Sum of array using pointer arithmetic

Last Updated : 21 Sep, 2022

Given an array, write a program to find the sum of array using pointers arithmetic. In this program we make use of * operator . The * (asterisk) operator denotes the value of variable. The * operator at the time of declaration denotes that this is a pointer, otherwise it denotes the value of the memory location pointed by the pointer . sum() function is used to find the sum of the array through pointers.

Examples :

Input : array = 2, 4, -6, 5, 8, -1
Output : sum = 12

Input : array = 1, 4, -6, 8, -10, -12
Output : sum = -15

CPP

// CPP program to find sum of array using pointers 
#include <iostream> 
using namespace std; 

// Function to find the sum of the array 
void sum(int* array, int length) 
{ 
    int i, sum_of_array = 0; 
    for (i = 0; i < length; i++) 
        sum_of_array = sum_of_array + *(array + i); 
    cout << "sum of array is = " << sum_of_array; 
} 
// Driver function 
int main() 
{ 
    // Array to hold the values 
    int array[] = { 2, 4, -6, 5, 8, -1 }; 
    sum(array, 6); 
    return 0; 
}

Output

sum of array is = 12

Time Complexity: O(N)
Auxiliary Space: O(1)

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