Sorted insert for circular linked list Last Updated : 17 May, 2025 Comments Improve Suggest changes Like Article Like Report Try it on GfG Practice Given a sorted circular linked list, your task is to insert a new node in this circular list so that it remains a sorted circular linked list.Examples:Input: head = 1 →2 →4, data = 2Output: 1 →2 →2 →4Explanation: We can add 2 after the second node.Input: head = 1 →4 →7 →9, data = 5Output: 1 →4 →5 →7 →9Explanation: We can add 5 after the second node.Approach:To inset the newNode in the circular Linked List follow below : Allocate memory for the newNode with the given data.If the list is empty, update the head to point to the newNode.If data is less than head, create a new node, link it after the last node, and return it as the new head.Else, traverse to find the position where input data is smaller or equal to head's data and insert newNode by adjusting the necessary pointers.Otherwise, insert the newNode in its appropriate position which is data <= head →data:Illustration: C++ // C++ program for sorted insert // in circular linked list #include <iostream> using namespace std; class Node { public: int data; Node *next; Node(int x) { data = x; next = nullptr; } }; // Function to insert a new node in the // list in a sorted way Node* sortedInsert(Node* head, int data) { // Create the new node with the given data Node* newNode = new Node(data); // If linked list is empty if (head == nullptr) { newNode->next = newNode; head = newNode; return head; } Node* curr = head; Node* nextToCurr = head->next; // Insert at the beginning if data is less // than or equal to head's data if (data <= head->data) { Node* lastNode = head; while (lastNode->next != head) { // Find the last node lastNode = lastNode->next; } // Set new node's next to head newNode->next = head; // Update last node's next to new node lastNode->next = newNode; // Update head to new node head = newNode; return head; } // Insert in the middle of the list while (curr->next != head) { if (curr->data < data && nextToCurr->data >= data) { // Set new node's next to current's next newNode->next = curr->next; curr->next = newNode; return head; } else { // Move to the next node curr = curr->next; nextToCurr = nextToCurr->next; } } // Insert at the end of the list newNode->next = head; curr->next = newNode; return head; } int main() { // Create circular linked list: 3->7->9->11->3 Node *head = new Node(3); head->next = new Node(7); head->next->next = new Node(9); head->next->next->next = new Node(11); head->next->next->next->next = head; head = sortedInsert(head, 8); Node *curr = head; if (head != nullptr) { do { cout << curr->data << " "; curr = curr->next; } while (curr != head); } cout << endl; return 0; } C // C program for sorted insert in // circular linked list #include <stdlib.h> struct Node { int data; struct Node *next; }; struct Node* createNode(int data) { struct Node* newNode = (struct Node*)malloc(sizeof(struct Node)); newNode->data = data; newNode->next = NULL; return newNode; } // Function to insert a new node // in the list in a sorted way struct Node* sortedInsert(struct Node* head, int data) { // Create the new node with the given data struct Node* newNode = createNode(data); // If linked list is empty if (head == NULL) { newNode->next = newNode; head = newNode; return head; } struct Node* curr = head; struct Node* nextToCurr = head->next; // Insert at the beginning if data is // less than or equal to head's data if (data <= head->data) { struct Node* lastNode = head; while (lastNode->next != head) { // Find the last node lastNode = lastNode->next; } // Set new node's next to head newNode->next = head; // Update last node's next to new node lastNode->next = newNode; // Update head to new node head = newNode; return head; } // Insert in the middle of the list while (curr->next != head) { if (curr->data < data && nextToCurr->data >= data) { // Set new node's next to current's next newNode->next = curr->next; curr->next = newNode; return head; } else { // Move to the next node curr = curr->next; nextToCurr = nextToCurr->next; } } // Insert at the end of the list newNode->next = head; curr->next = newNode; return head; } int main() { // Create circular linked list: 3->7->9->11->3 struct Node *head = createNode(3); head->next = createNode(7); head->next->next = createNode(9); head->next->next->next = createNode(11); head->next->next->next->next = head; head = sortedInsert(head, 8); struct Node *curr = head; if (head != NULL) { do { printf("%d ", curr->data); curr = curr->next; } while (curr != head); } printf("\n"); } Java // Java program for sorted insert // in circular linked list class Node { int data; Node next; Node(int x) { data = x; next = null; } } public class GfG { // Function to insert a new node in the // list in a sorted way static Node sortedInsert(Node head, int data) { // Create the new node with the given data Node newNode = new Node(data); // If linked list is empty if (head == null) { newNode.next = newNode; return newNode; } Node curr = head; Node nextToCurr = head.next; // Insert at the beginning if data is // less than or equal to head's data if (data <= head.data) { Node lastNode = head; while (lastNode.next != head) { // Find the last node lastNode = lastNode.next; } // Set new node's next to head newNode.next = head; // Update last node's next to new node lastNode.next = newNode; // Update head to new node return newNode; } // Insert in the middle of the list while (curr.next != head) { if (curr.data < data && nextToCurr.data >= data) { // Set new node's next to current's next newNode.next = curr.next; curr.next = newNode; return head; } else { // Move to the next node curr = curr.next; nextToCurr = nextToCurr.next; } } // Insert at the end of the list newNode.next = head; curr.next = newNode; return head; } public static void main(String[] args) { // Create circular linked list: 3->7->9->11->3 Node head = new Node(3); head.next = new Node(7); head.next.next = new Node(9); head.next.next.next = new Node(11); head.next.next.next.next = head; head = sortedInsert(head, 8); Node curr = head; if (head != null) { do { System.out.print(curr.data + " "); curr = curr.next; } while (curr != head); } System.out.println(); } } Python # python program for sorted insert in # circular linked list class Node: def __init__(self, data): self.data = data self.next = None # Function to insert a new node in # the list in a sorted way def sortedInsert(head, data): new_node = Node(data) # If linked list is empty if head is None: new_node.next = new_node return new_node curr = head next_to_curr = head.next # Insert at the beginning if data is less # than or equal to head's data if data <= head.data: last_node = head while last_node.next != head: last_node = last_node.next new_node.next = head last_node.next = new_node return new_node # Insert in the middle of the list while curr.next != head: if curr.data < data and next_to_curr.data >= data: new_node.next = curr.next curr.next = new_node return head else: curr = curr.next next_to_curr = next_to_curr.next # Insert at the end of the list new_node.next = head curr.next = new_node return head if __name__ == "__main__": # Create circular linked list: 3->7->9->11->3 head = Node(3) head.next = Node(7) head.next.next = Node(9) head.next.next.next = Node(11) head.next.next.next.next = head head = sortedInsert(head, 8) curr = head if head is not None: while True: print(curr.data, end=" ") curr = curr.next if curr == head: break print() C# // C# program for sorted insert // in circular linked list using System; class Node { public int data; public Node next; public Node(int x) { data = x; next = null; } } class GfG { // Function to insert a new node in the list in a sorted // way static Node SortedInsert(Node head, int data) { // Create the new node with the given data Node newNode = new Node(data); // If linked list is empty if (head == null) { newNode.next = newNode; return newNode; } Node curr = head; Node nextToCurr = head.next; // Insert at the beginning if data is // less than or equal to head's data if (data <= head.data) { Node lastNode = head; while (lastNode.next != head) { // Find the last node lastNode = lastNode.next; } // Set new node's next to head newNode.next = head; // Update last node's next to new node lastNode.next = newNode; // Update head to new node return newNode; } // Insert in the middle of the list while (curr.next != head) { if (curr.data < data && nextToCurr.data >= data) { // Set new node's next to current's next newNode.next = curr.next; curr.next = newNode; return head; } else { // Move to the next node curr = curr.next; nextToCurr = nextToCurr.next; } } // Insert at the end of the list newNode.next = head; curr.next = newNode; return head; } static void Main(string[] args) { // Create circular linked list: 3->7->9->11->3 Node head = new Node(3); head.next = new Node(7); head.next.next = new Node(9); head.next.next.next = new Node(11); head.next.next.next.next = head; head = SortedInsert(head, 8); Node curr = head; if (head != null) { do { Console.Write(curr.data + " "); curr = curr.next; } while (curr != head); } Console.WriteLine(); } } JavaScript // Javascript program for sorted insert in circular linked // list class Node { constructor(data) { this.data = data; this.next = null; } } // Function to insert a new node in // the list in a sorted way function sortedInsert(head, data) { let newNode = new Node(data); // If linked list is empty if (head === null) { newNode.next = newNode; return newNode; } let curr = head; let nextToCurr = head.next; // Insert at the beginning if data is // less than or equal to head's data if (data <= head.data) { let lastNode = head; while (lastNode.next !== head) { lastNode = lastNode.next; } newNode.next = head; lastNode.next = newNode; return newNode; } // Insert in the middle of the list while (curr.next !== head) { if (curr.data < data && nextToCurr.data >= data) { newNode.next = curr.next; curr.next = newNode; return head; } else { curr = curr.next; nextToCurr = nextToCurr.next; } } // Insert at the end of the list newNode.next = head; curr.next = newNode; return head; } // Create circular linked list: 3->7->9->11->3 let head = new Node(3); head.next = new Node(7); head.next.next = new Node(9); head.next.next.next = new Node(11); head.next.next.next.next = head; head = sortedInsert(head, 8); let output = ""; if (head !== null) { let curr = head; do { output += curr.data + " "; curr = curr.next; } while (curr !== head); } console.log(output.trim()); Output3 7 8 9 11 Time Complexity: O(n), where n is the number of nodes in the given circular linked list.Auxiliary Space: O(1) Sorted insert for circular linked list | DSA Problem Comment More infoAdvertise with us Next Article Analysis of Algorithms K kartik Follow Improve Article Tags : Linked List DSA Microsoft Amazon Zoho circular linked list +2 More Practice Tags : AmazonMicrosoftZohocircular linked listLinked List +1 More Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. 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