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C++ Program For Printing Reverse Of A Linked List Without Actually Reversing

Last Updated : 08 Jul, 2022
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Given a linked list, print reverse of it using a recursive function. For example, if the given linked list is 1->2->3->4, then output should be 4->3->2->1.
Note that the question is only about printing the reverse. To reverse the list itself see this 
Difficulty Level: Rookie 
 

reverse-a-link-list

Algorithm: 

printReverse(head)
  1. call print reverse for head->next
  2. print head->data

Implementation: 

C++
// C++ program to print reverse of a linked list 
#include <bits/stdc++.h>
using namespace std;

// Link list node 
class Node 
{ 
    public:
    int data; 
    Node* next; 
}; 

// Function to reverse the 
// linked list 
void printReverse(Node* head) 
{ 
    // Base case 
    if (head == NULL) 
    return; 

    // Print the list after head node 
    printReverse(head->next); 

    // After everything else is printed, 
    // print head 
    cout << head->data << " "; 
} 

// UTILITY FUNCTIONS
/* Push a node to linked list. 
   Note that this function 
   changes the head */
void push(Node** head_ref, 
          char new_data) 
{ 
    // Allocate node 
    Node* new_node = new Node();

    // Put in the data 
    new_node->data = new_data; 

    // Link the old list off the 
    // new node 
    new_node->next = (*head_ref); 

    // Move the head to point to 
    // the new node 
    (*head_ref) = new_node; 
} 

// Driver code
int main() 
{ 
    // Let us create linked list 
    // 1->2->3->4 
    Node* head = NULL; 
    push(&head, 4); 
    push(&head, 3); 
    push(&head, 2); 
    push(&head, 1); 
    
    printReverse(head); 
    return 0; 
} 
// This code is contributed by rathbhupendra

Output: 

4 3 2 1

Time Complexity: O(n)

Space Complexity: O(n) for call stack since using recursion

Please refer complete article on Print reverse of a Linked List without actually reversing for more details!
 


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