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            "categoryTitle": "JavaScript",
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            "title": "Array Wrapper",
            "titleSlug": "array-wrapper",
            "content": "<p>Create a class&nbsp;<code>ArrayWrapper</code> that accepts&nbsp;an array of integers in its constructor. This class should have two features:</p>\n\n<ul>\n\t<li>When two instances of this class are added together with the&nbsp;<code>+</code>&nbsp;operator, the resulting value is the sum of all the elements in&nbsp;both arrays.</li>\n\t<li>When the&nbsp;<code>String()</code>&nbsp;function is called on the instance, it will return a comma separated string surrounded by brackets. For example, <code>[1,2,3]</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [[1,2],[3,4]], operation = &quot;Add&quot;\n<strong>Output:</strong> 10\n<strong>Explanation:</strong>\nconst obj1 = new ArrayWrapper([1,2]);\nconst obj2 = new ArrayWrapper([3,4]);\nobj1 + obj2; // 10\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [[23,98,42,70]], operation = &quot;String&quot;\n<strong>Output:</strong> &quot;[23,98,42,70]&quot;\n<strong>Explanation:</strong>\nconst obj = new ArrayWrapper([23,98,42,70]);\nString(obj); // &quot;[23,98,42,70]&quot;\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [[],[]], operation = &quot;Add&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nconst obj1 = new ArrayWrapper([]);\nconst obj2 = new ArrayWrapper([]);\nobj1 + obj2; // 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i]&nbsp;&lt;= 1000</code></li>\n\t<li><code>Note: nums is the array passed to the constructor</code></li>\n</ul>\n",
            "translatedTitle": "包装数组",
            "translatedContent": "<p>创建一个名为 <code>ArrayWrapper</code> 的类，它在其构造函数中接受一个整数数组作为参数。该类应具有以下两个特性：</p>\n\n<ul>\n\t<li>当使用 <code>+</code> 运算符将两个该类的实例相加时，结果值为两个数组中所有元素的总和。</li>\n\t<li>当在实例上调用 <code>String()</code> 函数时，它将返回一个由逗号分隔的括在方括号中的字符串。例如，<code>[1,2,3]</code> 。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [[1,2],[3,4]], operation = \"Add\"\n<b>输出：</b>10\n<b>解释：</b>\nconst obj1 = new ArrayWrapper([1,2]);\nconst obj2 = new ArrayWrapper([3,4]);\nobj1 + obj2; // 10\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [[23,98,42,70]], operation = \"String\"\n<b>输出：</b>\"[23,98,42,70]\"\n<strong>解释：</strong>\nconst obj = new ArrayWrapper([23,98,42,70]);\nString(obj); // \"[23,98,42,70]\"\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [[],[]], operation = \"Add\"\n<b>输出：</b>0\n<strong>解释：</strong>\nconst obj1 = new ArrayWrapper([]);\nconst obj2 = new ArrayWrapper([]);\nobj1 + obj2; // 0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i]&nbsp;&lt;= 1000</code></li>\n\t<li><code>注意：nums 是传递给构造函数的数组。</code></li>\n</ul>\n",
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                    "code": "/**\n * @param {number[]} nums\n * @return {void}\n */\nvar ArrayWrapper = function(nums) {\n    \n};\n\n/**\n * @return {number}\n */\nArrayWrapper.prototype.valueOf = function() {\n    \n}\n\n/**\n * @return {string}\n */\nArrayWrapper.prototype.toString = function() {\n    \n}\n\n/**\n * const obj1 = new ArrayWrapper([1,2]);\n * const obj2 = new ArrayWrapper([3,4]);\n * obj1 + obj2; // 10\n * String(obj1); // \"[1,2]\"\n * String(obj2); // \"[3,4]\"\n */",
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