Check if a graph is Strongly, Unilaterally or Weakly connected Last Updated : 15 Jul, 2025 Comments Improve Suggest changes Like Article Like Report Given an unweighted directed graph G as a path matrix, the task is to find out if the graph is Strongly Connected or Unilaterally Connected or Weakly Connected. Strongly Connected: A graph is said to be strongly connected if every pair of vertices(u, v) in the graph contains a path between each other. In an unweighted directed graph G, every pair of vertices u and v should have a path in each direction between them i.e., bidirectional path. The elements of the path matrix of such a graph will contain all 1's.Unilaterally Connected: A graph is said to be unilaterally connected if it contains a directed path from u to v OR a directed path from v to u for every pair of vertices u, v. Hence, at least for any pair of vertices, one vertex should be reachable form the other. Such a path matrix would rather have upper triangle elements containing 1's OR lower triangle elements containing 1's.Weakly Connected: A directed graph is weakly connected if there is a path between every two vertices in the underlying undirected graph (i.e, the graph formed when the direction of the edges are removed). Examples: Input: Below is the given graph with path matrix: Output: Strongly Connected Graph Input: Below is the given graph with path matrix: Output: Unilaterally Connected GraphInput: Below is the given graph with path matrix: Output: Weakly Connected Graph Approach: For the graph to be Strongly Connected, traverse the given path matrix using the approach discussed in this article check whether all the values in the cell are 1 or not. If yes then print "Strongly Connected Graph" else check for the other two graphs.For the graph to be Unilaterally Connected, traverse the given path matrix using the approach discussed in this article and check the following: If all the values above the main diagonal are 1s and all the values other than that are 0s.If all the values below the main diagonal are 1s and all the values other than that are 0s.If one of the above two conditions satisfies then the given graph is Unilaterally Connected else the graph is Weakly Connected Graph. Below is the implementation of the above approach: C++ // C++ implementation of the approach #include <bits/stdc++.h> using namespace std; #define V 3 // Function to find the characteristic // of the given graph int checkConnected(int graph[][V], int n) { // Check whether the graph is // strongly connected or not bool strongly = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If all the elements are // not equal then the graph // is not strongly connected if (graph[i][j] != graph[j][i]) { strongly = false; break; } } // Break out of the loop if false if (!strongly) { break; } } // If true then print strongly // connected and return if (strongly) { cout << "Strongly Connected"; return 0; } // Check whether the graph is // Unilaterally connected by // checking Upper Triangle element bool uppertri = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If uppertriangle elements // are 0 then break out of the // loop and check the elements // of lowertriangle matrix if (i > j && graph[i][j] == 0) { uppertri = false; break; } } // Break out of the loop if false if (!uppertri) { break; } } // If true then print unilaterally // connected and return if (uppertri) { cout << "Unilaterally Connected"; return 0; } // Check lowertraingle elements bool lowertri = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If lowertraingle elements // are 0 then break cause // 1's are expected if (i < j && graph[i][j] == 0) { lowertri = false; break; } } // Break out of the loop if false if (!lowertri) { break; } } // If true then print unilaterally // connected and return if (lowertri) { cout << "Unilaterally Connected"; return 0; } // If elements are in random order // unsynchronized then print weakly // connected and return else { cout << "Weakly Connected"; } return 0; } // Driver Code int main() { // Number of nodes int n = 3; // Given Path Matrix int graph[V][V] = { { 0, 1, 1 }, { 0, 0, 1 }, { 0, 0, 0 }, }; // Function Call checkConnected(graph, n); return 0; } Java // Java implementation of the above approach import java.util.*; class GFG { static final int V = 3; // Function to find the characteristic // of the given graph static int checkConnected(int graph[][], int n) { // Check whether the graph is // strongly connected or not boolean strongly = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If all the elements are // not equal then the graph // is not strongly connected if (graph[i][j] != graph[j][i]) { strongly = false; break; } } // Break out of the loop if false if (!strongly) { break; } } // If true then print strongly // connected and return if (strongly) { System.out.print("Strongly Connected"); return 0; } // Check whether the graph is // Unilaterally connected by // checking Upper Triangle element boolean uppertri = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If uppertriangle elements // are 0 then break out of the // loop and check the elements // of lowertriangle matrix if (i > j && graph[i][j] == 0) { uppertri = false; break; } } // Break out of the loop if false if (!uppertri) { break; } } // If true then print unilaterally // connected and return if (uppertri) { System.out.print("Unilaterally Connected"); return 0; } // Check lowertraingle elements boolean lowertri = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If lowertraingle elements // are 0 then break cause // 1's are expected if (i < j && graph[i][j] == 0) { lowertri = false; break; } } // Break out of the loop if false if (!lowertri) { break; } } // If true then print unilaterally // connected and return if (lowertri) { System.out.print("Unilaterally Connected"); return 0; } // If elements are in random order // unsynchronized then print weakly // connected and return else { System.out.print("Weakly Connected"); } return 0; } // Driver Code public static void main(String[] args) { // Number of nodes int n = 3; // Given Path Matrix int graph[][] = { { 0, 1, 1 }, { 0, 0, 1 }, { 0, 0, 0 } }; // Function call checkConnected(graph, n); } } // This code is contributed by 29AjayKumar Python3 # Python3 implementation of # the above approach V = 3 # Function to find the # characteristic of the # given graph def checkConnected(graph, n): # Check whether the graph is # strongly connected or not strongly = True # Traverse the path # matrix for i in range(n): for j in range(n): # If all the elements are # not equal then the graph # is not strongly connected if (graph[i][j] != graph[j][i]): strongly = False break # Break out of the # loop if false if not strongly: break # If true then print # strongly connected and return if (strongly): print("Strongly Connected") exit() # Check whether the graph is # Unilaterally connected by # checking Upper Triangle element uppertri = True # Traverse the path matrix for i in range(n): for j in range(n): # If uppertriangle elements # are 0 then break out of the # loop and check the elements # of lowertriangle matrix if (i > j and graph[i][j] == 0): uppertri = False break # Break out of the # loop if false if not uppertri: break # If true then print # unilaterally connected # and return if uppertri: print("Unilaterally Connected") exit() # Check lowertraingle elements lowertri = True # Traverse the path matrix for i in range(n): for j in range(n): # If lowertraingle elements # are 0 then break cause # 1's are expected if (i < j and graph[i][j] == 0): lowertri = False break # Break out of the # loop if false if not lowertri: break # If true then print # unilaterally connected # and return if lowertri: print("Unilaterally Connected") exit() # If elements are in random order # unsynchronized then print weakly # connected and return else: print("Weakly Connected") exit() if __name__ == "__main__": # Number of nodes n = 3 # Given Path Matrix graph = [[0, 1, 1], [0, 0, 1], [0, 0, 0]] # Function Call checkConnected(graph, n) # This code is contributed by rutvik_56 C# // C# implementation of the above approach using System; class GFG { // static readonly int V = 3; // Function to find the characteristic // of the given graph static int checkConnected(int[, ] graph, int n) { // Check whether the graph is // strongly connected or not bool strongly = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If all the elements are // not equal then the graph // is not strongly connected if (graph[i, j] != graph[j, i]) { strongly = false; break; } } // Break out of the loop if false if (!strongly) { break; } } // If true then print strongly // connected and return if (strongly) { Console.Write("Strongly Connected"); return 0; } // Check whether the graph is // Unilaterally connected by // checking Upper Triangle element bool uppertri = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If uppertriangle elements // are 0 then break out of the // loop and check the elements // of lowertriangle matrix if (i > j && graph[i, j] == 0) { uppertri = false; break; } } // Break out of the loop if false if (!uppertri) { break; } } // If true then print unilaterally // connected and return if (uppertri) { Console.Write("Unilaterally Connected"); return 0; } // Check lowertraingle elements bool lowertri = true; // Traverse the path matrix for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { // If lowertraingle elements // are 0 then break cause // 1's are expected if (i < j && graph[i, j] == 0) { lowertri = false; break; } } // Break out of the loop if false if (!lowertri) { break; } } // If true then print unilaterally // connected and return if (lowertri) { Console.Write("Unilaterally Connected"); return 0; } // If elements are in random order // unsynchronized then print weakly // connected and return else { Console.Write("Weakly Connected"); } return 0; } // Driver Code public static void Main(String[] args) { // Number of nodes int n = 3; // Given Path Matrix int[, ] graph = { { 0, 1, 1 }, { 0, 0, 1 }, { 0, 0, 0 } }; // Function call checkConnected(graph, n); } } // This code is contributed by 29AjayKumar JavaScript <script> // Javascript implementation of the above approach let V = 3; // Function to find the characteristic // of the given graph function checkConnected(graph, n) { // Check whether the graph is // strongly connected or not let strongly = true; // Traverse the path matrix for(let i = 0; i < n; i++) { for(let j = 0; j < n; j++) { // If all the elements are // not equal then the graph // is not strongly connected if (graph[i][j] != graph[j][i]) { strongly = false; break; } } // Break out of the loop if false if (!strongly) { break; } } // If true then print strongly // connected and return if (strongly) { document.write("Strongly Connected"); return 0; } // Check whether the graph is // Unilaterally connected by // checking Upper Triangle element let uppertri = true; // Traverse the path matrix for(let i = 0; i < n; i++) { for(let j = 0; j < n; j++) { // If uppertriangle elements // are 0 then break out of the // loop and check the elements // of lowertriangle matrix if (i > j && graph[i][j] == 0) { uppertri = false; break; } } // Break out of the loop if false if (!uppertri) { break; } } // If true then print unilaterally // connected and return if (uppertri) { document.write("Unilaterally Connected"); return 0; } // Check lowertraingle elements let lowertri = true; // Traverse the path matrix for(let i = 0; i < n; i++) { for(let j = 0; j < n; j++) { // If lowertraingle elements // are 0 then break cause // 1's are expected if (i < j && graph[i][j] == 0) { lowertri = false; break; } } // Break out of the loop if false if (!lowertri) { break; } } // If true then print unilaterally // connected and return if (lowertri) { document.write("Unilaterally Connected"); return 0; } // If elements are in random order // unsynchronized then print weakly // connected and return else { document.write("Weakly Connected"); } return 0; } // Driver Code // Number of nodes let n = 3; // Given Path Matrix let graph = [[ 0, 1, 1 ], [ 0, 0, 1 ], [ 0, 0, 0 ]]; // Function call checkConnected(graph, n); // This code is contributed by susmitakundugoaldanga. </script> OutputUnilaterally Connected Time Complexity: O(N2) Auxiliary Space: O(1) Comment More infoAdvertise with us Next Article Analysis of Algorithms S shreedhar_bhatt Follow Improve Article Tags : DSA Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. 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