How to declare a Two Dimensional Array of pointers in C?

#include <stdio.h>

// Drivers code
int main()
{
    int arr1[5][5] = { { 0, 1, 2, 3, 4 },
                       { 2, 3, 4, 5, 6 },
                       { 4, 5, 6, 7, 8 },
                       { 5, 4, 3, 2, 6 },
                       { 2, 5, 4, 3, 1 } };
    int* arr2[5][5];

    // Initialising each element of the
    // pointer array with the address of
    // element present in the other array
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            arr2[i][j] = &arr1[i][j];
        }
    }

    // Printing the array using
    // the array of pointers
    printf("The values are\n");
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            printf("%d ", *arr2[i][j]);
        }
        printf("\n");
    }

    return 0;
}

#include <stdio.h>
#include <stdlib.h>
// Drivers code
int main()
{
    int arr1[5][5] = { { 0, 1, 2, 3, 4 },
                       { 2, 3, 4, 5, 6 },
                       { 4, 5, 6, 7, 8 },
                       { 5, 4, 3, 2, 6 },
                       { 2, 5, 4, 3, 1 } };

    // Creating 2D array of pointers using Dynamic Memory
    // allocation through malloc() function
    int*** arr2 = malloc(5 * sizeof(int**));
    for (int i = 0; i < 5; i++)
        arr2[i] = malloc(5 * sizeof(int*));

    // Initialising each element of the
    // pointer array with the address of
    // element present in the other array
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            arr2[i][j] = &arr1[i][j];
        }
    }

    // Printing the array using
    // the array of pointers
    printf("The values are\n");
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            printf("%d ", *arr2[i][j]);
        }
        printf("\n");
    }

    return 0;
}