In this article, we will learn about the solution to the problem statement given below.
Problem statement − We are given an integer n, we need to count the number of trailing zeros in the factorial.
Now let’s observe the solution in the implementation below −
Example
# trailing zero
def find(n):
# Initialize count
count = 0
# update Count
i = 5
while (n / i>= 1):
count += int(n / i)
i *= 5
return int(count)
# Driver program
n = 79
print("Count of trailing 0s "+"in",n,"! is", find(n))Output
Count of trailing 0s in 79 ! is 18

Conclusion
In this article, we have learned about how we can make a Python Program to Count trailing zeroes in factorial of a number