Java.lang.Math Class in Java | Set 2

Last Updated : 13 Sep, 2023

Java.lang.Math Class in Java | Set 1 More Methods:

cosh() : java.lang.Math.cosh() method returns the hyperbolic cosine of the argument passed. Special cases :
- Result is NaN, if argument is NaN.
- Result is 1.0, if the argument is zero.
- Result is +ve infinity, if argument is infinite.
Syntax:
```
public static double cosh(double arg)
Parameters:
arg - The number whose hyperbolic cosine is to be returned.
Returns:
the hyperbolic cosine of the argument arg.
```

decrementExact() : java.lang.Math.decrementExact() method decrements the value of passed argument by one. Syntax:

public static int decrementExact(int arg)
                or
public static long decrementExact(long arg)
Parameters:
arg - argument passed. 
Returns:
return argument decremented by one.
Throws:
Exception if the result overflows long or int datatype, according to the
argumented data type.

exp() : java.lang.Math.exp(double arg) method returns the Euler’s number raised to the power of double argument. Important cases:
- Result is NaN, if argument is NaN.
- Result is +ve infinity, if the argument is +ve infinity.
- Result is +ve zero, if argument is -ve infinity.
Syntax:
```
public static double exp(double arg)
Parameters:
arg - argument passed. 
Returns:
Euler’s number raised to the power of passed argument
```

Java code explaining exp(), decrementExact(), cosh() method in lang.Math class.

Java

// Java program explaining lang.Math class methods
// exp(), decrementExact(), cosh()

import java.math.*;
public class NewClass
{
    public static void main(String[] args)
    {
        // Use of cosh() method
        double value = 2;
        double coshValue = Math.cosh(value);
        System.out.println("Hyperbolic Cosine of "  + coshValue);
        System.out.println("");

        // Use of decrementExact() method
        int result = Math.decrementExact(3051);
        System.out.println("Use of decrementExact() : " + result);
        System.out.println("");


        // Use of exp() method
        // declare the exponent to be used
        double exponent = 34;
        // raise e to exponent declared
        double expVal = Math.exp(exponent);
        System.out.println("Value of exp : "+ expVal);

    }
}

Output:

Using addExact() : 9

acos value of Asini : NaN
acos value of Asinj : 0.054858647341251204

cube root : 6.0

incrementExact() : java.lang.Math.incrementExact() method returns the argument by incrementing it's value.

Syntax:
public static int incrementExact(int arg)
               or
public static long incrementExact(long arg)
Parameters:
arg - the argument
Returns:
incremented value of the argument

log10() : java.lang.Math.log10() method returns the base10 logarithmic value of the passed argument.

Syntax:
public static double log(double arg)
Parameters:
arg - argument passed. 
Returns:
base10 logarithmic value of the argument passed.

pow() : java.lang.Math.pow(double b, double e) method returns the value as b^e

Syntax:
public static double pow(double b,double e)
Parameters:
b : base
e : exponent 
Returns:
value as base^exponent

JAVA code explaining incrementExact(), log10(), pow() method in lang.Math class.

Java

// Java program explaining lang.MATH class methods
// incrementExact(), log10(), pow()

import java.lang.*;
public class NewClass
{
    public static void main(String[] args)
    {
        // Use of incrementExact() method
        int f1 = 30, f2 = -56;
        f1 =Math.incrementExact(f1);
        System.out.println("Incremented value of f1 : "+f1);

        f2 =Math.incrementExact(f2);
        System.out.println("Incremented value of f2 : "+f2);
        System.out.println("");
       

        // Use of log10() method
        double value = 10;
        double logValue = Math.log10(value);
        System.out.println("Log10 value of 10 : "+logValue);
        System.out.println("");

        // Use of pow() method
        double b = 10, e = 2;
        double power = Math.pow(b,e);
        System.out.println("Use of pow() : "+power);

    }
}

Output :

Incremented value of f1 : 31
Incremented value of f2 : -55

Log10 value of 10 : 1.0

Use of pow() : 100.0

signum() : java.lang.Math.signum() method returns the signum value of the argument passed.

                                    -1    if x < 0
                    signum fun(x) =  0    if x = 0
                                     1    if x > 0

Note:

Syntax:

public static double signum(double x)
               or
public static float signum(float x)
Parameters:
x - the argument whose signum value we need
Returns:
signum value of x

round() : java.lang.Math.round() method round off the passed argument upto closest decimal places. Note: Result is 0, if the argument is NaN. Syntax:

public static long round(long arg)
             or
public static double round(double arg)
Parameters:
arg - argument needs to round off 
Returns:
round off value of the argument

max() : java.lang.Math.max(double v1, double v2) method returns the greater value out of the two passed argument values. This method just compares using magnitude without considering any sign. Syntax:
```
public static double max(double v1, double v2)
Parameters:
v1 - first value
v2 - second value
Returns:
v1 or v2 based on which number is greater.
It can return either of the two if v1 = v2. 
```

Java code explaining signum(), round(), max() method in lang.Math class.

Java

// Java code explaining the lang.Math Class methods
// signum(), round(), max()

import java.lang.*;
public class NewClass
{
    public static void main(String args[])
    {
        // Use of signum() method
        double x = 10.4556, y = -23.34789;
        double signm = Math.signum(x);
        System.out.println("Signum of 10.45  = "+signm);

        signm = Math.signum(y);
        System.out.println("Signum of -23.34 = "+signm);
        System.out.println("");

        // Use of round() method
        double r1 = Math.round(x);
        System.out.println("Round off 10.4556  = "+r1);

        double r2 = Math.round(y);
        System.out.println("Round off 23.34789 = "+r2);
        System.out.println("");

        // Use of max() method on r1 and r2
        double m = Math.max(r1, r2);
        System.out.println("Max b/w r1 and r2 = "+r2);

    }
}

Output:

Signum of 10.45  = 1.0
Signum of -23.34 = -1.0

Round off 10.4556  = 10.0
Round off 23.34789 = -23.0

Max b/w r1 and r2 = -23.0

log1p() : java.lang.Math.log1p() method returns natural log of (passed argument + 1). Syntax:

public static double log1p(double arg)
Parameters:
arg - the argument
Returns:
log of (argument + 1).
This result is within 1 unit in the last place of exact result.

ulp() : java.lang.Math.ulp() method returns Unit of least precision(ulp) ie. the least distance between two floating point numbers. Here, it is the least distance b/w the argument and next larger value. Syntax:
```
public static double ulp(double arg)
              or
public static float ulp(float arg)
Parameters:
arg - argument passed. 
Returns:
least distance b/w the argument and next larger value.
```

Java code explaining ulp(), log1p() method in lang.Math class.

Java

// Java code explaining the lang.Math Class methods
// ulp(), log1p()

import java.lang.*;
public class NewClass
{
    public static void main(String args[])
    {
        // Use of ulp() method
        double x = 34.652, y = -23.34789;
        double u = Math.ulp(x);
        System.out.println("ulp of 34.652    : "+u);

        u = Math.ulp(y);
        System.out.println("ulp of -23.34789 : "+u);
        System.out.println("");

        // Use of log() method
        double l = 99;
        double l1 = Math.log1p(l);
        System.out.println("Log of (1 + 99)  : "+l1);

        l1 = Math.log(100);
        System.out.println("Log of 100       : "+l1);

    }
}

Output:

ulp of 34.652    : 7.105427357601002E-15
ulp of -23.34789 : 3.552713678800501E-15

Log of (1 + 99)  : 4.605170185988092
Log of 100       : 4.605170185988092

Java.lang.Math Class in Java | Set 2

Mohit Gupta_OMG

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Java.lang.Math Class in Java | Set 2

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