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BUG: Cannot append to DataFrame with Timestamp column with non-nanosecond unit #55374

@AdrianDAlessandro

Description

@AdrianDAlessandro

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Reproducible Example

import pandas as pd
df = pd.DataFrame({"time": pd.Timestamp(1513393355, unit="us"), "A":[0]}) # Note micro-second unit
df.loc[1] = df.loc[0] # <-- This raises a ValueError for incompatible shapes

Issue Description

Appending a row to a DataFrame with .loc is broken when one of the columns contains a timestamp that has units that are not nanoseconds. Attempting to do so raises a ValueError.

Expected Behavior

The new row should be appended to the DataFrame successfully. The below example works:

import pandas as pd
df = pd.DataFrame({"time": pd.Timestamp(1513393355, unit="ns"), "A":[0]}) # Note nano-second unit
df.loc[1] = df.loc[0]

Installed Versions

INSTALLED VERSIONS

commit : 77bc67a
python : 3.11.1.final.0
python-bits : 64
OS : Darwin
OS-release : 22.6.0
Version : Darwin Kernel Version 22.6.0: Wed Jul 5 22:22:05 PDT 2023; root:xnu-8796.141.3~6/RELEASE_ARM64_T6000
machine : arm64
processor : arm
byteorder : little
LC_ALL : None
LANG : en_US.UTF-8
LOCALE : en_US.UTF-8

pandas : 0+untagged.33100.g77bc67a.dirty
numpy : 1.24.4
pytz : 2023.3
dateutil : 2.8.2
setuptools : 65.5.0
pip : 23.2.1
Cython : 0.29.33
pytest : 7.4.0
hypothesis : 6.82.5
sphinx : 6.2.1
blosc : 1.11.1
feather : None
xlsxwriter : 3.1.2
lxml.etree : 4.9.3
html5lib : 1.1
pymysql : 1.4.6
psycopg2 : 2.9.7
jinja2 : 3.1.2
IPython : 8.14.0
pandas_datareader : None
bs4 : 4.12.2
bottleneck : 1.3.7
dataframe-api-compat: None
fastparquet : 2023.7.0
fsspec : 2023.6.0
gcsfs : 2023.6.0
matplotlib : 3.7.2
numba : 0.57.1
numexpr : 2.8.5
odfpy : None
openpyxl : 3.1.2
pandas_gbq : None
pyarrow : 12.0.1
pyreadstat : 1.2.2
python-calamine : None
pyxlsb : 1.0.10
s3fs : 2023.6.0
scipy : 1.11.2
sqlalchemy : 2.0.20
tables : None
tabulate : 0.9.0
xarray : 2023.7.0
xlrd : 2.0.1
zstandard : 0.21.0
tzdata : 2023.3
qtpy : None
pyqt5 : None

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BugNon-Nanodatetime64/timedelta64 with non-nanosecond resolution

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