BigInteger setBit() Method in Java
Last Updated :
03 Mar, 2022
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The java.math.BigInteger.setbit(index) method returns a Big-integer whose value is equivalent to this Big-integer with the designated bit set. The method computes (this | (1<<n)). The bit at index n of binary representation of Big-integer will be set means converted to 1.
Syntax:
public BigInteger setbit(int n)
Parameters: The method takes one parameter n which refers to the index of the bit that is needed to be set.
Return Value: The method returns the BigInteger value after setting the bit position n.
Exceptions: The method might throw an ArithmeticException when n is negative..
Examples:
Input: value = 2300 index = 1 Output: 2302 Explanation: Binary Representation of 2300 = 100011111100 bit at index 1 is 0 so set the bit at index 1 Now Binary Representation becomes 100011111110 and Decimal equivalent of 100011111110 is 2302 Input: value = 5482549 index = 1 Output: 5482551
Below program illustrate the setBit(index) method of BigInteger:
// Program to demonstrate setBit() method of BigInteger
import java.math.*;
public class GFG {
public static void main(String[] args)
{
// Creating BigInteger object
BigInteger biginteger = new BigInteger("2300");
// Creating an integer i for index
int i = 1;
// Calling setBit() method on bigInteger at index i
// store the return BigInteger
BigInteger changedvalue = biginteger.setBit(i);
String result = "After applying setBit at index " +
i + " of " + biginteger+ " New Value is " + changedvalue;
// Displaying the result
System.out.println(result);
}
}
Output:
After applying setBit at index 1 of 2300 New Value is 2302