C# Program to get the first three elements from a list

Use the Take() method to get the first individual number of elements in C#.

Firstly, set a list and add elements −

List<string> myList = new List<string>();
myList.Add("One");
myList.Add("Two");
myList.Add("Three");
myList.Add("Four");
myList.Add("Five");
myList.Add("Six");

Now, use the Take() method to get the elements from the list. Add the number of the elements you want as an argument −

myList.Take(3)

Here is the code −

Example

using System;
using System.Linq;
using System.Collections.Generic;
public class Demo {
   public static void Main() {
      List<string> myList = new List<string>();
      myList.Add("One");
      myList.Add("Two");
      myList.Add("Three");
      myList.Add("Four");
      myList.Add("Five");
      myList.Add("Six");
      // first three elements
      var res = myList.Take(3);
      // displaying the first three elements
      foreach (string str in res) {
         Console.WriteLine(str);
      }
   }
}

Output

One
Two
Three