Answer : B

Explanation

By passing the name of an array as a function argument; the name contains the base address of an array and the base address (array value) get updated in the main function.

Answer : A

Explanation

To open a file in C programming, we can use library function fopen(). In the given above code, fopen() function is opening a file source.txt for reading. Here, r stands for reading. If, fopen() function does not find any file for reading, returns NULL

#include<stdio.h>

int main ()
{
   FILE *fp;
   
   fp = fopen("source.txt", "r");
   return 0;
}

Answer : C

Explanation

In DOS, numbers of byte exist for near pointer = 2,far pointer = 4andhuge pointer = 4.

In Windows and Linux, numbers of byte exist for near pointer = 4,far pointer = 4andhuge pointer = 4.

Answer : A

Explanation

Both functions retrive and store a string from console or file, but fgets() functions are more safer to use then gets() because gets()doesn't facilitate to detail the length of the buffer to store the string in and fgets() facilitates to specify a maximum string length.

   char *fgets(char *s, int size, FILE *stream);
   char *gets(char *s);

Answer : D

Explanation

In C Programming, thescanf()can be used to read a formatted string from thestdinstream, where as; scanf() uses %lf to read a double value and %f to read a floating-point number in fixed decimal format.

int scanf(const char *format, ...)

Answer : B

Explanation

ptr = (data type *)malloc(size);

The given above code is a prototype of malloc() function, where ptr indicates the pointer.

char *p = (char*)malloc(100);

In this code, *p is a pointer of type char and malloc() function allocates the memory for char.

Answer : A

Explanation

In C library, NULL Macrois the value of a null pointer constant. It may be defined as((void*)0), 0or0Ldepending on the compiler merchant.

Answer : B

Explanation

Ptr is an alias to int*.

Answer : A

Explanation

Const charp P;

Although, the code itself indicates the keyword "const", so that; P is a constant.

Answer : C

Explanation

Here, x is an array of three function pointers

#include<stdio.h>

int main ()
{
   typedef char (*(*arrfptr[3])())[10];
   arrfptr x
   return 0;
}

Answer : C

Explanation

va_list ptr is an argument pointer that traverse through the variable arguments passed in the function, where, va_start points 'ptr' to the first argument (IndiaMix). In each call to the va_arg, ptr shift to the next variable argument and after two calls ptr ends up at '7' and return the number '4'.

#include<stdio.h>
#include<stdarg.h>

Void fun(char *msg, ...);
int main ()
{
   fun("IndiaMAX", 1, 4, 7, 11, 0);
   return 0;
}
   void fun(char *msg, ...)  
{
va_list ptr;{
   int num;
   va_start(ptr, msg);
   num = va_arg(ptr, int);    
   num = va_arg(ptr, int);
   printf("%d", num);
}

Answer : D

Explanation

* / % holds highest priority than + - . All with left to right associativity.

Answer : C

Explanation

In C, there are 5 arithmetic operators (+, -, *, /, and %) that can be used in performing arithmetic operations.

Answer : B

Explanation

Double value can be printed using %lf format specifier.

Answer : D

Explanation

The syntax of fclose() function is wrong; it should be int fclose(FILE *stream); closes the stream. Here, fclose(fp, fs, ft); is using separator(,) which returns error by saying that extra parameter in call to fclose() function.

#include<stdio.h>

int main ()
{
   FILE *fs, *ft, *fp;
   
   fp = fopen("ABC", "r");
   fs = fopen("ACD", "r");
   ft = fopen("ADF", "r");
   fclose(fp, fs, ft);
return 0;
}

Answer : A

Explanation

Syntax is exp1?exp2:exp3. Any exp can be a valid expression.

Answer : D

Explanation

Evaluation order is implementation dependent.

Answer : D

Explanation

It is because ++needs a value and aconstvariable cant be modified.

#include<stdio.h>

int main()
{
   const int i = 0;
    
   printf("%d\n", i++);
   return 0;
}

Answer : A

Explanation

Unary operator acts on single expression.

Answer : B

Explanation

As per the operators preference.

Answer : A

Explanation

%f can be use to print outfloat value and %lf can be use to print out double value.

Answer : A

Explanation

%f can be use to print outfloat value and %lf can be use to print out double value.

Answer : A

Explanation

In C, these are the unary operators,

   Logical NOT = !
   Address-of = &
   Cast Operator = ( )
   Pointer dereference = *
   Unary Plus = +
   Increment = ++
   Unary negation = 

Answer : D

Explanation

The above program will return error

#include<stdio.h>

int main()
{
   const int x = 5;
   
   const int *ptrx;
   ptrx = &x;
   *ptrx = 10;
   printf("%d\n", x);
   return 0;
}

Answer : B

Explanation

square parenthesis signify as array at declaration and type is int*, so array of integer pointers.

Answer : D

Explanation

fopen() function is used to open a file and r++ enable the file for reading and writing.

#include<stdio.h>

int main ()
{
   FILE *fp;
   
   fp = fopen("NOTES.TXT", "r+");
   return 0;
}

Answer : A

Explanation

Firstly, int get() which is a get()function prototype returns an integer value without any parameters.

Secondly,const int x = get();The constant variablexis declared as an integer data type and initialized with the value of get(). Hence, the value of get()is 40, printf("%d", x);will print the value of x, that means; 40. So, the program output will be 40.

#include<stdio.h>

int get();

int main()

{
   const int x = get();
   
   printf("%d", x);
   return 0;
}
   int get()
   {
    return 40;
}

Answer : A

Explanation

Preprocessing enlarges and boosts the C programming language by replacing preprocessing directive #include<stdio.h>with the content of the file stdio.h.

Answer : A

Explanation

The C library function strcmp()compares two strings with each other and return the value accordingly.

   int strcmp(const char *str1, const char *str2)

Comparison happens between first string (str1) with second string (str2).

By comparing two strings, the values return by the function strcmp()are,

• If, str1 is less than str2 then Return value < 0
• If, str2 is less than str1 then Return value > 0
• If, str1 is equal to str2 then Return value = 0

Answer : C

Explanation

First the pointer holds Is address and changes later to hold js address. Hence printing the 10 & 20 respectively.

#include<stdio.h>

int fun(int **ptr);

int main()
{
    int i = 10, j = 20;
    const int *ptr = &i;
    
    printf(" i = %5X", ptr);
    printf(" ptr = %d", *ptr);
    ptr = &j;
    printf(" j = %5X", ptr);
    printf(" ptr = %d", *ptr);
    return 0;
}

Answer : A

Explanation

Although, char str[] = "Welcome"; and s = str;, the program will print the value of s.

#include<stdio.h>

int main()
{
   const int *ptr = &i;
   
   char str[] = "Welcome";
   s = str;
   while(*s)
   printf("%c", *s++);
   return 0;
}

Answer : A

Explanation

Option A is the correct answer. In C programming language, "\n" is the escape sequence for printing a new line character. In printf("\\n"); statement, "\\" symbol will be printed as "\" and n will be known as a common symbol.

Answer : A

Explanation

Some time, it becomes necessary to deliver command line values to the C programming to execute the particular code when the code of the program is controlled from outside. Those command line values are called command line arguments. The command line arguments are handled by the main() function.

Declaration of main () with command-line argument is,

int main(int argc, char *argv[])

Where, argc refers to the number of arguments passed, and argv[]is a pointer array which points to each argument passed to the program.

Answer : A

Explanation

Although, integer y = 100; and constant integer x is equal to y. here in the given above program we have to print the x value, so that it will be 100.

Answer : B

Explanation

Strstr() finds the first occurrence of a substring in another string.

Answer : B

Explanation

Here, *s is char pointer that holds character string. To print whole string we use printf("%s",s) by using base address. s contains base address (&s[0]) and printf will print characters until '\0' occurs. *s only gives first character of input string, but s++ will increase the base address by 1 byte. When *s=='\0' encountered, it will terminate loop.

#include<stdio.h>

int xstrlen(char *s)
{
   int length = 0;
   
   while(*s!='\0')
   {length++; s++;}
   return (length);
}
   int main()
{
   char d[] = "IndiaMAX";
    
   printf("Length = %d\n", xstrlen(d));
   return 0;
}

Answer : D

Explanation

The maximum combined length of the command-line arguments and the spaces between adjacent arguments vary from one OS to another.

Answer : D

Explanation

gets (); = Collects a string of characters terminated by a new line from the standard input streamstdin

Answer : D

Explanation

square parenthesis signify as array at declaration and type is char*, so array of character pointers.

Answer : A

Explanation

pf is a pointer as well holds some functions reference.

Answer : A

Explanation

Extern is used to resolve the scope of global identifier.

Answer : D

Explanation

5 1, 4 2- The condition fails when i=j=3.

#include<stdio.h>

main ()

{

   int i, j;

   for(i=5, j=1; i>j; i--, ++j) 

}

Answer : A

Explanation

1 2 2 1, the pointers are swapped not the values.

#include<stdio.h>

main ()

{ 
   int a=1, b=2, *p=&a, *q=&b, *r=p;

   p = q; q = r;

   printf("%d %d %d %d\n",a,b,*p,*q);

}

Answer : A

Explanation

Hello, every line is a valid statement.

#include<stdio.h>

void g(void) { 

}

main ()

{ 
   void (*f)(void);

   f = g;

   f();

}

Answer : C

Explanation

1, the return value is post increment expression as it always receives 1 and returns 1.

#include<stdio.h>

int f(int i) {

}

main ()

{ 

   printf("%d",f(f(f(f(f(1))))));

}

Answer : A

Explanation

0, static variable retains its value between the function calls.

#include<stdio.h>

main ()

{ 
   static int i = 1;

   if(i--) {

   printf("%d ",i);

   main();

  }

}

Answer : B

Explanation

(b), printfs need arguments.

Answer : D

Explanation

(d), It compiles successfully and cant be executed. Use gcc c option to compile the same with command line compiler (UNIX/Linux) or just compile without build in an IDE.

Answer : C

Explanation

Compile error, as the macro is undefined NULL is considered as undeclared.

#include<stdio.h>

main ()

{ 
   int *p = NULL;

   #undef NULL 

   if(p==NULL) printf("NULL"); 

   else printf("Nill");

}

Answer : B

Explanation

Prints date, __DATE__ is a compiler defined macro.