Background
Bitonic Sort is a classic parallel algorithm for sorting.
- The number of comparisons done by Bitonic sort is more than popular sorting algorithms like Merge Sort [ does O(log N) comparisons], but Bitonic sort is better for parallel implementation because we always compare elements in a predefined sequence and the sequence of comparison doesn't depend on data. Therefore it is suitable for implementation in hardware and parallel processor array.
- Bitonic Sort can only be done if the number of elements to sort is 2^n. The procedure of bitonic sequence fails if the number of elements is not in the aforementioned quantity precisely.
To understand Bitonic Sort, we must first understand what is Bitonic Sequence and how to make a given sequence Bitonic.
Bitonic Sequence
A sequence is called Bitonic if it is first increasing, then decreasing. In other words, an array arr[0..n-i] is Bitonic if there exists an index I, where 0<=i<=n-1 such that
x0 <= x1 …..<= xi
and
xi >= xi+1….. >= xn-1
- A sequence, sorted in increasing order is considered Bitonic with the decreasing part as empty. Similarly, decreasing order sequence is considered Bitonic with the increasing part as empty.
- A rotation of the Bitonic Sequence is also bitonic.
How to form a Bitonic Sequence from a random input?
We start by forming 4-element bitonic sequences the from consecutive 2-element sequences. Consider 4-element in sequence x0, x1, x2, x3. We sort x0 and x1 in ascending order and x2 and x3 in descending order. We then concatenate the two pairs to form a 4 element bitonic sequence.
Next, we take two 4-element bitonic sequences, sorting one in ascending order, the other in descending order (using the Bitonic Sort which we will discuss below), and so on, until we obtain the bitonic sequence.
Example:
Convert the following sequence to a bitonic sequence: 3, 7, 4, 8, 6, 2, 1, 5
Step 1: Consider each 2-consecutive element as a bitonic sequence and apply bitonic sort on each 2- pair element. In the next step, take 4-element bitonic sequences and so on.
Note: x0 and x1 are sorted in ascending order and x2 and x3 in descending order and so on
Step 2: Two 4 element bitonic sequences: A(3,7,8,4) and B(2,6,5,1) with comparator length as 2
After this step, we'll get a Bitonic sequence of length 8.
3, 4, 7, 8, 6, 5, 2, 1
Bitonic Sorting
Bitonic Sort Algorithm:
- Bitonic sequence is created.
- Comparison between the corresponding element of the bitonic sequence.
- Swapping the second element of the sequence.
- Swapping the adjacent element.
It mainly involves two steps.
- Form a bitonic sequence (discussed above in detail). After this step we reach the fourth stage in the below diagram, i.e., the array becomes {3, 4, 7, 8, 6, 5, 2, 1}
- Creating one sorted sequence from a bitonic sequence: After the r first state ep, the first half is sorted in increasing order and the second half in decreasing order.
We compare the first element of the first half with the first element of the second half, then the second element of the first half with the second element of the second, and so on. We exchange elements if an element of the first half is larger than second half.
After her above compare and exchange steps, we get two bitonic sequences in the array. See the fifth stage below the diagram. In the fifth stage, we have {3, 4, 2, 1, 6, 5, 7, 8}. If we take a closer look at the elements, we can notice that there are two bitonic sequences of length n/2 such that all elements in the first bitonic sequence {3, 4, 2, 1} are smaller than all elements of the second bitonic sequence {6, 5, 7, 8}.
We repeat the same process within two bitonic sequences and we get four bitonic sequences of length n/4 such that all elements of the leftmost bitonic sequence are smaller and all elements of the rightmost. See sixth stage in below diagram, arrays is {2, 1, 3, 4, 6, 5, 7, 8}.
If we repeat this process one more time we get 8 bitonic sequences of size n/8 which is 1. Since all these bitonic sequences are sorted and every bitonic sequence has one element, we get the sorted array.
Below are implementations of Bitonic Sort.
C++
/* C++ Program for Bitonic Sort. Note that this program
works only when size of input is a power of 2. */
#include<bits/stdc++.h>
using namespace std;
/*The parameter dir indicates the sorting direction, ASCENDING
or DESCENDING; if (a[i] > a[j]) agrees with the direction,
then a[i] and a[j] are interchanged.*/
void compAndSwap(int a[], int i, int j, int dir)
{
if (dir==(a[i]>a[j]))
swap(a[i],a[j]);
}
/*It recursively sorts a bitonic sequence in ascending order,
if dir = 1, and in descending order otherwise (means dir=0).
The sequence to be sorted starts at index position low,
the parameter cnt is the number of elements to be sorted.*/
void bitonicMerge(int a[], int low, int cnt, int dir)
{
if (cnt>1)
{
int k = cnt/2;
for (int i=low; i<low+k; i++)
compAndSwap(a, i, i+k, dir);
bitonicMerge(a, low, k, dir);
bitonicMerge(a, low+k, k, dir);
}
}
/* This function first produces a bitonic sequence by recursively
sorting its two halves in opposite sorting orders, and then
calls bitonicMerge to make them in the same order */
void bitonicSort(int a[],int low, int cnt, int dir)
{
if (cnt>1)
{
int k = cnt/2;
// sort in ascending order since dir here is 1
bitonicSort(a, low, k, 1);
// sort in descending order since dir here is 0
bitonicSort(a, low+k, k, 0);
// Will merge whole sequence in ascending order
// since dir=1.
bitonicMerge(a,low, cnt, dir);
}
}
/* Caller of bitonicSort for sorting the entire array of
length N in ASCENDING order */
void sort(int a[], int N, int up)
{
bitonicSort(a,0, N, up);
}
// Driver code
int main()
{
int a[]= {3, 7, 4, 8, 6, 2, 1, 5};
int N = sizeof(a)/sizeof(a[0]);
int up = 1; // means sort in ascending order
sort(a, N, up);
printf("Sorted array: \n");
for (int i=0; i<N; i++)
printf("%d ", a[i]);
return 0;
}
/* Java program for Bitonic Sort. Note that this program
works only when size of input is a power of 2. */
public class BitonicSort
{
/* The parameter dir indicates the sorting direction,
ASCENDING or DESCENDING; if (a[i] > a[j]) agrees
with the direction, then a[i] and a[j] are
interchanged. */
void compAndSwap(int a[], int i, int j, int dir)
{
if ( (a[i] > a[j] && dir == 1) ||
(a[i] < a[j] && dir == 0))
{
// Swapping elements
int temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
/* It recursively sorts a bitonic sequence in ascending
order, if dir = 1, and in descending order otherwise
(means dir=0). The sequence to be sorted starts at
index position low, the parameter cnt is the number
of elements to be sorted.*/
void bitonicMerge(int a[], int low, int cnt, int dir)
{
if (cnt>1)
{
int k = cnt/2;
for (int i=low; i<low+k; i++)
compAndSwap(a,i, i+k, dir);
bitonicMerge(a,low, k, dir);
bitonicMerge(a,low+k, k, dir);
}
}
/* This function first produces a bitonic sequence by
recursively sorting its two halves in opposite sorting
orders, and then calls bitonicMerge to make them in
the same order */
void bitonicSort(int a[], int low, int cnt, int dir)
{
if (cnt>1)
{
int k = cnt/2;
// sort in ascending order since dir here is 1
bitonicSort(a, low, k, 1);
// sort in descending order since dir here is 0
bitonicSort(a,low+k, k, 0);
// Will merge whole sequence in ascending order
// since dir=1.
bitonicMerge(a, low, cnt, dir);
}
}
/*Caller of bitonicSort for sorting the entire array
of length N in ASCENDING order */
void sort(int a[], int N, int up)
{
bitonicSort(a, 0, N, up);
}
/* A utility function to print array of size n */
static void printArray(int arr[])
{
int n = arr.length;
for (int i=0; i<n; ++i)
System.out.print(arr[i] + " ");
System.out.println();
}
// Driver method
public static void main(String args[])
{
int a[] = {3, 7, 4, 8, 6, 2, 1, 5};
int up = 1;
BitonicSort ob = new BitonicSort();
ob.sort(a, a.length,up);
System.out.println("\nSorted array");
printArray(a);
}
}
# Python program for Bitonic Sort. Note that this program
# works only when size of input is a power of 2.
# The parameter dir indicates the sorting direction, ASCENDING
# or DESCENDING; if (a[i] > a[j]) agrees with the direction,
# then a[i] and a[j] are interchanged.*/
def compAndSwap(a, i, j, dire):
if (dire==1 and a[i] > a[j]) or (dire==0 and a[i] < a[j]):
a[i],a[j] = a[j],a[i]
# It recursively sorts a bitonic sequence in ascending order,
# if dir = 1, and in descending order otherwise (means dir=0).
# The sequence to be sorted starts at index position low,
# the parameter cnt is the number of elements to be sorted.
def bitonicMerge(a, low, cnt, dire):
if cnt > 1:
k = cnt//2
for i in range(low , low+k):
compAndSwap(a, i, i+k, dire)
bitonicMerge(a, low, k, dire)
bitonicMerge(a, low+k, k, dire)
# This function first produces a bitonic sequence by recursively
# sorting its two halves in opposite sorting orders, and then
# calls bitonicMerge to make them in the same order
def bitonicSort(a, low, cnt,dire):
if cnt > 1:
k = cnt//2
bitonicSort(a, low, k, 1)
bitonicSort(a, low+k, k, 0)
bitonicMerge(a, low, cnt, dire)
# Caller of bitonicSort for sorting the entire array of length N
# in ASCENDING order
def sort(a,N, up):
bitonicSort(a,0, N, up)
# Driver code to test above
a = [3, 7, 4, 8, 6, 2, 1, 5]
n = len(a)
up = 1
sort(a, n, up)
print ("\n\nSorted array is")
for i in range(n):
print("%d" %a[i],end=" ")
/* C# Program for Bitonic Sort. Note that this program
works only when size of input is a power of 2. */
using System;
/*The parameter dir indicates the sorting direction, ASCENDING
or DESCENDING; if (a[i] > a[j]) agrees with the direction,
then a[i] and a[j] are interchanged.*/
class GFG
{
/* To swap values */
static void Swap<T>(ref T lhs, ref T rhs)
{
T temp;
temp = lhs;
lhs = rhs;
rhs = temp;
}
public static void compAndSwap(int[] a, int i, int j, int dir)
{
int k;
if((a[i]>a[j]))
k=1;
else
k=0;
if (dir==k)
Swap(ref a[i],ref a[j]);
}
/*It recursively sorts a bitonic sequence in ascending order,
if dir = 1, and in descending order otherwise (means dir=0).
The sequence to be sorted starts at index position low,
the parameter cnt is the number of elements to be sorted.*/
public static void bitonicMerge(int[] a, int low, int cnt, int dir)
{
if (cnt>1)
{
int k = cnt/2;
for (int i=low; i<low+k; i++)
compAndSwap(a, i, i+k, dir);
bitonicMerge(a, low, k, dir);
bitonicMerge(a, low+k, k, dir);
}
}
/* This function first produces a bitonic sequence by recursively
sorting its two halves in opposite sorting orders, and then
calls bitonicMerge to make them in the same order */
public static void bitonicSort(int[] a,int low, int cnt, int dir)
{
if (cnt>1)
{
int k = cnt/2;
// sort in ascending order since dir here is 1
bitonicSort(a, low, k, 1);
// sort in descending order since dir here is 0
bitonicSort(a, low+k, k, 0);
// Will merge whole sequence in ascending order
// since dir=1.
bitonicMerge(a,low, cnt, dir);
}
}
/* Caller of bitonicSort for sorting the entire array of
length N in ASCENDING order */
public static void sort(int[] a, int N, int up)
{
bitonicSort(a,0, N, up);
}
// Driver code
static void Main()
{
int[] a= {3, 7, 4, 8, 6, 2, 1, 5};
int N = a.Length;
int up = 1; // means sort in ascending order
sort(a, N, up);
Console.Write("Sorted array: \n");
for (int i=0; i<N; i++)
Console.Write(a[i] + " ");
}
//This code is contributed by DrRoot_
}
<script>
/* JavaScript program for Bitonic Sort.
Note that this program
works only when size of input is a power of 2. */
/* The parameter dir indicates the sorting direction,
ASCENDING or DESCENDING; if (a[i] > a[j]) agrees
with the direction, then a[i] and a[j] are
interchanged. */
function compAndSwap(a, i, j, dir) {
if ((a[i] > a[j] && dir === 1) ||
(a[i] < a[j] && dir === 0))
{
// Swapping elements
var temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
/* It recursively sorts a bitonic sequence in ascending
order, if dir = 1, and in descending order otherwise
(means dir=0). The sequence to be sorted starts at
index position low, the parameter cnt is the number
of elements to be sorted.*/
function bitonicMerge(a, low, cnt, dir) {
if (cnt > 1) {
var k = parseInt(cnt / 2);
for (var i = low; i < low + k; i++)
compAndSwap(a, i, i + k, dir);
bitonicMerge(a, low, k, dir);
bitonicMerge(a, low + k, k, dir);
}
}
/* This function first produces a bitonic sequence by
recursively sorting its two halves in opposite sorting
orders, and then calls bitonicMerge to make them in
the same order */
function bitonicSort(a, low, cnt, dir) {
if (cnt > 1) {
var k = parseInt(cnt / 2);
// sort in ascending order since dir here is 1
bitonicSort(a, low, k, 1);
// sort in descending order since dir here is 0
bitonicSort(a, low + k, k, 0);
// Will merge whole sequence in ascending order
// since dir=1.
bitonicMerge(a, low, cnt, dir);
}
}
/*Caller of bitonicSort for sorting the entire array
of length N in ASCENDING order */
function sort(a, N, up) {
bitonicSort(a, 0, N, up);
}
/* A utility function to print array of size n */
function printArray(arr) {
var n = arr.length;
for (var i = 0; i < n; ++i)
document.write(arr[i] + " ");
document.write("<br>");
}
// Driver method
var a = [3, 7, 4, 8, 6, 2, 1, 5];
var up = 1;
sort(a, a.length, up);
document.write("Sorted array: <br>");
printArray(a);
</script>
Output:
Sorted array:
1 2 3 4 5 6 7 8
Analysis of Bitonic Sort
To form a sorted sequence of length n from two sorted sequences of length n/2, log(n) comparisons are required.
For example: log(8) = 3 when sequence size. Therefore, The number of comparisons T(n) of the entire sorting is given by:
T(n) = log(n) + T(n/2)
The solution of this recurrence equation is
T(n) = log(n) + log(n)-1 + log(n)-2 + ... + 1 = log(n) · (log(n)+1) / 2
As each stage of the sorting network consists of n/2 comparators. Therefore total O(n log2n) comparators.
Time complexity:
- Best Case: O(log2n)
- Average Case: O(log2n)
- Worst Case: O(log2n)
Space Complexity: O(n.log2n)
Stable: Yes
Important Points:
- It is a comparison-based sorting technique
- Elements are sorted depending on the bitonic sequence
- Easily Implemented in parallel computing
- More efficient than quicksort
- The number of comparisons is more than other algorithms
- A sequence with elements in increasing and decreasing order is a bitonic sequence.
- Memory is well handled by the process.
- Best suited for parallel processor array.
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