To return vector of label values using level name in the MultiIndex, use the MultiIndex.get_level_values() method in Pandas.
At first, import the required libraries −
import pandas as pd
MultiIndex is a multi-level, or hierarchical, index object for pandas objects −
multiIndex = pd.MultiIndex.from_arrays([list('pqrrss'), list('strvwx')],names=['One', 'Two'])Display the MultiIndex −
print("The MultiIndex...\n",multiIndex)
Get level values using level name "Two" −
print("\nLevel values using level name...\n",multiIndex.get_level_values("Two"))Example
Following is the code −
import pandas as pd
# MultiIndex is a multi-level, or hierarchical, index object for pandas objects
multiIndex = pd.MultiIndex.from_arrays([list('pqrrss'), list('strvwx')],names=['One', 'Two'])
# display the MultiIndex
print("The MultiIndex...\n",multiIndex)
# get the levels in MultiIndex
print("\nThe levels in MultiIndex...\n",multiIndex.levels)
# get level values using level name "Two"
print("\nLevel values using level name...\n",multiIndex.get_level_values("Two"))Output
This will produce the following output −
The MultiIndex...
MultiIndex([('p', 's'),
('q', 't'),
('r', 'r'),
('r', 'v'),
('s', 'w'),
('s', 'x')],
names=['One', 'Two'])
The levels in MultiIndex...
[['p', 'q', 'r', 's'], ['r', 's', 't', 'v', 'w', 'x']]
Level values using level name...
Index(['s', 't', 'r', 'v', 'w', 'x'], dtype='object', name='Two')