Java Program for KMP Algorithm for Pattern Searching Last Updated : 10 Jan, 2024 Summarize Comments Improve Suggest changes Share Like Article Like Report Given a text txt[0..n-1] and a pattern pat[0..m-1], write a function search(char pat[], char txt[]) that prints all occurrences of pat[] in txt[]. You may assume that n > m. Examples: Input: txt[] = "THIS IS A TEST TEXT" pat[] = "TEST" Output: Pattern found at index 10 Input: txt[] = "AABAACAADAABAABA" pat[] = "AABA" Output: Pattern found at index 0 Pattern found at index 9 Pattern found at index 12 Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.KMP Algorithm for Pattern SearchingPattern searching is an important problem in computer science. When we do search for a string in notepad/word file or browser or database, pattern searching algorithms are used to show the search results. Program for KMP Algorithm for Pattern SearchingBelow is the implementation of KMP Algorithm: Java // JAVA program for implementation of KMP pattern // searching algorithm class KMP_String_Matching { void KMPSearch(String pat, String txt) { int M = pat.length(); int N = txt.length(); // create lps[] that will hold the longest // prefix suffix values for pattern int lps[] = new int[M]; int j = 0; // index for pat[] // Preprocess the pattern (calculate lps[] // array) computeLPSArray(pat, M, lps); int i = 0; // index for txt[] while (i < N) { if (pat.charAt(j) == txt.charAt(i)) { j++; i++; } if (j == M) { System.out.println("Found pattern " + "at index " + (i - j)); j = lps[j - 1]; } // mismatch after j matches else if (i < N && pat.charAt(j) != txt.charAt(i)) { // Do not match lps[0..lps[j-1]] characters, // they will match anyway if (j != 0) j = lps[j - 1]; else i = i + 1; } } } void computeLPSArray(String pat, int M, int lps[]) { // length of the previous longest prefix suffix int len = 0; int i = 1; lps[0] = 0; // lps[0] is always 0 // the loop calculates lps[i] for i = 1 to M-1 while (i < M) { if (pat.charAt(i) == pat.charAt(len)) { len++; lps[i] = len; i++; } else // (pat[i] != pat[len]) { // This is tricky. Consider the example. // AAACAAAA and i = 7. The idea is similar // to search step. if (len != 0) { len = lps[len - 1]; // Also, note that we do not increment // i here } else // if (len == 0) { lps[i] = len; i++; } } } } // Driver program to test above function public static void main(String args[]) { String txt = "ABABDABACDABABCABAB"; String pat = "ABABCABAB"; new KMP_String_Matching().KMPSearch(pat, txt); } } OutputFound pattern at index 10 Complexity of the above Method:Time Complexity: O(m+n)Space Complexity: O(m) Please refer complete article on KMP Algorithm for Pattern Searching for more details! 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