Make all even values inside loop equal in given Linked list

Last Updated : 23 Dec, 2023

Given a linked list that contains integers, your task is to find the minimum cost for making all even numbers that are inside the cycle equal. You can perform the below-mentioned operations to achieve this :

Increase a node's value by 1, this will cost 1 operation.
Decrease a node's value by 1, this will cost 1 operation.

Examples :

Input: 1->2->4->6->2
Output: 6
Explanation: Even numbers inside a loop are 2, 4, 6, and 2. To make them equal, they need to be converted into 3.

So, converting 2 -> 3 will cost 1 operation.
converting 4->3 will cost 1 operation.
converting 6->3 will cost 3 operations.
converting 2->3 will cost 1 operation.
Minimum Cost = 1 + 1 + 3 + 1 = 6 operations.

Input: 1->2->3->4->8->12->NULL
Output: 0
Explanation: Since there is no loop in the given linked list, therefore, the cost will be 0.

Approach: To solve this problem, follow the below-mentioned instructions step by step:

Start by detecting the loop in the linked list, if yes then proceed further otherwise directly return 0.
If there exists a loop then iterate inside the loop track even numbers present inside the loop and store them in a vector.
If the size of this vector is more than 1 (this shows that there are more than 1 even numbers so we need to make them equal) then pass this vector to findMinCost function otherwise return 0.
In findMinCost, find average of all the elements in array, this average number is the number which every array element should be converted to.
Then iterate over the array again and calculate the absolute difference between current element and average value, add this sum of all elements and then return it.

Below Code is the implementation of above approach in C++.

C++

// C++ program for the above mentioned approach
#include <bits/stdc++.h>
using namespace std;
// Link list node
class Node {
public:
    int data;
    Node* next;
};

// Function that checks for loop in linked list,
// returns address of node inside loop if
// present otherwise returns null
Node* detectLoop(Node* head)
{
    Node *slow = head, *fast = head;
    while (slow && fast && fast->next) {
        slow = slow->next;
        fast = fast->next->next;

        // if loop detected then
        // returning the node address
        if (slow == fast) {
            return slow;
        }
    }

    // if no loop found then return NULL
    return NULL;
}

// Function for pushing node in linked list
void push(Node** head_ref, int new_data)
{
    /* allocate node */
    Node* new_node = new Node();

    /* put in the data */
    new_node->data = new_data;

    /* link the old list of the new node */
    new_node->next = (*head_ref);

    /* move the head to point to the new node */
    (*head_ref) = new_node;
}

// Function for calculating minimum cost which
// takes integer vector
int findMinCost(vector<int> arr)
{
    int avg = arr[0];

    // Calculating average
    for (int i = 1; i < arr.size(); i++) {
        avg = (avg + arr[i]) / 2;
    }
    int ans = 0;

    // For calculating sum of absolute
    // difference
    for (int i = 0; i < arr.size(); i++) {
        ans += abs(avg - arr[i]);
    }
    return ans;
}
// Main function which takes head node address
// and returns minimum cost
int minimumCost(Node* head)
{

    // For detecting loop
    Node* temp = detectLoop(head);
    if (!temp)

        // Return 0 if no loop found
        return 0;
    Node* temp2 = temp->next;
    vector<int> arr;
    if (temp->data % 2 == 0)
        arr.push_back(temp->data);
    while (temp2 != temp) {

        // if current data is even
        // then push it into the vector
        if (temp2->data % 2 == 0)
            arr.push_back(temp2->data);
        temp2 = temp2->next;
    }

    // when even numbers are more than 1
    if (arr.size() > 1) {
        return findMinCost(arr);
    }
    else {
        return 0;
    }
}

// Driver code
int main()
{
    // Start with the empty list
    Node* head = NULL;

    push(&head, 20);
    push(&head, 4);
    push(&head, 15);
    push(&head, 10);

    // Create a loop for testing
    head->next->next->next->next = head;

    cout << minimumCost(head);
    return 0;
}

Java

import java.util.*;

// Link list node
class Node {
    int data;
    Node next;

    // Constructor
    Node(int data) {
        this.data = data;
        this.next = null;
    }
}

public class Main {
    // Function that checks for a loop in the linked list,
    // returns the address of the node inside the loop if
    // present; otherwise, returns null
    static Node detectLoop(Node head) {
        Node slow = head, fast = head;
        while (slow != null && fast != null && fast.next != null) {
            slow = slow.next;
            fast = fast.next.next;

            // if loop detected then
            // return the node address
            if (slow == fast) {
                return slow;
            }
        }

        // if no loop found then return null
        return null;
    }

    // Function for pushing node in linked list
    static Node push(Node head, int new_data) {
        /* allocate node */
        Node new_node = new Node(new_data);

        /* link the old list to the new node */
        new_node.next = head;

        /* return the new head */
        return new_node;
    }

    // Function for calculating minimum cost which
    // takes integer list
    static int findMinCost(List<Integer> arr) {
        int avg = arr.get(0);

        // Calculating average
        for (int i = 1; i < arr.size(); i++) {
            avg = (avg + arr.get(i)) / 2;
        }
        int ans = 0;

        // For calculating the sum of absolute difference
        for (int i = 0; i < arr.size(); i++) {
            ans += Math.abs(avg - arr.get(i));
        }
        return ans;
    }

    // Main function which takes head node address
    // and returns minimum cost
    static int minimumCost(Node head) {
        // For detecting loop
        Node temp = detectLoop(head);
        if (temp == null)

            // Return 0 if no loop found
            return 0;
        Node temp2 = temp.next;
        List<Integer> arr = new ArrayList<>();
        if (temp.data % 2 == 0)
            arr.add(temp.data);
        while (temp2 != temp) {

            // if the current data is even
            // then push it into the list
            if (temp2.data % 2 == 0)
                arr.add(temp2.data);
            temp2 = temp2.next;
        }

        // when even numbers are more than 1
        if (arr.size() > 1) {
            return findMinCost(arr);
        } else {
            return 0;
        }
    }

    // Driver code
    public static void main(String[] args) {
        // Start with the empty list
        Node head = null;

        head = push(head, 20);
        head = push(head, 4);
        head = push(head, 15);
        head = push(head, 10);

        // Create a loop for testing
        head.next.next.next.next = head;

        System.out.println(minimumCost(head));
    }
}

Python3

# Node class for a linked list
class Node:
    def __init__(self, data):
        self.data = data
        self.next = None

# Function that checks for a loop in a linked list,
# returns the address of the node inside the loop if
# present, otherwise returns None
def detectLoop(head):
    slow = head
    fast = head

    while slow and fast and fast.next:
        slow = slow.next
        fast = fast.next.next

        # If a loop is detected, return the node address
        if slow == fast:
            return slow

    # If no loop is found, return None
    return None

# Function for pushing a node into a linked list
def push(head_ref, new_data):
    # Allocate a new node
    new_node = Node(new_data)

    # Link the old list to the new node
    new_node.next = head_ref

    # Move the head to point to the new node
    head_ref = new_node
    return head_ref

# Function for calculating the minimum cost which
# takes an integer list
def findMinCost(arr):
    avg = arr[0]

    # Calculating the average
    for i in range(1, len(arr)):
        avg = (avg + arr[i]) // 2

    ans = 0

    # For calculating the sum of absolute differences
    for i in range(len(arr)):
        ans += abs(avg - arr[i])

    return ans

# Main function which takes the head node address
# and returns the minimum cost
def minimumCost(head):
    # For detecting a loop
    temp = detectLoop(head)
    if not temp:
        # Return 0 if no loop found
        return 0

    temp2 = temp.next
    arr = []

    if temp.data % 2 == 0:
        arr.append(temp.data)

    while temp2 != temp:
        # If the current data is even, push it into the list
        if temp2.data % 2 == 0:
            arr.append(temp2.data)
        temp2 = temp2.next

    # When even numbers are more than 1
    if len(arr) > 1:
        return findMinCost(arr)
    else:
        return 0

# Driver code
if __name__ == "__main__":
    # Start with an empty list
    head = None

    head = push(head, 20)
    head = push(head, 4)
    head = push(head, 15)
    head = push(head, 10)

    # Create a loop for testing
    head.next.next.next.next = head

    print(minimumCost(head))

using System;
using System.Collections.Generic;

// Linked list node
class Node
{
    public int data;
    public Node next;
}
class GFG
{
    // Function that checks for loop in linked list
    static Node DetectLoop(Node head)
    {
        Node slow = head, fast = head;
        while (slow != null && fast != null && fast.next != null)
        {
            slow = slow.next;
            fast = fast.next.next;
            // if loop detected then returning the node address
            if (slow == fast)
            {
                return slow;
            }
        }
        // if no loop found then return NULL
        return null;
    }
    // Function for pushing node in the linked list
    static void Push(ref Node headRef, int newData)
    {
        Node newNode = new Node();
        newNode.data = newData;
        newNode.next = headRef;
        headRef = newNode;
    }
    // Function for calculating minimum cost which takes integer list
    static int FindMinCost(List<int> arr)
    {
        int avg = arr[0];
        // Calculating average
        for (int i = 1; i < arr.Count; i++)
        {
            avg = (avg + arr[i]) / 2;
        }
        int ans = 0;
        // For calculating sum of absolute difference
        for (int i = 0; i < arr.Count; i++)
        {
            ans += Math.Abs(avg - arr[i]);
        }
        return ans;
    }
    // Main function which takes head node address and returns minimum cost
    static int MinimumCost(Node head)
    {
        // For detecting loop
        Node temp = DetectLoop(head);
        if (temp == null)
            // Return 0 if no loop found
            return 0;
        Node temp2 = temp.next;
        List<int> arr = new List<int>();
        if (temp.data % 2 == 0)
            arr.Add(temp.data);
        while (temp2 != temp)
        {
            if (temp2.data % 2 == 0)
                arr.Add(temp2.data);
            temp2 = temp2.next;
        }
        // when even numbers are more than 1
        if (arr.Count > 1)
        {
            return FindMinCost(arr);
        }
        else
        {
            return 0;
        }
    }
    // Driver code
    static void Main()
    {
        // Start with the empty list
        Node head = null;
        Push(ref head, 20);
        Push(ref head, 4);
        Push(ref head, 15);
        Push(ref head, 10);
        // Create a loop for testing
        head.next.next.next.next = head;
        Console.WriteLine(MinimumCost(head));
    }
}

JavaScript

// Javascript code for the above approach

// Link list node
class Node {
    // Constructor
    constructor(data) {
        this.data = data;
        this.next = null;
    }
}

// Function that checks for a loop in the linked list,
// returns the address of the node inside the loop if
// present; otherwise, returns null
function detectLoop(head) {
    let slow = head,
        fast = head;
    while (slow != null && fast != null && fast.next != null) {
        slow = slow.next;
        fast = fast.next.next;

        // if loop detected then
        // return the node address
        if (slow == fast) {
            return slow;
        }
    }

    // if no loop found then return null
    return null;
}

// Function for pushing node in linked list
function push(head, new_data) {
    /* allocate node */
    const new_node = new Node(new_data);

    /* link the old list to the new node */
    new_node.next = head;

    /* return the new head */
    return new_node;
}

// Function for calculating minimum cost which
// takes integer list
function findMinCost(arr) {
    let avg = arr[0];

    // Calculating average
    for (let i = 1; i < arr.length; i++) {
        avg = Math.floor((avg + arr[i]) / 2);
    }
    let ans = 0;

    // For calculating the sum of absolute difference
    for (let i = 0; i < arr.length; i++) {
        ans += Math.abs(avg - arr[i]);
    }
    return ans;
}

// Main function which takes head node address
// and returns minimum cost
function minimumCost(head) {
    // For detecting loop
    const temp = detectLoop(head);
    if (temp == null)

        // Return 0 if no loop found
        return 0;
    let temp2 = temp.next;
    const arr = [];
    if (temp.data % 2 == 0)
        arr.push(temp.data);
    while (temp2 != temp) {

        // if the current data is even
        // then push it into the list
        if (temp2.data % 2 == 0)
            arr.push(temp2.data);
        temp2 = temp2.next;
    }

    // when even numbers are more than 1
    if (arr.length > 1) {
        return findMinCost(arr);
    } else {
        return 0;
    }
}

// Driver code
// Start with the empty list
head = null;

head = push(head, 20);
head = push(head, 4);
head = push(head, 15);
head = push(head, 10);

// Create a loop for testing
head.next.next.next.next = head;

console.log(minimumCost(head));

// This code is contributed by ragul21

Output

Time Complexity: O(N)
Auxiliary Space: O(N)

Make all even values inside loop equal in given Linked list

nikhil9402kj

Improve

Article Tags :

Practice Tags :

Linked List

Make all even values inside loop equal in given Linked list

Similar Reads

Thank You!

What kind of Experience do you want to share?

Log in

Create Account