matplotlib-users Mailing List for matplotlib (Page 13)

Works for me with TkAgg backend on 1.4.3.

-Sterling

On Jul 9, 2015, at 3:52AM, Mark Bakker <ma...@gm...> wrote:

> Hello list,
> 
> I am trying to set the backgroundcolor of a textbox:
> 
> from pylab import *
> plot([1, 2, 3])
> text(1, 2, 'Hello', backgroundcolor = 'red')
> 
> This plots a nice red box but no text. It looks like the backgroundcolor is set as the foreground. Am I doing something wrong or is this a bug? mpl version 1.4.3
> 
> Thanks, Mark
> 
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Which backend are you using? It works fine for me with a recent-ish master
using Qt4Agg backend.

Ben Root

On Thu, Jul 9, 2015 at 6:52 AM, Mark Bakker <ma...@gm...> wrote:

> Hello list,
>
> I am trying to set the backgroundcolor of a textbox:
>
> from pylab import *
> plot([1, 2, 3])
> text(1, 2, 'Hello', backgroundcolor = 'red')
>
> This plots a nice red box but no text. It looks like the backgroundcolor
> is set as the foreground. Am I doing something wrong or is this a bug? mpl
> version 1.4.3
>
> Thanks, Mark
>
>
>
> ------------------------------------------------------------------------------
> Don't Limit Your Business. Reach for the Cloud.
> GigeNET's Cloud Solutions provide you with the tools and support that
> you need to offload your IT needs and focus on growing your business.
> Configured For All Businesses. Start Your Cloud Today.
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>
>

why not use MathJax?

On Thu, Jul 9, 2015 at 8:03 AM, asiga <asi...@ya...> wrote:

> Hi,
>
> I need to render LaTeX math formulas on mobile apps (iOS/Android), with
> high
> quality, and as efficiently as possible.
>
> I'm considering matplotlib as the best candidate at the moment. Maybe it
> might be a bit overkill because I don't need plotting, just math formulas
> rendering, but it has a "copycenter" license (very welcome when you target
> iOS), and it seems to render LaTeX math with high quality. So I think it
> beats other options I found (MathGL: copyleft license; and MathJax: setting
> a complete Javascript engine just for rendering math does seem overkill to
> me).
>
> However, I still have some doubts before choosing matplotlib:
>
> 1) Can I redirect the output of math rendering to OpenGL calls, or convert
> it into a 2D triangle mesh for example? (if the drawing commands issued by
> matplotlib when rendering math are a relatively small set, I can translate
> them to OpenGL myself, but I need to know where should I do that
> translation
> (I've zero idea about matplotlib internals, and I'm a Python newbie -I'm
> here because I need math rendering, not because I use Python).
>
> (note that I wish to render through OpenGL because I want to be able to
> interactively pan and zoom math very efficiently: the best approach would
> be
> to cache the matplotlib output as a -for example- 2D triangle mesh, and
> then
> just send the triangles to OpenGL, without having to call matplotlib on
> each
> screen redraw, which would kill performance)
>
> 2) In order to get matplotlib running as efficient as possible on mobile
> devices, would you recommend that I translate matplotlib to C/C++ using any
> of the translators available? If affirmative, what translator would you
> suggest me to use?
>
> Thanks a lot!!
>
>
>
>
>
> --
> View this message in context:
> http://matplotlib.1069221.n5.nabble.com/Efficient-matplotlib-use-on-iOS-and-Android-apps-tp45901.html
> Sent from the matplotlib - users mailing list archive at Nabble.com.
>
>
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>

It might just have to be 2 separate contour/surface plots side by side,
perhaps with a linked cursor between them.
The other thing I considered was combining the a,b data into a single value
(combined % deviation from ideal?) but that reduces the data which I'd
rather not do if possible.

On Thu, Jul 9, 2015 at 9:40 AM, Jonno <jon...@gm...> wrote:

> I was thinking of doing that or having 2 surface plots but I think it
> would be visually quite confusing.
> I was trying to think of an example since I'm sure someone has come up
> with a nice way to display this kind of data.
> Imagine if the data was average temperature (a) and average rainfall (b)
> for a region in the world (lat/long = x,y). The goal is to display the data
> such that it's obvious where the locations are that have closest to the
> ideal temp/rain combination.
> How would you go about that?
>
> On Thu, Jul 9, 2015 at 12:28 AM, Sterling Smith <sm...@fu...>
> wrote:
>
>> In the x,y plane, could you overlay contours of a with contours of b?
>> -Sterling
>>
>> On Jul 8, 2015, at 8:19PM, Jonno <jon...@gm...> wrote:
>>
>> > I have a bunch of experimental data points each of which has 2
>> variables (x,y) and 2 results (a,b). Each pair or x,y values produces a
>> pair of a,b resultant values.
>> > There is a single optimal pair of a,b values and I'd like to figure out
>> a way to illustrate the data to show the relationship between each x,y pair
>> and how close each a,b pair is to the ideal.
>> > I'm thinking about a dual surface/contour plot with 2 different z-axes.
>> Ideally I would center both z-axes at the ideal values. I don't know if
>> this is possible. Might be kinda messy.
>> >
>> > Any other thoughts? I'm sure there must be other examples where this is
>> a problem.
>> >
>> ------------------------------------------------------------------------------
>> > Don't Limit Your Business. Reach for the Cloud.
>> > GigeNET's Cloud Solutions provide you with the tools and support that
>> > you need to offload your IT needs and focus on growing your business.
>> > Configured For All Businesses. Start Your Cloud Today.
>> >
>> https://www.gigenetcloud.com/_______________________________________________
>> > Matplotlib-users mailing list
>> > Mat...@li...
>> > https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>>
>>
>

I was thinking of doing that or having 2 surface plots but I think it would
be visually quite confusing.
I was trying to think of an example since I'm sure someone has come up with
a nice way to display this kind of data.
Imagine if the data was average temperature (a) and average rainfall (b)
for a region in the world (lat/long = x,y). The goal is to display the data
such that it's obvious where the locations are that have closest to the
ideal temp/rain combination.
How would you go about that?

On Thu, Jul 9, 2015 at 12:28 AM, Sterling Smith <sm...@fu...>
wrote:

> In the x,y plane, could you overlay contours of a with contours of b?
> -Sterling
>
> On Jul 8, 2015, at 8:19PM, Jonno <jon...@gm...> wrote:
>
> > I have a bunch of experimental data points each of which has 2 variables
> (x,y) and 2 results (a,b). Each pair or x,y values produces a pair of a,b
> resultant values.
> > There is a single optimal pair of a,b values and I'd like to figure out
> a way to illustrate the data to show the relationship between each x,y pair
> and how close each a,b pair is to the ideal.
> > I'm thinking about a dual surface/contour plot with 2 different z-axes.
> Ideally I would center both z-axes at the ideal values. I don't know if
> this is possible. Might be kinda messy.
> >
> > Any other thoughts? I'm sure there must be other examples where this is
> a problem.
> >
> ------------------------------------------------------------------------------
> > Don't Limit Your Business. Reach for the Cloud.
> > GigeNET's Cloud Solutions provide you with the tools and support that
> > you need to offload your IT needs and focus on growing your business.
> > Configured For All Businesses. Start Your Cloud Today.
> >
> https://www.gigenetcloud.com/_______________________________________________
> > Matplotlib-users mailing list
> > Mat...@li...
> > https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>
>

Hi,

I need to render LaTeX math formulas on mobile apps (iOS/Android), with high
quality, and as efficiently as possible.

I'm considering matplotlib as the best candidate at the moment. Maybe it
might be a bit overkill because I don't need plotting, just math formulas
rendering, but it has a "copycenter" license (very welcome when you target
iOS), and it seems to render LaTeX math with high quality. So I think it
beats other options I found (MathGL: copyleft license; and MathJax: setting
a complete Javascript engine just for rendering math does seem overkill to
me).

However, I still have some doubts before choosing matplotlib:

1) Can I redirect the output of math rendering to OpenGL calls, or convert
it into a 2D triangle mesh for example? (if the drawing commands issued by
matplotlib when rendering math are a relatively small set, I can translate
them to OpenGL myself, but I need to know where should I do that translation
(I've zero idea about matplotlib internals, and I'm a Python newbie -I'm
here because I need math rendering, not because I use Python).

(note that I wish to render through OpenGL because I want to be able to
interactively pan and zoom math very efficiently: the best approach would be
to cache the matplotlib output as a -for example- 2D triangle mesh, and then
just send the triangles to OpenGL, without having to call matplotlib on each
screen redraw, which would kill performance)

2) In order to get matplotlib running as efficient as possible on mobile
devices, would you recommend that I translate matplotlib to C/C++ using any
of the translators available? If affirmative, what translator would you
suggest me to use?

Thanks a lot!!

 



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Hello list,

I am trying to set the backgroundcolor of a textbox:

from pylab import *
plot([1, 2, 3])
text(1, 2, 'Hello', backgroundcolor = 'red')

This plots a nice red box but no text. It looks like the backgroundcolor is
set as the foreground. Am I doing something wrong or is this a bug? mpl
version 1.4.3

Thanks, Mark

In the x,y plane, could you overlay contours of a with contours of b?
-Sterling

On Jul 8, 2015, at 8:19PM, Jonno <jon...@gm...> wrote:

> I have a bunch of experimental data points each of which has 2 variables (x,y) and 2 results (a,b). Each pair or x,y values produces a pair of a,b resultant values.
> There is a single optimal pair of a,b values and I'd like to figure out a way to illustrate the data to show the relationship between each x,y pair and how close each a,b pair is to the ideal.
> I'm thinking about a dual surface/contour plot with 2 different z-axes. Ideally I would center both z-axes at the ideal values. I don't know if this is possible. Might be kinda messy.
> 
> Any other thoughts? I'm sure there must be other examples where this is a problem.
> ------------------------------------------------------------------------------
> Don't Limit Your Business. Reach for the Cloud.
> GigeNET's Cloud Solutions provide you with the tools and support that
> you need to offload your IT needs and focus on growing your business.
> Configured For All Businesses. Start Your Cloud Today.
> https://www.gigenetcloud.com/_______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users

I have a bunch of experimental data points each of which has 2 variables
(x,y) and 2 results (a,b). Each pair or x,y values produces a pair of a,b
resultant values.
There is a single optimal pair of a,b values and I'd like to figure out a
way to illustrate the data to show the relationship between each x,y pair
and how close each a,b pair is to the ideal.
I'm thinking about a dual surface/contour plot with 2 different z-axes.
Ideally I would center both z-axes at the ideal values. I don't know if
this is possible. Might be kinda messy.

Any other thoughts? I'm sure there must be other examples where this is a
problem.

Hi,

I'm trying to use a custom font that is set dynamically at runtime, if available. (I don't want this font to be the default in the config file.) But matplotlib keeps defaulting to the generic sans-serif font if I include that as an option later in the font family list.

In the process of troubleshooting, I found there was a commit which already addressed this issue (https://github.com/matplotlib/matplotlib/commit/314a0cf), although unfortunately it didn't solve it in my particular case, when the font being scored is first in the rcParams font alias list.

Seems like it could be an easy fix for someone familiar with the scoring algorithm. I don't see quite what the expected scores *should* be (the docstring for that function looks to be out of sync) but it shouldn't be 0 for default fonts not explicitly named first in the family list. I'll put this in the bug tracker and try to workaround for now.

Thanks,
cw

Your code example is incomplete. Even if I add in the typical imports and
"fig, ax = plt.subplots()" and "plt.show()", The x tick labels aren't
rotated, and I certainly don't have too many tick labels. Could you provide
a complete working example that demonstrate the problem?

Ben Root

On Wed, Jul 8, 2015 at 9:15 AM, manik971 <nec...@ho...> wrote:

> <code>
> date_range = (735599.0, 735745.0)
> x = (735610.5, 735647.0, 735647.5, 735648.5, 735669.0, 735699.0, 735701.5,
> 735702.5, 735709.5, 735725.5, 735728.5, 735735.5, 735736.0)
> y = (227891.25361545716, 205090.4880046467, 208352.59317388065,
> 175462.99296699322, 98209.836461969651, 275063.37219361769,
> 219456.93600708069, 230731.12613806152, 209043.19805037521,
> 218297.51486296533, 208036.88967207001, 206311.71988471842,
> 216036.56824433553)
> y0 = 218206.79192
> x_after = (735610.5, 735647.0, 735647.5, 735701.5, 735702.5, 735709.5,
> 735725.5, 735728.5, 735735.5, 735736.0)
> y_after = (227891.25361545716, 205090.4880046467, 208352.59317388065,
> 219456.93600708069, 230731.12613806152, 209043.19805037521,
> 218297.51486296533, 208036.88967207001, 206311.71988471842,
> 216036.56824433553)
> ax.plot_date(x, numpy.array(y) / y0, color='r', xdate=True, marker='x')
> linex = -39.1175584541
> liney = 28993493.5251
>
> ax.set_xlim(date_range)
> steps = list(ax.get_xlim())
> steps.append(steps[-1] + 2)
> steps = [steps[0] - 2] + steps
> ax.plot(steps, numpy.array([linex * a + liney for a in steps]) / y0,
> color='b')
> </code>
>
>
>
> --
> View this message in context:
> http://matplotlib.1069221.n5.nabble.com/Plot-Too-many-ticks-on-X-axe-tp45893p45894.html
> Sent from the matplotlib - users mailing list archive at Nabble.com.
>
>
> ------------------------------------------------------------------------------
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> GigeNET's Cloud Solutions provide you with the tools and support that
> you need to offload your IT needs and focus on growing your business.
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>

<code>
date_range = (735599.0, 735745.0)
x = (735610.5, 735647.0, 735647.5, 735648.5, 735669.0, 735699.0, 735701.5,
735702.5, 735709.5, 735725.5, 735728.5, 735735.5, 735736.0)
y = (227891.25361545716, 205090.4880046467, 208352.59317388065,
175462.99296699322, 98209.836461969651, 275063.37219361769,
219456.93600708069, 230731.12613806152, 209043.19805037521,
218297.51486296533, 208036.88967207001, 206311.71988471842,
216036.56824433553)
y0 = 218206.79192
x_after = (735610.5, 735647.0, 735647.5, 735701.5, 735702.5, 735709.5,
735725.5, 735728.5, 735735.5, 735736.0)
y_after = (227891.25361545716, 205090.4880046467, 208352.59317388065,
219456.93600708069, 230731.12613806152, 209043.19805037521,
218297.51486296533, 208036.88967207001, 206311.71988471842,
216036.56824433553)
ax.plot_date(x, numpy.array(y) / y0, color='r', xdate=True, marker='x')
linex = -39.1175584541
liney = 28993493.5251

ax.set_xlim(date_range)
steps = list(ax.get_xlim())
steps.append(steps[-1] + 2)
steps = [steps[0] - 2] + steps
ax.plot(steps, numpy.array([linex * a + liney for a in steps]) / y0,
color='b')
</code>



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Hello,

The first loaded plot have too many ticks on X axe (see image01).
<http://matplotlib.1069221.n5.nabble.com/file/n45893/help-01.jpg> 

If I use the zoom action on X axe, the plot is now well loaded.
<http://matplotlib.1069221.n5.nabble.com/file/n45893/help-02.jpg> 

Can you give me some advise where I can search because The Plot constructor
parameters seems good.

Thank you for your help.
Manuel



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We are pleased to announce the fourth public release of HoloViews,
a Python package for simplifying the exploration of scientific data:

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   conda install -c ioam holoviews

   pip install --upgrade 'holoviews[recommended]'

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   using Python 3's better unicode support (when available).

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   and nbagg) with support for other plotting systems (such as Bokeh)
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   multiple color bars. Polar projections now supported throughout.

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   define blank spaces (using the Empty object) as well as more
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   interact widgets, improvements to the Pandas interface, easy
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talks in Austin and Cambridge (or read the paper at http://goo.gl/NH9FTB)!

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Jean-Luc R. Stevens
James A. Bednar

The University of Edinburgh
School of Informatics

-- 
The University of Edinburgh is a charitable body, registered in
Scotland, with registration number SC005336.

Christian Alis wrote:

> Have you tried making the string unicode?
> 
> ax.set_xlabel (u' ')
> 
> 
------------------------------------------------------------------------------

Oh, thanks.  That works now on py2 and py3.

Have you tried making the string unicode?

ax.set_xlabel (u' ')

This code runs on python3, but on python2 I get:
Traceback (most recent call last):
  File "per_vs_lambda.py", line 35, in <module>
    ax.set_xlabel (' ')
  File "/usr/lib64/python2.7/site-packages/matplotlib/axes/_axes.py", line 
179, in set_xlabel
    return self.xaxis.set_label_text(xlabel, fontdict, **kwargs)
  File "/usr/lib64/python2.7/site-packages/matplotlib/axis.py", line 1480, 
in set_label_text
    self.label.set_text(label)
  File "/usr/lib64/python2.7/site-packages/matplotlib/text.py", line 1028, 
in set_text
    self._text = '%s' % (s,)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xce in position 0: 
ordinal not in range(128)


#!/usr/bin/python
# -*- coding: utf-8 -*-
data='''carriers,lambda,per
1,7,1.3e-4
1,8,3.0e-4
1,9,.0014
8,7,4.8e-4
8,8,1.3e-3
8,9,.0075
'''

import pandas as pd
try:
    from StringIO import StringIO
except ImportError:
    from io import StringIO
df = pd.read_csv (StringIO (data))
g = df.groupby ('carriers')
import matplotlib.pyplot as plt

import matplotlib as mpl
#mpl.rcParams['font.family'] = 'stix'
mpl.rc('font', family='DejaVu Sans')
#mpl.rc('font', family='stix')

import itertools
markers = itertools.cycle(['o','s','v']) 

fig = plt.figure() 
ax = fig.add_subplot(111)
for c, stuff in g:
    plt.semilogy (stuff['lambda'].values, stuff['per'].values, 
label='carriers=%s'%c, marker=next(markers))

plt.legend (loc='best')
ax.set_xlabel (' ') <<< this invisible character is a small greek lambda
ax.set_ylabel ('per')
plt.grid(which='major', linestyle='solid')
plt.grid(which='minor', linestyle='dashed') 
plt.savefig ('per_vs_lambda.pdf')

Neal Becker wrote:

> Using mpl 1.4.3 on Fedora 22, I'm trying to use stix font (so I can render
> the unicode lambda label on the x-axis).  I have every fedora package
> related to 'stix', I think. It displays ok in qtagg4, but if I try to save
> to pdf if fails with
> 
> RuntimeError                              Traceback (most recent call
> last) <ipython-input-2-7dee58c07264> in <module>()
> ----> 1 exec(open(r'/usr/tmp/python-8710q1Y.py').read()) # PYTHON-MODE
> 
> <string> in <module>()
> 
> /usr/lib64/python3.4/site-packages/matplotlib/pyplot.py in savefig(*args,
> **kwargs)
>     575 def savefig(*args, **kwargs):
>     576     fig = gcf()
> --> 577     res = fig.savefig(*args, **kwargs)
>     578     draw()   # need this if 'transparent=True' to reset colors
>     579     return res
> 
> /usr/lib64/python3.4/site-packages/matplotlib/figure.py in savefig(self,
> *args, **kwargs)
>    1474             self.set_frameon(frameon)
>    1475
> -> 1476         self.canvas.print_figure(*args, **kwargs)
>    1477
>    1478         if frameon:
> 
> /usr/lib64/python3.4/site-packages/matplotlib/backend_bases.py in
> print_figure(self, filename, dpi, facecolor, edgecolor, orientation,
> format, **kwargs)
>    2209                 orientation=orientation,
>    2210                 bbox_inches_restore=_bbox_inches_restore,
> -> 2211                 **kwargs)
>    2212         finally:
>    2213             if bbox_inches and restore_bbox:
> 
> /usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in
> print_pdf(self, filename, **kwargs)
>    2489                 file.endStream()
>    2490             else:            # we opened the file above; now
>    finish
> it off
> -> 2491                 file.close()
>    2492
>    2493
> 
> /usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in
> close(self)
>     523         self.endStream()
>     524         # Write out the various deferred objects
> --> 525         self.writeFonts()
>     526         self.writeObject(self.alphaStateObject,
>     527                          dict([(val[0], val[1])
> 
> /usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in
> writeFonts(self)
>     626                 chars = self.used_characters.get(stat_key)
>     627                 if chars is not None and len(chars[1]):
> --> 628                     fonts[Fx] = self.embedTTF(realpath, chars[1])
>     629         self.writeObject(self.fontObject, fonts)
>     630
> 
> /usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in
> embedTTF(self, filename, characters)
>    1101
>    1102         if fonttype == 3:
> -> 1103             return embedTTFType3(font, characters, descriptor)
>    1104         elif fonttype == 42:
>    1105             return embedTTFType42(font, characters, descriptor)
> 
> /usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in
> embedTTFType3(font, characters, descriptor)
>     887             # actual outlines)
>     888             rawcharprocs = ttconv.get_pdf_charprocs(
> --> 889                 filename.encode(sys.getfilesystemencoding()),
> glyph_ids)
>     890             charprocs = {}
>     891             for charname, stream in six.iteritems(rawcharprocs):
> 
> RuntimeError: TrueType font is missing table
> 

forgot to attach the code.


#!/usr/bin/python
# -*- coding: utf-8 -*-
data='''carriers,lambda,per
1,7,1.3e-4
1,8,3.0e-4
1,9,.0014
8,7,4.8e-4
8,8,1.3e-3
8,9,.0075
'''

import pandas as pd
try:
    from StringIO import StringIO
except ImportError:
    from io import StringIO
df = pd.read_csv (StringIO (data))
g = df.groupby ('carriers')
import matplotlib.pyplot as plt

import matplotlib as mpl
#mpl.rcParams['font.family'] = 'stix'
mpl.rc('font', family='DejaVu Sans')
#mpl.rc('font', family='stix')

import itertools
markers = itertools.cycle(['o','s','v']) 

fig = plt.figure() 
ax = fig.add_subplot(111)
for c, stuff in g:
    plt.semilogy (stuff['lambda'].values, stuff['per'].values, 
label='carriers=%s'%c, marker=next(markers))

plt.legend (loc='best')
ax.set_xlabel (' ')
ax.set_ylabel ('per')
plt.grid(which='major', linestyle='solid')
plt.grid(which='minor', linestyle='dashed') 
plt.savefig ('per_vs_lambda.pdf')

Using mpl 1.4.3 on Fedora 22, I'm trying to use stix font (so I can render 
the unicode lambda label on the x-axis).  I have every fedora package 
related to 'stix', I think. It displays ok in qtagg4, but if I try to save 
to pdf if fails with

RuntimeError                              Traceback (most recent call last)
<ipython-input-2-7dee58c07264> in <module>()
----> 1 exec(open(r'/usr/tmp/python-8710q1Y.py').read()) # PYTHON-MODE

<string> in <module>()

/usr/lib64/python3.4/site-packages/matplotlib/pyplot.py in savefig(*args, 
**kwargs)
    575 def savefig(*args, **kwargs):
    576     fig = gcf()
--> 577     res = fig.savefig(*args, **kwargs)
    578     draw()   # need this if 'transparent=True' to reset colors
    579     return res

/usr/lib64/python3.4/site-packages/matplotlib/figure.py in savefig(self, 
*args, **kwargs)
   1474             self.set_frameon(frameon)
   1475 
-> 1476         self.canvas.print_figure(*args, **kwargs)
   1477 
   1478         if frameon:

/usr/lib64/python3.4/site-packages/matplotlib/backend_bases.py in 
print_figure(self, filename, dpi, facecolor, edgecolor, orientation, format, 
**kwargs)
   2209                 orientation=orientation,
   2210                 bbox_inches_restore=_bbox_inches_restore,
-> 2211                 **kwargs)
   2212         finally:
   2213             if bbox_inches and restore_bbox:

/usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in 
print_pdf(self, filename, **kwargs)
   2489                 file.endStream()
   2490             else:            # we opened the file above; now finish 
it off
-> 2491                 file.close()
   2492 
   2493 

/usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in 
close(self)
    523         self.endStream()
    524         # Write out the various deferred objects
--> 525         self.writeFonts()
    526         self.writeObject(self.alphaStateObject,
    527                          dict([(val[0], val[1])

/usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in 
writeFonts(self)
    626                 chars = self.used_characters.get(stat_key)
    627                 if chars is not None and len(chars[1]):
--> 628                     fonts[Fx] = self.embedTTF(realpath, chars[1])
    629         self.writeObject(self.fontObject, fonts)
    630 

/usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in 
embedTTF(self, filename, characters)
   1101 
   1102         if fonttype == 3:
-> 1103             return embedTTFType3(font, characters, descriptor)
   1104         elif fonttype == 42:
   1105             return embedTTFType42(font, characters, descriptor)

/usr/lib64/python3.4/site-packages/matplotlib/backends/backend_pdf.py in 
embedTTFType3(font, characters, descriptor)
    887             # actual outlines)
    888             rawcharprocs = ttconv.get_pdf_charprocs(
--> 889                 filename.encode(sys.getfilesystemencoding()), 
glyph_ids)
    890             charprocs = {}
    891             for charname, stream in six.iteritems(rawcharprocs):

RuntimeError: TrueType font is missing table

Thank you very for helping with this issue. I am using the last version 1.4.3 (if it is the last one).

 

Gaël

 

De : ben...@gm... [mailto:ben...@gm...] De la part de Benjamin Root
Envoyé : 3 juillet 2015 22:41
À : Gael Grissonnanche
Cc : Matplotlib Users
Objet : Re: [Matplotlib-users] Zorder and Clip_on issues

 

Which version of matplotlib? This is familiar.... I could have sworn we fixed this.

Ben Root

On Jul 3, 2015 10:25 PM, "Gael Grissonnanche" <gae...@gm... <mailto:gae...@gm...> > wrote:

Hi everyone,

 

I had recently experienced a frustration regarding zorder and clip_on in Matplotlib.

 

In figure 1 attached here, I would like to put blue horizontal error bars above the x-axis. As you can see right now, half of it is cut by the x-axis (for the blue point at H = 0). I used:

 

axes.errorbar(data[:,0], data[:,1], xerr=data[:,2], fmt='', ls ="", c = ‘b’, capthick=2, elinewidth=2, clip_on = False, zorder = 10)

 

But even if I change zorder = 1000, the error bar never goes above the axis. Is it a bug?

 

Regarding the same topic, I also discovered that when using axes.twinx() in Figure 2 (A : axes; B : axes2 = axes.twinx()). The blue curve (A) never goes above the red curve (B), whatever zorder I use. I even tried axes2.set_axisbelow(True), but it doesn’t change anything. I really want “axes2” to be below the “axes”. Is it a bug? I had to change it manually with Illustrator and it worked, but it is of course really not convenient.

 

Thank you very much for your help !

 

 


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Which version of matplotlib? This is familiar.... I could have sworn we
fixed this.

Ben Root
On Jul 3, 2015 10:25 PM, "Gael Grissonnanche" <gae...@gm...>
wrote:

> Hi everyone,
>
>
>
> I had recently experienced a frustration regarding zorder and clip_on in
> Matplotlib.
>
>
>
> In figure 1 attached here, I would like to put blue horizontal error bars
> above the x-axis. As you can see right now, half of it is cut by the x-axis
> (for the blue point at H = 0). I used:
>
>
>
> axes.errorbar(data[:,0], data[:,1], xerr=data[:,2], fmt='', ls ="", c =
> ‘b’, capthick=2, elinewidth=2, clip_on = False, zorder = 10)
>
>
>
> But even if I change zorder = 1000, the error bar never goes above the
> axis. Is it a bug?
>
>
>
> Regarding the same topic, I also discovered that when using axes.twinx()
> in Figure 2 (A : axes; B : axes2 = axes.twinx()). The blue curve (A) never
> goes above the red curve (B), whatever zorder I use. I even tried
> axes2.set_axisbelow(True), but it doesn’t change anything. I really want
> “axes2” to be below the “axes”. Is it a bug? I had to change it manually
> with Illustrator and it worked, but it is of course really not convenient.
>
>
>
> Thank you very much for your help !
>
>
>
>
>
>
> ------------------------------------------------------------------------------
> Don't Limit Your Business. Reach for the Cloud.
> GigeNET's Cloud Solutions provide you with the tools and support that
> you need to offload your IT needs and focus on growing your business.
> Configured For All Businesses. Start Your Cloud Today.
> https://www.gigenetcloud.com/
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>
>

Such as example below. I want to put a new ax at data coordinates
[(45,45),(50,50)], but the transform fail to transform data coordinates to
axes.

import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import matplotlib as mpl
from matplotlib.backends.backend_pdf import PdfPages
import matplotlib.transforms as mtrans
%matplotlib inline
fig = plt.figure()
ax = fig.add_subplot(121,aspect=0.5)
ax.plot(np.linspace(0,100))
ax.set_ylim(0,50)
pbcb = mtrans.Bbox(ax.transLimits.transform([(45,45),(50,50)]))
cbax = fig.add_axes(pbcb)

This has been discussed and the consensus was that getting the heuristics
right is probably impossible (I work with dark-current subtracted image
data so it can have negative values, but using a diverging color map is
_very_ wrong, taking 0 as the center only makes sense some of the time).
Defaulting to a linear norm and sequential color map is in the worst case
not helpful, where as using the wrong center (or incorrectly using a
diverging color map) can be misleading.  We are prioritizing not being
misleading over being slightly more convenient in the core library.

A function with a call signature like you describe should definitely be in
the examples.

Also see PR https://github.com/matplotlib/matplotlib/pull/3858 which is
adding a new normalizer to make setting up non-symmetric diverging color
maps easier.

Tom

On Thu, Jul 2, 2015 at 11:49 AM George Nurser <gn...@gm...> wrote:

> Hi,
> I've been following the discussions about the new default colormaps.
> I think it might be really helpful if the default behaviour were that
> matplotlib simply examined your data (Z, say), and if
> (1) Z.max() & Z.min() had the same sign then used a sequential colormap
> whereas if
> (2) Z.max() & Z.min() had opposite signs then it used a diverging
> colormap, centered on zero.
> Keywords e.g. Anomaly=True  & centre = 10. could be extra arguments to
> override this behaviour.
>
> I realise that
> a) this really only requires a user to write a simple helper application.
>  But 99% of users will never do this.
>
> b) it may not always be desired; but again 99% of the time it probably is.
>
> This would enable people just starting to use matplotlib perhaps to see
> that it can give 'better' plots than matlab
>
> Anyway, just a thought.
>
> George Nurser.
>
>
>
>
>
>
> ------------------------------------------------------------------------------
> Don't Limit Your Business. Reach for the Cloud.
> GigeNET's Cloud Solutions provide you with the tools and support that
> you need to offload your IT needs and focus on growing your business.
> Configured For All Businesses. Start Your Cloud Today.
> https://www.gigenetcloud.com/
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>

Hi,
I've been following the discussions about the new default colormaps.
I think it might be really helpful if the default behaviour were that
matplotlib simply examined your data (Z, say), and if
(1) Z.max() & Z.min() had the same sign then used a sequential colormap
whereas if
(2) Z.max() & Z.min() had opposite signs then it used a diverging colormap,
centered on zero.
Keywords e.g. Anomaly=True  & centre = 10. could be extra arguments to
override this behaviour.

I realise that
a) this really only requires a user to write a simple helper application.
 But 99% of users will never do this.

b) it may not always be desired; but again 99% of the time it probably is.

This would enable people just starting to use matplotlib perhaps to see
that it can give 'better' plots than matlab

Anyway, just a thought.

George Nurser.

You would need to save the artist object that is returned by
drawshapefile() in a list or something. Then, when you want to get rid of
it. you can call its `remove()` method or just do a `set_visible(False)` to
just hide it. This all requires having a reference to the artist object
itself.

Does that help?

Ben Root

On Wed, Jul 1, 2015 at 1:58 PM, Ronquillo, Edgar Nahum <ero...@la...>
wrote:

>  Hello All,
>
>
>
> I am working with Basemap and loading several shapefiles using checkboxes
> in python. However, when I uncheck a checkbox I would like a shapefile to
> be removed and stay with the other shapefiles that are already loaded. I
> tried reloading and replotting the whole thing when I remove a checkbox but
> it will remove all the other shapefiles as well. In simpler words, is it
> possible to remove a shapefile from Basemap after m.readshapefile() has
> been called?
>
>
>
> Thanks in advance
>
>
>
>
>
>
> ------------------------------------------------------------------------------
> Don't Limit Your Business. Reach for the Cloud.
> GigeNET's Cloud Solutions provide you with the tools and support that
> you need to offload your IT needs and focus on growing your business.
> Configured For All Businesses. Start Your Cloud Today.
> https://www.gigenetcloud.com/
> _______________________________________________
> Matplotlib-users mailing list
> Mat...@li...
> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>
>