How to Remove Multiple Objects from Nested Array of Objects in JavaScript ?
Last Updated :
23 Jul, 2025
A nested array of objects is an array of arrays that contain multiple objects as their elements. Removing multiple objects from the nested array of objects in JavaSript can be accomplished in different ways as listed below:
Using filter() with some() Method
This approach uses the filter() method with the some() method to remove objects from each inner array based on the condition that their id should not match any id in the objtoRemove array.
Syntax:
let newArray = originalArray.filter((element) => {
return !conditionArray.some((conditionElement) => condition);
});
Example: The below code uses the filter() with some() method to remove multiple objects from a nested array of objects in JavaScript.
JavaScript
let arr = [
[
{ id: 1, name: "Geek1" },
{ id: 2, name: "Geek2" },
],
[
{ id: 3, name: "Geek3" },
{ id: 4, name: "Geek4" },
],
];
let objToRemove = [
{ id: 2, name: "Geek2" },
{ id: 4, name: "Geek4" }
];
// removing objects using some function
let outputArr = arr.map((inArr) =>
inArr.filter((geek) =>
!objToRemove.some((obj) =>
obj.id === geek.id))
);
console.log("Before:", arr);
console.log("After:", outputArr);
OutputBefore: [
[ { id: 1, name: 'Geek1' }, { id: 2, name: 'Geek2' } ],
[ { id: 3, name: 'Geek3' }, { id: 4, name: 'Geek4' } ]
]
After: [ [ { id: 1, name: 'Geek1' } ], [ { id: 3, name: 'Geek3' } ] ]
Using filter() with includes() Method
This approach uses the filter() with includes() method to remove objects whose id matches an id in the objtoRemove array.
Syntax:
let newArray = originalArray.filter((element) => {
return !conditionArray.map((conditionElement) => conditionElement.id).includes(element.id);
});
Example: The below code uses the filter() with includes() method to remove multiple objects from a nested array of objects in JavaScript.
JavaScript
let arr = [
[
{ id: 1, name: "Geek1" },
{ id: 2, name: "Geek2" },
],
[
{ id: 3, name: "Geek3" },
{ id: 4, name: "Geek4" },
],
];
let objToRemove = [
{ id: 2, name: "Geek2" },
{ id: 4, name: "Geek4" }
];
// removing objects using map and includes functions
let outputArr = arr.map((inArr) =>
inArr.filter((geek) =>
!objToRemove.map((obj) => obj.id).includes(geek.id)
)
);
console.log("Before:", arr);
console.log("After:", outputArr);
OutputBefore: [
[ { id: 1, name: 'Geek1' }, { id: 2, name: 'Geek2' } ],
[ { id: 3, name: 'Geek3' }, { id: 4, name: 'Geek4' } ]
]
After: [ [ { id: 1, name: 'Geek1' } ], [ { id: 3, name: 'Geek3' } ] ]
Using filter( ) with findIndex() Method
This approach uses the filter() with the findIndex() method to remove objects from the inner array where the id matches any id in the objToRemove array using the findIndex() method.
Syntax:
let newArray = originalArray.map((elementArray) =>
elementArray.filter((element) =>
objArray.findIndex((obj) => obj.id === element.id) === -1
)
);
Example: The below code uses the filter() with findIndex() method to remove multiple objects from a nested array of objects in JavaScript.
JavaScript
let arr = [
[
{ id: 1, name: "Geek1" },
{ id: 2, name: "Geek2" },
],
[
{ id: 3, name: "Geek3" },
{ id: 4, name: "Geek4" },
],
];
let objToRemove = [
{ id: 2, name: "Geek2" },
{ id: 4, name: "Geek4" }
];
// removing objects using findIndex function
let outputArr = arr.map((inArr) =>
inArr.filter((geek) =>
objToRemove.findIndex((obj) => obj.id === geek.id) === -1
)
);
console.log("Before:", arr);
console.log("After:", outputArr);
OutputBefore: [
[ { id: 1, name: 'Geek1' }, { id: 2, name: 'Geek2' } ],
[ { id: 3, name: 'Geek3' }, { id: 4, name: 'Geek4' } ]
]
After: [ [ { id: 1, name: 'Geek1' } ], [ { id: 3, name: 'Geek3' } ] ]
Using filter() with reduce() Method
This approach uses the filter() with reduce() method to remove objects from each inner array where the id matches an id in the objToRemove array.
Syntax:
let newArray = originalArray.map((elementArray) =>
elementArray.reduce((accumulator, element) => {
// condition
if (/* condition */) {
accumulator.push(element);
}
return accumulator;
}, [])
);
Example: The below code uses the filter() with reduce() method to remove multiple objects from a nested array of objects in JavaScript.
JavaScript
let arr = [
[
{ id: 1, name: "Geek1" },
{ id: 2, name: "Geek2" },
],
[
{ id: 3, name: "Geek3" },
{ id: 4, name: "Geek4" },
],
];
let objToRemove = [
{ id: 2, name: "Geek2" },
{ id: 4, name: "Geek4" }
];
// Removing objects using some function
let outputArr = arr.map((inArr) =>
inArr.reduce((acc, geek) => {
if (!objToRemove.some((obj) => obj.id === geek.id)) {
acc.push(geek);
}
return acc;
}, [])
);
console.log("Before:", arr);
console.log("After:", outputArr);
OutputBefore: [
[ { id: 1, name: 'Geek1' }, { id: 2, name: 'Geek2' } ],
[ { id: 3, name: 'Geek3' }, { id: 4, name: 'Geek4' } ]
]
After: [ [ { id: 1, name: 'Geek1' } ], [ { id: 3, name: 'Geek3' } ] ]
Using filter() with Set for Efficient Removal
In this approach, we use a Set to store the IDs of the objects we want to remove for efficient look-up. We then use filter() to remove objects based on whether their IDs are present in the Set.
Example:
JavaScript
let arr = [
[
{ id: 1, name: "Geek1" },
{ id: 2, name: "Geek2" },
],
[
{ id: 3, name: "Geek3" },
{ id: 4, name: "Geek4" },
],
];
let objtoRemove = [
{ id: 2, name: "Geek2" },
{ id: 4, name: "Geek4" }
];
// Create a Set of IDs to remove
let idsToRemove = new Set(objtoRemove.map(obj => obj.id));
// Remove objects using filter and Set
let outputArr = arr.map(innerArr => innerArr.filter(obj => !idsToRemove.has(obj.id)));
console.log("Before:", arr);
console.log("After:", outputArr);
OutputBefore: [
[ { id: 1, name: 'Geek1' }, { id: 2, name: 'Geek2' } ],
[ { id: 3, name: 'Geek3' }, { id: 4, name: 'Geek4' } ]
]
After: [ [ { id: 1, name: 'Geek1' } ], [ { id: 3, name: 'Geek3' } ] ]
Using filter() with every() Method
In this approach, the filter() method is combined with the every() method to remove objects from each inner array. The every() method checks that no objects in the objToRemove array match the IDs of objects in the nested arrays. This approach is useful when you want to ensure that none of the objects to remove are present in the nested arrays.
Syntax:
let newArray = originalArray.map((innerArray) =>
innerArray.filter((element) =>
conditionArray.every((conditionElement) => conditionElement.id !== element.id)
)
);
Example: The code below uses the filter() with every() method to remove multiple objects from a nested array of objects in JavaScript
JavaScript
let arr = [
[
{ id: 1, name: "Nikunj" },
{ id: 2, name: "Yash" },
],
[
{ id: 3, name: "Dhruv" },
{ id: 4, name: "Arti" },
],
];
let objToRemove = [
{ id: 2, name: "Yash" },
{ id: 4, name: "Arti" }
];
// Removing objects using every function
let outputArr = arr.map((inArr) =>
inArr.filter((geek) =>
objToRemove.every((obj) => obj.id !== geek.id)
)
);
console.log("Before:", arr);
console.log("After:", outputArr);
OutputBefore: [
[ { id: 1, name: 'Nikunj' }, { id: 2, name: 'Yash' } ],
[ { id: 3, name: 'Dhruv' }, { id: 4, name: 'Arti' } ]
]
After: [ [ { id: 1, name: 'Nikunj' } ], [ { id: 3, name: 'Dhruv' } ] ]
Example: The below code demonstrates the use of the filter() method with a Set to remove multiple objects from a nested array of objects in JavaScript.
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