Suppose we have two numbers K and X. Consider Amal has K, 500 rupee notes. We have to check whether the sums up to X rupees or not.
So, if the input is like K = 2; X = 900, then the output will be True, because 2*500 = 1000 and it is not less than 900.
Steps
To solve this, we will follow these steps −
if (500 * k) >= x, then: return true Otherwise return false
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
bool solve(int k, int x){
if ((500 * k) >= x){
return true;
} else{
return false;
}
}
int main(){
int K = 2;
int X = 900;
cout << solve(K, X) << endl;
}Input
2, 900
Output
1