C Program for KMP Algorithm for Pattern Searching[duplicate] Last Updated : 13 Jul, 2023 Comments Improve Suggest changes Like Article Like Report C++ // C++ program for implementation of KMP pattern searching // algorithm #include <bits/stdc++.h> void computeLPSArray(char* pat, int M, int* lps); // Prints occurrences of txt[] in pat[] void KMPSearch(char* pat, char* txt) { int M = strlen(pat); int N = strlen(txt); // create lps[] that will hold the longest prefix suffix // values for pattern int lps[M]; // Preprocess the pattern (calculate lps[] array) computeLPSArray(pat, M, lps); int i = 0; // index for txt[] int j = 0; // index for pat[] while (i < N) { if (pat[j] == txt[i]) { j++; i++; } if (j == M) { printf("Found pattern at index %d ", i - j); j = lps[j - 1]; } // mismatch after j matches else if (i < N && pat[j] != txt[i]) { // Do not match lps[0..lps[j-1]] characters, // they will match anyway if (j != 0) j = lps[j - 1]; else i = i + 1; } } } // Fills lps[] for given pattern pat[0..M-1] void computeLPSArray(char* pat, int M, int* lps) { // length of the previous longest prefix suffix int len = 0; lps[0] = 0; // lps[0] is always 0 // the loop calculates lps[i] for i = 1 to M-1 int i = 1; while (i < M) { if (pat[i] == pat[len]) { len++; lps[i] = len; i++; } else // (pat[i] != pat[len]) { // This is tricky. Consider the example. // AAACAAAA and i = 7. The idea is similar // to search step. if (len != 0) { len = lps[len - 1]; // Also, note that we do not increment // i here } else // if (len == 0) { lps[i] = 0; i++; } } } } // Driver program to test above function int main() { char txt[] = "ABABDABACDABABCABAB"; char pat[] = "ABABCABAB"; KMPSearch(pat, txt); return 0; } Please refer complete article on KMP Algorithm for Pattern Searching for more details! Comment More infoAdvertise with us Next Article C Program for KMP Algorithm for Pattern Searching[duplicate] kartik Follow Improve Article Tags : C Language Similar Reads C Program for KMP Algorithm for Pattern Searching Given a text txt[0..n-1] and a pattern pat[0..m-1], write a function search(char pat[], char txt[]) that prints all occurrences of pat[] in txt[]. You may assume that n > m. 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