One list is given with duplicate element, our task is create another list which contains the element of without duplicates.
Example
A::[2,3,4,3,4,6,78,90] Output::[2,3,4,6,78,90]
Algorithm
Step 1: create a list. Step 2: create a new list which is empty. Step 3: traverse every element in list. Step 4: if element is not present in the list return true. Step 5: append in the new list. Step 6: display new list.
Example Code
# To remove duplicate elements
defremoveduplicateele(A):
newlist = []
for n in A:
if n not in newlist:
newlist.append(n)
returnnewlist
# Driver Code
A=list()
n=int(input("Enter the size of the List ::"))
print("Enter the number ::")
fori in range(int(n)):
k=int(input(""))
A.append(int(k))
print("THE NEW LIST IS ::>",removeduplicateele(A))
output
Enter the size of the List ::5 Enter the number :: 10 20 30 20 10 THE LIST IS ::> [10, 20, 30]