Find maximum product of K integers in a Binary Search Tree Last Updated : 23 Jul, 2025 Comments Improve Suggest changes Like Article Like Report Given a Binary search tree(BST) and a positive integer K, find the maximum product of k integers in the tree. Return the product as an integer. Examples: Input: K = 3, 10 / \ 3 12 / \ / \ 2 4 11 13Output: 1716Explanation: The maximum product of 3 integers can be obtained by selecting 12, 13, and 11. The product is 12*13*11 = 1716. Hence the output is 1716, which is the maximum product of 3 integers. Input: K = 2, 5 / \ 2 6 / \ \ 1 3 8Output: 48Explanation: The maximum product of 2 integers can be obtained by selecting 6 and 8. The product is 6*8 = 48. Hence the output is 48, which is the maximum product of 2 integers. Approach: This can be solved with the following idea: We can find the maximum product of K integers in the BST using the following approach: Traverse the BST and store all the nodes in a vector.Sort the vector in decreasing order of node values.Select the first k nodes from the sorted vector and compute their product.Return the product.Below are the steps to implement the above idea : Define a class for the BST node, which contains the node value and pointers to the left and right child nodes.Define a function to traverse the BST in any order (preorder, inorder, postorder) and store the nodes in a vector.Define a function to sort the vector in decreasing order of node values.Define a function to compute the product of K nodes.Define a function to find the maximum product of k nodes in the BST, which uses the above functions.Below is the code for the above approach: C++ // C++ Implementation #include <bits/stdc++.h> using namespace std; // Define a class for the BST node class Node { public: int value; Node* left; Node* right; Node(int val) { value = val; left = nullptr; right = nullptr; } }; // Function to traverse the BST in any // order and store the nodes in a vector void traverse(Node* root, vector<Node*>& nodes) { if (root == nullptr) { return; } traverse(root->left, nodes); nodes.push_back(root); traverse(root->right, nodes); } // Function to sort the vector in // decreasing order of node values bool cmp(Node* a, Node* b) { return a->value > b->value; } // Function to compute the product // of k nodes int product(vector<Node*>& nodes, int k) { int prod = 1; for (int i = 0; i < k; i++) { prod *= nodes[i]->value; } return prod; } // Function to find the maximum product // of k nodes in the BST int max_product(Node* root, int k) { // Create a vector to store the nodes vector<Node*> nodes; // Traverse the BST and store the // nodes in the vector traverse(root, nodes); // Sort the vector in decreasing // order of node values sort(nodes.begin(), nodes.end(), cmp); // If the number of nodes in the // BST is less than k, return 0 if (nodes.size() < k) { return 0; } // Compute the product of the first // k nodes in the sorted vector int prod = product(nodes, k); // Return the product return prod; } // Driver code int main() { // Create the BST /* 10 / \ 3 12 / \ / \ 2 4 11 13 */ Node* root1 = new Node(10); root1->left = new Node(3); root1->right = new Node(12); root1->left->left = new Node(2); root1->left->right = new Node(4); root1->right->left = new Node(11); root1->right->right = new Node(13); // Function call cout << max_product(root1, 3) << endl; return 0; } Java import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; import java.util.List; // Define a class for the BST node class Node { public int value; public Node left; public Node right; public Node(int val) { value = val; left = null; right = null; } } public class MaximumProductBST { // Function to traverse the BST in any // order and store the nodes in a list static void traverse(Node root, List<Node> nodes) { if (root == null) { return; } traverse(root.left, nodes); nodes.add(root); traverse(root.right, nodes); } // Function to sort the list in // decreasing order of node values static Comparator<Node> comparator = (a, b) -> b.value - a.value; // Function to compute the product // of k nodes static int product(List<Node> nodes, int k) { int prod = 1; for (int i = 0; i < k; i++) { prod *= nodes.get(i).value; } return prod; } // Function to find the maximum product // of k nodes in the BST static int maxProduct(Node root, int k) { // Create a list to store the nodes List<Node> nodes = new ArrayList<>(); // Traverse the BST and store the // nodes in the list traverse(root, nodes); // Sort the list in decreasing // order of node values Collections.sort(nodes, comparator); // If the number of nodes in the // BST is less than k, return 0 if (nodes.size() < k) { return 0; } // Compute the product of the first // k nodes in the sorted list int prod = product(nodes, k); // Return the product return prod; } // Driver code public static void main(String[] args) { // Create the BST /* 10 / \ 3 12 / \ / \ 2 4 11 13 */ Node root = new Node(10); root.left = new Node(3); root.right = new Node(12); root.left.left = new Node(2); root.left.right = new Node(4); root.right.left = new Node(11); root.right.right = new Node(13); // Function call System.out.println(maxProduct(root, 3)); } } // This code was contributed by codearcade Python # Python Implementation # Define a class for the BST node class Node: def __init__(self, val): self.value = val self.left = None self.right = None # Function to traverse the BST in any # order and store the nodes in a list def traverse(root, nodes): if root is None: return traverse(root.left, nodes) nodes.append(root) traverse(root.right, nodes) # Function to sort the list in # decreasing order of node values def cmp(a, b): return a.value > b.value # Function to compute the product # of k nodes def product(nodes, k): prod = 1 for i in range(k): prod *= nodes[i].value return prod # Function to find the maximum product # of k nodes in the BST def max_product(root, k): # Create a list to store the nodes nodes = [] # Traverse the BST and store the # nodes in the list traverse(root, nodes) # Sort the list in decreasing # order of node values nodes.sort(key=lambda x: x.value, reverse=True) # If the number of nodes in the # BST is less than k, return 0 if len(nodes) < k: return 0 # Compute the product of the first # k nodes in the sorted list prod = product(nodes, k) # Return the product return prod # Driver code if __name__ == "__main__": # Create the BST """ 10 / \ 3 12 / \ / \ 2 4 11 13 """ root1 = Node(10) root1.left = Node(3) root1.right = Node(12) root1.left.left = Node(2) root1.left.right = Node(4) root1.right.left = Node(11) root1.right.right = Node(13) # Function call print(max_product(root1, 3)) # This code is contributed by Susobhan Akhuli C# // C# Implementation using System; using System.Collections.Generic; using System.Linq; // Define a class for the BST node class Node { public int value; public Node left; public Node right; public Node(int val) { value = val; left = null; right = null; } } class Program { // Function to traverse the BST in any // order and store the nodes in a list static void Traverse(Node root, List<Node> nodes) { if (root == null) { return; } Traverse(root.left, nodes); nodes.Add(root); Traverse(root.right, nodes); } // Function to sort the list in // decreasing order of node values static int CompareNodes(Node a, Node b) { return b.value.CompareTo(a.value); } // Function to compute the product // of k nodes static int Product(List<Node> nodes, int k) { int prod = 1; for (int i = 0; i < k; i++) { prod *= nodes[i].value; } return prod; } // Function to find the maximum product // of k nodes in the BST static int MaxProduct(Node root, int k) { // Create a list to store the nodes List<Node> nodes = new List<Node>(); // Traverse the BST and store the // nodes in the list Traverse(root, nodes); // Sort the list in decreasing // order of node values nodes.Sort(CompareNodes); // If the number of nodes in the // BST is less than k, return 0 if (nodes.Count < k) { return 0; } // Compute the product of the first // k nodes in the sorted list int prod = Product(nodes, k); // Return the product return prod; } // Driver code static void Main() { // Create the BST /* 10 / \ 3 12 / \ / \ 2 4 11 13 */ Node root1 = new Node(10); root1.left = new Node(3); root1.right = new Node(12); root1.left.left = new Node(2); root1.left.right = new Node(4); root1.right.left = new Node(11); root1.right.right = new Node(13); // Function call Console.WriteLine(MaxProduct(root1, 3)); } } // This code is contributed by Susobhan Akhuli JavaScript <script> // JavaScript code for the above approach // Define a class for the BST node class Node { constructor(val) { this.value = val; this.left = null; this.right = null; } } // Function to traverse the BST in any order and store the nodes in a vector function traverse(root, nodes) { if (root === null) { return; } traverse(root.left, nodes); nodes.push(root); traverse(root.right, nodes); } // Function to sort the vector in decreasing order of node values function cmp(a, b) { return a.value > b.value ? -1 : 1; } // Function to compute the product of k nodes function product(nodes, k) { let prod = 1; for (let i = 0; i < k; i++) { prod *= nodes[i].value; } return prod; } // Function to find the maximum product of k nodes in the BST function maxProduct(root, k) { // Create a vector to store the nodes const nodes = []; // Traverse the BST and store the nodes in the vector traverse(root, nodes); // Sort the vector in decreasing order of node values nodes.sort(cmp); // If the number of nodes in the BST is less than k, return 0 if (nodes.length < k) { return 0; } // Compute the product of the first k nodes in the sorted vector const prod = product(nodes, k); // Return the product return prod; } // Create the BST /* 10 / \ 3 12 / \ / \ 2 4 11 13 */ const root = new Node(10); root.left = new Node(3); root.right = new Node(12); root.left.left = new Node(2); root.left.right = new Node(4); root.right.left = new Node(11); root.right.right = new Node(13); // Function call document.write(maxProduct(root, 3)); // This code is contributed by Susobhan Akhuli </script> Output1716Time Complexity: O(n*logn)Auxiliary Space: O(n) Comment More infoAdvertise with us Next Article Analysis of Algorithms P prajwalkandekar123 Follow Improve Article Tags : Binary Search Tree DSA BST Data Structures-Binary Search Trees Practice Tags : Binary Search Tree Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. 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