C# | Random.Next() Method
Last Updated :
11 Jul, 2025
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The Next() Method of System.Random class in C# is used to get a random integer number. This method can be overloaded by passing different parameters to it as follows:
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- Next()
- Next(Int32)
- Next(Int32, Int32)
Next() Method
This method is used to returns a non-negative random integer. Syntax:public virtual int Next ();Return Value: This method returns the 32-bit signed integer which is greater than or equal to 0 and less than MaxValue. Example:
// C# program to illustrate the
// Random.Next() Method
using System;
class GFG {
// Driver code
public static void Main()
{
// Instantiate random number generator
Random rand = new Random();
// Print 10 random numbers
Console.WriteLine("Printing 10 random numbers");
for (int i = 1; i <= 10; i++)
Console.WriteLine("{0} -> {1}", i, rand.Next());
}
}
Output:
Printing 10 random numbers 1 -> 1386420123 2 -> 2133003862 3 -> 981665925 4 -> 495382685 5 -> 1127976381 6 -> 824414652 7 -> 213006792 8 -> 1948108820 9 -> 214839986 10 -> 261560448
Next(Int32) Method
This method is used to get a non-negative random integer which is less than the specified maximum. Syntax:public virtual int Next (int maxValue);Here, maxValue is the upper boundary of the random number to be generated. It must be greater than or equal to 0. Return Value: The function returns a 32-bit signed integer which is greater than or equal to 0, and less than maxValue. However, if maxValue equals 0, maxValue is returned. Exception: This method will give ArgumentOutOfRangeException if the maxValue is less than 0. Example:
// C# program to illustrate the
// Random.Next(Int32) Method
using System;
class GFG {
// Driver code
public static void Main()
{
// Instantiate random number generator
Random rand = new Random();
// Print 10 random numbers less than 100
Console.WriteLine("Printing 10 random numbers less than 100");
for (int i = 1; i <= 10; i++)
Console.WriteLine("{0} -> {1}", i, rand.Next(100));
}
}
Output:
Printing 10 random numbers less than 100 1 -> 19 2 -> 94 3 -> 14 4 -> 54 5 -> 94 6 -> 73 7 -> 39 8 -> 42 9 -> 18 10 -> 77
Next(Int32, Int32) Method
This method is used to get the random integer that is within a specified range. Syntax:public virtual int Next (int minValue, int maxValue);Parameters:
- maxValue: It is the exclusive upper boundary of the random number generated. It must be greater than or equal to minValue.
- minValue: It is the inclusive lower bound of the random number returned.
// C# program to illustrate the
// Next(Int32, Int32) Method
using System;
class GFG {
// Driver code
public static void Main()
{
// Instantiate random number generator
Random rand = new Random();
// Print 10 random numbers between 50 and 100
Console.WriteLine("Printing 10 random numbers"+
" between 50 and 100");
for (int i = 1; i <= 10; i++)
Console.WriteLine("{0} -> {1}", i, rand.Next(50, 100));
}
}
Output:
Reference:
Printing 10 random numbers between 50 and 100 1 -> 91 2 -> 85 3 -> 93 4 -> 74 5 -> 88 6 -> 77 7 -> 92 8 -> 76 9 -> 77 10 -> 52