Let’s say following is our array −
var numbers=[10,50,80,60,89];
To find the second largest element, the code is as follows −
Example
var numbers=[10,50,80,60,89];
var firstLargerNumber = Number.MIN_SAFE_INTEGER;
var secondlargerNumber = firstLargerNumber;
for(var tempNumber of numbers){
if(tempNumber > firstLargerNumber){
secondlargerNumber = firstLargerNumber;
firstLargerNumber = tempNumber;
}
else if(tempNumber > secondlargerNumber){
secondlargerNumber = tempNumber;
}
}
console.log("The second largest number="+secondlargerNumber);To run the above program, you need to use the following command −
node fileName.js.
Here, my file name is demo138.js.
Output
This will produce the following output −
PS C:\Users\Amit\JavaScript-code> node demo138.js The second largest number=80