C++ Program For Finding The Length Of Loop In Linked List Last Updated : 05 Apr, 2022 Summarize Comments Improve Suggest changes Share Like Article Like Report Write a function detectAndCountLoop() that checks whether a given Linked List contains loop and if loop is present then returns count of nodes in loop. For example, the loop is present in below-linked list and length of the loop is 4. If the loop is not present, then the function should return 0. Recommended: Please try your approach on PRACTICE, before moving on to the solution. Approach: It is known that Floyd’s Cycle detection algorithm terminates when fast and slow pointers meet at a common point. It is also known that this common point is one of the loop nodes. Store the address of this common point in a pointer variable say (ptr). Then initialize a counter with 1 and start from the common point and keeps on visiting the next node and increasing the counter till the common pointer is reached again. At that point, the value of the counter will be equal to the length of the loop.Algorithm: Find the common point in the loop by using the Floyd’s Cycle detection algorithmStore the pointer in a temporary variable and keep a count = 0Traverse the linked list until the same node is reached again and increase the count while moving to next node.Print the count as length of loop C++ // C++ program to count number of nodes // in loop in a linked list if loop is // present #include<bits/stdc++.h> using namespace std; // Link list node struct Node { int data; struct Node* next; }; // Returns count of nodes present // in loop. int countNodes(struct Node *n) { int res = 1; struct Node *temp = n; while (temp->next != n) { res++; temp = temp->next; } return res; } /* This function detects and counts loop nodes in the list. If loop is not there in then returns 0 */ int countNodesinLoop(struct Node *list) { struct Node *slow_p = list, *fast_p = list; while (slow_p && fast_p && fast_p->next) { slow_p = slow_p->next; fast_p = fast_p->next->next; /* If slow_p and fast_p meet at some point then there is a loop */ if (slow_p == fast_p) return countNodes(slow_p); } /* Return 0 to indicate that there is no loop*/ return 0; } struct Node *newNode(int key) { struct Node *temp = (struct Node*)malloc(sizeof(struct Node)); temp->data = key; temp->next = NULL; return temp; } // Driver Code int main() { struct Node *head = newNode(1); head->next = newNode(2); head->next->next = newNode(3); head->next->next->next = newNode(4); head->next->next->next->next = newNode(5); // Create a loop for testing head->next->next->next->next->next = head->next; cout << countNodesinLoop(head) << endl; return 0; } // This code is contributed by SHUBHAMSINGH10 Output: 4 Complexity Analysis: Time complexity:O(n). Only one traversal of the linked list is needed.Auxiliary Space:O(1). As no extra space is required. Please refer complete article on Find length of loop in linked list for more details! Comment More infoAdvertise with us K kartik Follow Improve Article Tags : C++ Linked Lists Adobe Qualcomm Practice Tags : AdobeQualcommCPP Similar Reads C++ Programming Language C++ is a computer programming language developed by Bjarne Stroustrup as an extension of the C language. It is known for is fast speed, low level memory management and is often taught as first programming language. It provides:Hands-on application of different programming concepts.Similar syntax to 5 min read Quick Sort QuickSort is a sorting algorithm based on the Divide and Conquer that picks an element as a pivot and partitions the given array around the picked pivot by placing the pivot in its correct position in the sorted array. 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