gridspec as gridspec 
from mpl_toolkits.axes_grid1 import make_axes_locatable 
  
  
plt.close('all') 
arr = np.arange(100).reshape((10, 10)) 
fig = plt.figure(figsize =(4, 4)) 
im = plt.imshow(arr,  
                interpolation ="none", 
                cmap ="plasma") 
  
divider = make_axes_locatable(plt.gca()) 
cax = divider.append_axes("left",  
                          "15 %", 
                          pad ="30 %") 
  
plt.colorbar(im, cax = cax) 

print("The current colorable artist is :")
print(plt.gci())

fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight ="bold") 

plt.show() 

# Implementation of matplotlib function
import matplotlib.pyplot as plt
from scipy import sin, cos


fig, ax = plt.subplots(2, 1)
x = [1, 2, 3, 4, 5, 6, 7, 8, 9]

y1 = sin(x)
y2 = cos(x)

plt.sca(ax[0])
plt.plot(x, y1)

plt.sca(ax[1])
plt.plot(x, y2)

print("The current colorable artist is :")
print(plt.gci())

fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight ="bold") 

plt.show()