Check Contiguous 1s Sequence in Binary Linked List
Last Updated :
03 Dec, 2023
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Given a binary linked list and integer K, the task is to check whether the binary linked list contains a contiguous sequence of 1s of K length.
Examples:
Input: 0 -> 1 -> 1 -> 1 -> 0 -> 1 -> 1 -> 0 -> 1 -> 1, K = 3
Output: True
Explanation: In the given binary linked list, there is a contiguous sequence of three 1s between the second and fourth nodes (1 -> 1 -> 1). Therefore, the output is return True.Input: 0 -> 0 -> 1 -> 0 -> 1 -> 1 -> 1 -> 1 -> 0, K = 4
Output: True
Explanation: In the given binary linked list, there is a contiguous sequence of four 1s between the fifth and eight nodes (1 -> 1 -> 1). Therefore, the output is return True.Input: 0 -> 1 -> 0 -> 0-> 0-> 1, K = 5
Output: False
Explanation: In the given binary linked list, there is no contiguous sequence of five 1s so the output is False.
Approach: To solve the problem follow the below idea:
To solve this problem idea is to iterating through the linked list and keeping track of a counter variable count that increments whenever a 1 is encountered and resets to 0 whenever a 0 is encountered.
Here is steps of above approach:
- Initialize variable count to 0.
- Traverse the linked list using a while loop. Inside the loop, we check whether the current node contains a 1 or a 0.
- If the current node contains a 1, we increment a counter variable count by 1.
- If the value of count becomes equal to K, it means we have found a contiguous sequence of 1s of length K, so we set the Boolean flag variable flag to true and break out of the loop.
- the current node contains a 0, we reset the value of count to 0, since a contiguous sequence of 1s has been broken.
- Finally, we return the value of flag, which indicates whether we found a contiguous sequence of 1s of length K in the linked list.
Below is the implementation of the above approach:
// C++ code for the above approach:
#include <bits/stdc++.h>
using namespace std;
// Defining the structure of a node
// in a binary linked list
struct Node {
int data;
Node* next;
};
// Function to create a new node
Node* newNode(int data)
{
Node* node = new Node();
node->data = data;
node->next = NULL;
return node;
}
// Function to determine whether the
// given binary linked list contains a
// contiguous sequence of 1s of length K
bool containsContiguousSequence(Node* head, int K)
{
// Initialize a counter for consecutive 1s
int count = 0;
// Initialize a flag to indicate if
// the contiguous sequence is found
bool flag = false;
while (head) {
// Increment the count if the current
// node contains 1
if (head->data == 1) {
count++;
if (count == K) {
// Set the flag to true if the
// contiguous sequence of
// length K is found
flag = true;
// Exit the loop early since the
// sequence has been found
break;
}
}
// Reset the count if the current
// node contains 0
else {
count = 0;
}
// Move to the next node in the
// linked list
head = head->next;
}
// Return true if a contiguous sequence of
// 1s of length K was found, otherwise
// false
return flag;
}
// Driver code
int main()
{
// Creating a sample binary linked list
Node* head = newNode(0);
head->next = newNode(1);
head->next->next = newNode(1);
head->next->next->next = newNode(1);
head->next->next->next->next = newNode(0);
head->next->next->next->next->next = newNode(1);
head->next->next->next->next->next->next = newNode(1);
head->next->next->next->next->next->next->next
= newNode(0);
head->next->next->next->next->next->next->next->next
= newNode(1);
head->next->next->next->next->next->next->next->next
->next
= newNode(1);
bool result = containsContiguousSequence(head, 3);
// Printing the result
if (result) {
cout << "True";
}
else {
cout << "False";
}
return 0;
}
// C++ code for the above approach:using namespace std;// Defining the structure of a node// in a binary linked liststruct Node { int data; Node* next;};// Function to create a new nodeNode* newNode(int data){ Node* node = new Node(); node->data = data; node->next = NULL; return node;}// Function to determine whether the// given binary linked list contains a// contiguous sequence of 1s of length Kbool containsContiguousSequence(Node* head, int K){ // Initialize a counter for consecutive 1s int count = 0; // Initialize a flag to indicate if // the contiguous sequence is found bool flag = false; while (head) { // Increment the count if the current // node contains 1 if (head->data == 1) { count++; if (count == K) { // Set the flag to true if the // contiguous sequence of // length K is found flag = true; // Exit the loop early since the // sequence has been found break; } } // Reset the count if the current // node contains 0 else { count = 0; } // Move to the next node in the // linked list head = head->next; } // Return true if a contiguous sequence of // 1s of length K was found, otherwise // false return flag;}// Driver codeint main(){ // Creating a sample binary linked list Node* head = newNode(0); head->next = newNode(1); head->next->next = newNode(1); head->next->next->next = newNode(1); head->next->next->next->next = newNode(0); head->next->next->next->next->next = newNode(1); head->next->next->next->next->next->next = newNode(1); head->next->next->next->next->next->next->next = newNode(0); head->next->next->next->next->next->next->next->next = newNode(1); head->next->next->next->next->next->next->next->next ->next = newNode(1); bool result = containsContiguousSequence(head, 3); // Printing the result if (result) { cout << "True"; } else { cout << "False"; } return 0;}// Defining the structure of a node in a binary linked list
class Node {
int data;
Node next;
Node(int data) {
this.data = data;
this.next = null;
}
}
public class Main {
// Function to determine whether the given binary linked list contains
// a contiguous sequence of 1s of length K
public static boolean containsContiguousSequence(Node head, int K) {
// Initialize a counter for consecutive 1s
int count = 0;
// Initialize a flag to indicate if the contiguous sequence is found
boolean flag = false;
while (head != null) {
// Increment the count if the current node contains 1
if (head.data == 1) {
count++;
if (count == K) {
// Set the flag to true if the contiguous sequence of length K is found
flag = true;
// Exit the loop early since the sequence has been found
break;
}
} else {
// Reset the count if the current node contains 0
count = 0;
}
// Move to the next node in the linked list
head = head.next;
}
// Return true if a contiguous sequence of 1s of length K was found, otherwise false
return flag;
}
public static void main(String[] args) {
// Creating a sample binary linked list
Node head = new Node(0);
head.next = new Node(1);
head.next.next = new Node(1);
head.next.next.next = new Node(1);
head.next.next.next.next = new Node(0);
head.next.next.next.next.next = new Node(1);
head.next.next.next.next.next.next = new Node(1);
head.next.next.next.next.next.next.next = new Node(0);
head.next.next.next.next.next.next.next.next = new Node(1);
head.next.next.next.next.next.next.next.next.next = new Node(1);
boolean result = containsContiguousSequence(head, 3);
// Printing the result
if (result) {
System.out.println("True");
} else {
System.out.println("False");
}
}
}
//Contributed by Aditi Tyagi
class Node:
def __init__(self, data):
self.data = data
self.next = None
def contains_contiguous_sequence(head, K):
# Initialize a counter for consecutive 1s
count = 0
# Initialize a flag to indicate if the contiguous sequence is found
flag = False
while head:
# Increment the count if the current node contains 1
if head.data == 1:
count += 1
if count == K:
# Set the flag to true if the contiguous sequence of
# length K is found
flag = True
# Exit the loop early since the sequence has been found
break
else:
# Reset the count if the current node contains 0
count = 0
# Move to the next node in the linked list
head = head.next
# Return True if a contiguous sequence of 1s of length K was found, otherwise False
return flag
# Driver code
if __name__ == "__main__":
# Creating a sample binary linked list
head = Node(0)
head.next = Node(1)
head.next.next = Node(1)
head.next.next.next = Node(1)
head.next.next.next.next = Node(0)
head.next.next.next.next.next = Node(1)
head.next.next.next.next.next.next = Node(1)
head.next.next.next.next.next.next.next = Node(0)
head.next.next.next.next.next.next.next.next = Node(1)
head.next.next.next.next.next.next.next.next.next = Node(1)
result = contains_contiguous_sequence(head, 3)
# Printing the result
if result:
print("True")
else:
print("False")
// C# Code
using System;
// Defining the structure of a node in a binary linked list
public class Node
{
public int Data { get; set; }
public Node Next { get; set; }
public Node(int data)
{
Data = data;
Next = null;
}
}
public class GFG
{
// Function to determine whether the given binary linked list contains
// a contiguous sequence of 1s of length K
public static bool ContainsContiguousSequence(Node head, int K)
{
// Initialize a counter for consecutive 1s
int count = 0;
// Initialize a flag to indicate if the contiguous sequence is found
bool flag = false;
while (head != null)
{
// Increment the count if the current node contains 1
if (head.Data == 1)
{
count++;
if (count == K)
{
// Set the flag to true if the contiguous sequence of length K is found
flag = true;
// Exit the loop early since the sequence has been found
break;
}
}
else
{
// Reset the count if the current node contains 0
count = 0;
}
// Move to the next node in the linked list
head = head.Next;
}
// Return true if a contiguous sequence of 1s of length K was found, otherwise false
return flag;
}
public static void Main()
{
// Creating a sample binary linked list
Node head = new Node(0);
head.Next = new Node(1);
head.Next.Next = new Node(1);
head.Next.Next.Next = new Node(1);
head.Next.Next.Next.Next = new Node(0);
head.Next.Next.Next.Next.Next = new Node(1);
head.Next.Next.Next.Next.Next.Next = new Node(1);
head.Next.Next.Next.Next.Next.Next.Next = new Node(0);
head.Next.Next.Next.Next.Next.Next.Next.Next = new Node(1);
head.Next.Next.Next.Next.Next.Next.Next.Next.Next = new Node(1);
bool result = ContainsContiguousSequence(head, 3);
// Printing the result
if (result)
{
Console.WriteLine("True");
}
else
{
Console.WriteLine("False");
}
}
}
// This code is contributed by guptapratik
// Definition of a node in a binary linked list
class Node {
constructor(data) {
this.data = data;
this.next = null;
}
}
// Function to determine whether the given binary linked list contains a contiguous sequence of 1s of length K
function containsContiguousSequence(head, K) {
// Initialize a counter for consecutive 1s
let count = 0;
// Initialize a flag to indicate if the contiguous sequence is found
let flag = false;
while (head) {
// Increment the count if the current node contains 1
if (head.data === 1) {
count++;
if (count === K) {
// Set the flag to true if the contiguous sequence of length K is found
flag = true;
// Exit the loop early since the sequence has been found
break;
}
} else {
// Reset the count if the current node contains 0
count = 0;
}
// Move to the next node in the linked list
head = head.next;
}
// Return true if a contiguous sequence of 1s of length K was found, otherwise false
return flag;
}
// Main function
function main() {
// Creating a sample binary linked list
const head = new Node(0);
head.next = new Node(1);
head.next.next = new Node(1);
head.next.next.next = new Node(1);
head.next.next.next.next = new Node(0);
head.next.next.next.next.next = new Node(1);
head.next.next.next.next.next.next = new Node(1);
head.next.next.next.next.next.next.next = new Node(0);
head.next.next.next.next.next.next.next.next = new Node(1);
head.next.next.next.next.next.next.next.next.next = new Node(1);
const result = containsContiguousSequence(head, 3);
// Printing the result
console.log(result ? "True" : "False");
}
// Call the main function
main();
Output
True
Time Complexity: O(n), where n is the number of nodes in the linked list.
Auxiliary Space: O(1), since we are only using a constant amount of extra space to store the counter variable count and the Boolean flag variable flag.
