Suppose we have a lowercase string s, we have to find how many "pizza" strings we can make using the characters present in s. We can use the characters in s in any order, but each character can be used once.
So, if the input is like "ihzapezlzzilaop", then the output will be 2.
To solve this, we will follow these steps −
- p_freq := Frequency of 'p' in s
- i_freq := Frequency of 'i' in s
- z_freq := Frequency of 'z' in s
- a_freq := Frequency of 'a' in s
- return minimum of (p_freq, i_freq, z_freq/2 and a_freq)
Let us see the following implementation to get better understanding −
Example
class Solution:
def solve(self, s):
p_freq = s.count('p')
i_freq = s.count('i')
z_freq = s.count('z')
a_freq = s.count('a')
return min(p_freq, i_freq, z_freq // 2, a_freq)
ob = Solution()
print(ob.solve("ihzapezlzzilaop"))Input
"ihzapezlzzilaop"
Output
2