Generate two output strings depending upon occurrence of character in input string.
Last Updated :
16 Jul, 2024
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Given an input string str[], generate two output strings. One of which consists of those character which occurs only once in input string and second which consists of multi-time occurring characters. Output strings must be sorted.
Examples:
Input : str[] = "geeksforgeeks"
Output : String with characters occurring once:
for
String with characters occurring multiple times:
egks
Input : str[] = "geekspractice"
Output : String with characters occurring once:
agikprst
String with characters occurring multiple times:
ce
Approach : We follow total two steps to generate the both output strings.
Step 1: Create a count array and count occurrences of characters in the given input string.
Step 2: Check count array for each position 'i' which leads to three possible conditions :
a) If count value is 1, append character in first output string.
b) If count value is greater than 1, append character in second output string.
c) If count value is 0 do nothing.
Time Complexity for above approach is O(n).
Auxiliary Space required is O(1).
// CPP program to print two strings
// made of character occurring once
// and multiple times
#include <bits/stdc++.h>
using namespace std;
const int MAX_CHAR = 256;
// function to print two strings
// generated from single string one
// with characters occurring once
// other with character occurring
// multiple of times
void printDuo(string &str)
{
// initialize hashtable with zero
// entry
int countChar[MAX_CHAR] = { 0 };
// perform hashing for input string
int n = str.length();
for (int i = 0; i < n; i++)
countChar[str[i] - 'a']++;
// generate string (str1) consisting
// char occurring once and string
// (str2) consisting char occurring
// multiple times
string str1 = "", str2 = "";
for (int i = 0; i < MAX_CHAR; i++) {
if (countChar[i] > 1)
str2 = str2 + (char)(i + 'a');
else if (countChar[i] == 1)
str1 = str1 + (char)(i + 'a');
}
// print both strings
cout << "String with characters occurring "
<< "once:\n";
cout << str1 << "\n";
cout << "String with characters occurring "
<< "multiple times:\n";
cout << str2 << "\n";
}
// driver program
int main()
{
string str = "lovetocode";
printDuo(str);
return 0;
}
// Java program to print two strings
// made of character occurring once
// and multiple times
class GFG {
final static int MAX_CHAR = 256;
// function to print two strings
// generated from single string one
// with characters occurring once
// other with character occurring
// multiple of times
static void printDuo(String str) {
// initialize hashtable with zero
// entry
int countChar[] = new int[MAX_CHAR];
// perform hashing for input string
int n = str.length();
for (int i = 0; i < n; i++) {
countChar[str.charAt(i) - 'a']++;
}
// generate string (str1) consisting
// char occurring once and string
// (str2) consisting char occurring
// multiple times
String str1 = "", str2 = "";
for (int i = 0; i < MAX_CHAR; i++) {
if (countChar[i] > 1) {
str2 = str2 + (char) (i + 'a');
} else if (countChar[i] == 1) {
str1 = str1 + (char) (i + 'a');
}
}
// print both strings
System.out.print("String with characters occurring "
+ "once:\n");
System.out.print(str1 + "\n");
System.out.print("String with characters occurring "
+ "multiple times:\n");
System.out.print(str2 + "\n");
System.out.print("");
}
// driver program
public static void main(String[] args) {
String str = "lovetocode";
printDuo(str);
}
}
//this code contributed by 29AJayKumar
# Python3 program to print two strings
# made of character occurring once
# and multiple times
MAX_CHAR = 256
# function to print two strings
# generated from single string one
# with characters occurring once
# other with character occurring
# multiple of times
def printDuo(string):
# initialize hashtable with zero
# entry
countChar = [0 for i in range(MAX_CHAR)]
# perform hashing for input string
n = len(string)
for i in range(n):
countChar[ord(string[i]) - ord('a')] += 1
# generate string (str1) consisting
# char occurring once and string
# (str2) consisting char occurring
# multiple times
str1 = ""
str2 = ""
for i in range(MAX_CHAR):
if (countChar[i] > 1):
str2 = str2 + chr(i + ord('a'))
elif (countChar[i] == 1):
str1 = str1 + chr(i + ord('a'))
# print both strings
print("String with characters occurring once:",
"\n", str1)
print("String with characters occurring",
"multiple times:", "\n", str2)
# Driver Code
string = "lovetocode"
printDuo(string)
# This code is contributed by
# Mohit kumar 29
// C# program to print two strings
// made of character occurring once
// and multiple times
using System;
class GFG
{
static int MAX_CHAR = 256;
// function to print two strings
// generated from single string one
// with characters occurring once
// other with character occurring
// multiple of times
static void printDuo(string str)
{
// initialize hashtable with zero
// entry
int[] countChar = new int[MAX_CHAR];
// perform hashing for input string
int n = str.Length;
for (int i = 0; i < n; i++)
{
countChar[str[i] - 'a']++;
}
// generate string (str1) consisting
// char occurring once and string
// (str2) consisting char occurring
// multiple times
string str1 = "", str2 = "";
for (int i = 0; i < MAX_CHAR; i++)
{
if (countChar[i] > 1)
{
str2 = str2 + (char) (i + 'a');
}
else if (countChar[i] == 1)
{
str1 = str1 + (char) (i + 'a');
}
}
// print both strings
Console.Write("String with characters "+
"occurring once:\n");
Console.Write(str1 + "\n");
Console.Write("String with characters occurring " +
"multiple times:\n");
Console.Write(str2 + "\n");
Console.Write("");
}
// Driver Code
public static void Main()
{
string str = "lovetocode";
printDuo(str);
}
}
// This code is contributed by ita_c
<script>
// javascript program to print two strings
// made of character occurring once
// and multiple times
var MAX_CHAR = 256;
// function to print two strings
// generated from single string one
// with characters occurring once
// other with character occurring
// multiple of times
function printDuo(str)
{
// initialize hashtable with zero
// entry
var countChar = Array(MAX_CHAR).fill(0);
// perform hashing for input string
var n = str.length;
for (var i = 0; i < n; i++)
countChar[str[i].charCodeAt(0) - 'a'.charCodeAt(0)]++;
// generate string (str1) consisting
// char occurring once and string
// (str2) consisting char occurring
// multiple times
var str1 = "", str2 = "";
for (var i = 0; i < MAX_CHAR; i++) {
if (countChar[i] > 1)
str2 = str2 + String.fromCharCode(i + 'a'.charCodeAt(0));
else if (countChar[i] == 1)
str1 = str1 + String.fromCharCode(i + 'a'.charCodeAt(0));
}
// print both strings
document.write( "String with characters occurring "
+ "once:<br>");
document.write( str1 + "<br>");
document.write( "String with characters occurring "
+ "multiple times:<br>");
document.write( str2 + "<br>");
}
// driver program
var str = "lovetocode";
printDuo(str);
</script>
Output:
String with characters occurring once:
cdltv
String with characters occurring multiple times:
eo
Time complexity : O(n)
Auxiliary Space : O(1)
Approach : Using Sets
Follwo the below steps:
- Create a set to store characters occurring only once.
- Create another set to store characters occurring multiple times.
- Iterate through the input string and populate the sets accordingly.
- Convert sets to sorted strings and return them.
Below is the implementation of the above approach :
def separate_characters(input_str):
# Initialize sets to store characters occurring only once and multiple times
singles_set = set()
multiples_set = set()
# Iterate through the input string and populate the sets accordingly
char_count = {}
for char in input_str:
if char in char_count:
char_count[char] += 1
else:
char_count[char] = 1
for char, count in char_count.items():
if count == 1:
singles_set.add(char)
else:
multiples_set.add(char)
# Convert sets to sorted strings
singles = ''.join(sorted(singles_set))
multiples = ''.join(sorted(multiples_set))
return singles, multiples
# Example usage:
input_str1 = "geeksforgeeks"
singles1, multiples1 = separate_characters(input_str1)
print("String with characters occurring once:", singles1)
print("String with characters occurring multiple times:", multiples1)
input_str2 = "geekspractice"
singles2, multiples2 = separate_characters(input_str2)
print("String with characters occurring once:", singles2)
print("String with characters occurring multiple times:", multiples2)
Output
String with characters occurring once: for String with characters occurring multiple times: egks String with characters occurring once: agikprst String with characters occurring multiple times: ce
Time complexity: O(n + k * log(k)), where n is the length of the input string & k is the number of unique characters
Auxiliary space : O(c), where c is the number of unique characters.
