package com.leetcode.arrays; import java.util.Arrays; import java.util.Comparator; /** * Level: Medium * Problem Link: https://leetcode.com/problems/merge-intervals/ * Problem Description: *
* Given a collection of intervals, merge all overlapping intervals. *
* Example 1: * Input: [[1,3],[2,6],[8,10],[15,18]] * Output: [[1,6],[8,10],[15,18]] * Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. *
* Example 2: * Input: [[1,4],[4,5]] * Output: [[1,5]] * Explanation: Intervals [1,4] and [4,5] are considered overlapping. *
* Companies: LinkedIn
* Related: {@link InsertInterval}.
*
* @author rampatra
* @since 2019-07-22
*/
public class MergeIntervals {
/**
* Time complexity: O(n log n)
* Space complexity: O(n)
* Runtime: 6 ms
*
* @param intervals a list of intervals, may not be sorted
* @return a list of intervals, with overlapping intervals merged
*/
public static int[][] merge(int[][] intervals) {
// some validations
if (intervals.length == 0) return new int[0][2];
// we first sort the intervals based on their start times
Arrays.sort(intervals, new IntervalComparator());
int[][] mergedIntervals = new int[intervals.length][2];
int lastMergedIndex = 0;
mergedIntervals[lastMergedIndex] = intervals[0];
for (int i = 1; i < intervals.length; i++) {
if (isOverlap(mergedIntervals[lastMergedIndex], intervals[i])) {
// if two intervals overlap, then merge the two
mergedIntervals[lastMergedIndex] = new int[]{Math.min(mergedIntervals[lastMergedIndex][0], intervals[i][0]),
Math.max(mergedIntervals[lastMergedIndex][1], intervals[i][1])};
} else {
mergedIntervals[++lastMergedIndex] = intervals[i];
}
}
return Arrays.copyOfRange(mergedIntervals, 0, lastMergedIndex + 1);
}
private static boolean isOverlap(int[] interval1, int[] interval2) {
return interval1[0] <= interval2[0] && interval1[1] >= interval2[0];
}
private static class IntervalComparator implements Comparator