You can use array destructuring to extract individual values from an array and put them in new variables.
let ages = [5, 10, 15, 20, 25],first, second, third, fourth, fifth, sixth;function agesFun(){return ages;}// Example 1[first, second, third] = ages;console.log(first, second, third); // 5, 10, 15// Example 2[first, second, ,fourth] = ages;console.log(first, second, fourth); // 5, 10, 20// Example 3[first, second, ...remaining] = ages;console.log(first, second, remaining); // 5, 10, [15, 20, 25]// Example 4[first, second, third, fourth, fifth, sixth] = ages;console.log(first, second, third, fourth, fifth, sixth); // 5, 10, 15, 20, 25, undefined// Example 5[first, second, third, fourth, fifth, sixth] = ages;console.log(first, second, third, fourth, fifth, sixth = 30); // 5, 10, 15, 20, 25, 30// Example 6[first, second, third, fourth, fifth] = agesFun();console.log(first, second, third, fourth, fifth); // 5, 10, 15, 20, 25
first, second, and third variables are filled with 5, 10, and 15 as values.first, second, fourth variables are filled with 5, 10, 20 as values.first and second variables are filled with 5 and 10 as values, and the rest of the values are filled in the remaining variable [15, 20, 25] as an array.sixth variable is set as undefined because array [5] does not exist.sixth is set to 30.agesFun method returns the array so first to fifth variables are set to 5, 10, 15, 20 and 25.