How Does the JSON.parse() Method Works in JavaScript? Last Updated : 21 Dec, 2024 Comments Improve Suggest changes Like Article Like Report The JSON.parse() method in JavaScript is used to convert a JSON string into a JavaScript object. This method is essential for working with JSON data, especially when fetching or processing data from APIs or external sources.Converts a JSON-formatted string into a JavaScript object.Maintains the structure of arrays, nested objects, and data types like numbers and strings.Supports a reviver function to transform values during parsing.It throws an error if the input JSON string is invalid. JavaScript const jsonS = '{"name": "Aarav", "age": 22, "city": "Delhi"}'; const obj = JSON.parse(jsonS); console.log(obj.name); OutputAarav jsonString is a valid JSON string.JSON.parse() converts the string into a JavaScript object.Object properties are accessed using dot notation.How the JSON.parse() Method Works1. Parsing Simple JSON StringsThe method processes JSON strings and maps key-value pairs to a JavaScript object. JavaScript const jsonS = '{"product": "Mobile", "price": 12000}'; const obj = JSON.parse(jsonS); console.log(obj.product); OutputMobile 2. Handling JSON ArraysIt seamlessly parses JSON strings representing arrays into JavaScript arrays. JavaScript const jsonA = '[{"name": "Riya"}, {"name": "Karan"}]'; const a = JSON.parse(jsonA); console.log(a[0].name); OutputRiya 3. Parsing Nested JSONThe method processes deeply nested JSON objects. JavaScript const nJson = '{"user": {"name": "Simran", "address": {"city": "Pune", "pin": 411001}}}'; const obj = JSON.parse(nJson); console.log(obj.user.address.city); OutputPune 4. Validating JSON During ParsingInvalid JSON strings throw a SyntaxError. You can use a try...catch block to handle these cases. JavaScript const invalidJson = '{"name": "Ajay", "age": 30'; try { JSON.parse(invalidJson); } catch (e) { console.error("Invalid JSON:", e.message); } 5. Using a Reviver FunctionThe reviver parameter modifies or filters values during the parsing process. JavaScript const jsonS = '{"price": "1500", "discount": "5"}'; const obj = JSON.parse(jsonS, (key, value) => { if (key === "price" || key === "discount") return parseFloat(value); return value; }); console.log(obj.price - obj.discount); Output1495 Create Quiz Comment A amanv09 Follow 0 Improve A amanv09 Follow 0 Improve Article Tags : JavaScript Web Technologies JavaScript-QnA JavaScript-JSON Explore JavaScript BasicsIntroduction to JavaScript4 min readVariables and Datatypes in JavaScript6 min readJavaScript Operators5 min readControl Statements in JavaScript4 min readArray & StringJavaScript Arrays7 min readJavaScript Array Methods7 min readJavaScript Strings5 min readJavaScript String Methods9 min readFunction & ObjectFunctions in JavaScript5 min readJavaScript Function Expression3 min readFunction Overloading in JavaScript4 min readObjects in JavaScript4 min readJavaScript Object Constructors4 min readOOPObject Oriented Programming in JavaScript3 min readClasses and Objects in JavaScript4 min readWhat Are Access Modifiers In JavaScript ?5 min readJavaScript Constructor Method7 min readAsynchronous JavaScriptAsynchronous JavaScript2 min readJavaScript Callbacks4 min readJavaScript Promise4 min readEvent Loop in JavaScript4 min readAsync and Await in JavaScript2 min readException HandlingJavascript Error and Exceptional Handling6 min readJavaScript Errors Throw and Try to Catch2 min readHow to create custom errors in JavaScript ?2 min readJavaScript TypeError - Invalid Array.prototype.sort argument1 min readDOMHTML DOM (Document Object Model)8 min readHow to select DOM Elements in JavaScript ?3 min readJavaScript Custom Events4 min readJavaScript addEventListener() with Examples9 min readAdvanced TopicsClosure in JavaScript4 min readJavaScript Hoisting6 min readScope of Variables in JavaScript3 min readJavaScript Higher Order Functions7 min readDebugging in JavaScript4 min read Like