Python Pandas - Form the intersection of two Index objects and sort the result

To form the intersection of two Index objects, use the index1.intersection(index2) method in Pandas. To sort the result, use the sort parameter.

At first, import the required libraries −

import pandas as pd

Creating Pandas index1 and index2 −

index1 = pd.Index([4, 3, 2, 1])
index2 = pd.Index([8, 2, 6, 4])

Display the Pandas index1 and index2

print("Pandas Index1...\n",index1)
print("Pandas Index2...\n",index2)

Perform intersection. The results are sorted using the "sort" parameter

res = index1.intersection(index2, sort=None)

Example

Following is the code −

import pandas as pd

# Creating Pandas index1 and index2
index1 = pd.Index([4, 3, 2, 1])
index2 = pd.Index([8, 2, 6, 4])

# Display the Pandas index1 and index2
print("Pandas Index1...\n",index1)
print("Pandas Index2...\n",index2)

# Return the number of elements in Index1 and Index2
print("\nNumber of elements in index1...\n",index1.size)
print("\nNumber of elements in index2...\n",index2.size)

# Perform intersection
# The results are sorted using the "sort" parameter
res = index1.intersection(index2, sort=None)

# Intersection of both the indexes and returning sorted result
print("\nThe index1 and index2 intersection (sorted result)...\n",res)

Output

This will produce the following output −

Pandas Index1...
Int64Index([4, 3, 2, 1], dtype='int64')
Pandas Index2...
Int64Index([8, 2, 6, 4], dtype='int64')

Number of elements in index1...
4

Number of elements in index2...
4

The index1 and index2 intersection (sorted result)...
Int64Index([2, 4], dtype='int64')