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Running from command line (not ipython), is there some way to add a plot and 
update display without blocking?  I have an algorithm that should iteratively 
converge.  I'd like to draw the result (a plot) after N iterations, continue 
computing, then draw after 2N, etc.  Retaining the previous plots.

Also, what if I wanted to erase previous plots?

You may use a proxy artist.

http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist

for example,

from matplotlib.lines import Line2D
l1 = Line2D([], [], linewidth=3, color="r")
l2 = Line2D([], [], linewidth=3, color="g")
l3 = Line2D([], [], linewidth=3, color="b")

legend([l1, l2, l3], ["label 1", "label 2", "label 3"])

Regards,

-JJ

On Wed, Aug 17, 2011 at 1:24 AM, Ravi Kanth Vanapalli
<vvn...@gm...> wrote:
> Hi ,
>
> I wish to add a custom legend to a multicolored line drawn using matplotlib
> as shown in the figure below
> http://www.scipy.org/Cookbook/Matplotlib/MulticoloredLine
> I tried exploring the legend but somehow couldn't figure out its usage and
> how to adapt it to multicolored line as in the above link
> I need to use say Red line  for label1 and blue line for label2 and green
> line for label3. All the three colors are a part of a single sinusoidal wave
> as in the above link.
> Any thoughts/ideas/suggestions which could provide me some direction on this
> would be highly appreciated.
>
> --
> Thanks and Regards,
> RaviKanth
>
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On Thu, Aug 18, 2011 at 5:53 PM, mogliii <mo...@gm...> wrote:
> 2) I want to make a shared y-axis label. I found this page:
> http://www.scipy.org/Cookbook/Matplotlib/Multiple_Subplots_with_One_Axis_Label
> But any additional axis I put before the gridspec axis is not shown in
> the end. Is there a special procedure that can be used together with
> gridspec?

This is general behavior of subplot command.

http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.subplot

If you want to suppress this, do something like

  fig.add_subplot(gs[0])

Regards,

-JJ

Can you post an simple self-contained script that reproduces your problem?
I just tried something similar but could not reproduces your problem.
Here is what I did,
Also, what version of matplotlb are you using?

Regards,

-JJ

import matplotlib.pyplot as plt
import numpy as np

from mpl_toolkits.axes_grid1 import ImageGrid

fig = plt.figure(1)

arr = np.arange(100).reshape((10, 10))

grid = ImageGrid(fig, 111, (2, 2))


cntr0 = grid[0].contour(arr)
cntr1 = grid[1].contour(arr)
cntr2 = grid[2].contour(arr)
cntr3 = grid[3].contour(arr)

plt.clabel(cntr0, manual=True)
plt.clabel(cntr1, manual=True)
plt.clabel(cntr2, manual=True)
plt.clabel(cntr3, manual=True)



On Thu, Aug 18, 2011 at 1:10 PM, R. O'Gara <ron...@ya...> wrote:
> Hey guys,
>
>
> I was hoping someone could provide a hint for how I should go about correcting this. As you can see, locations for the inline labels for
> contours in this image are unfortunately chosen, and they overlap with one another. If I set manual to 'True' then I get this weird behavior
> where I can only choose labels in the top left grid and nothing is shownin any of the other grids.
>
> I am using a 2x2 Image Grid (I get the same problem when using gridspec instead of image grid), and loadingcontour data (2x2 array) from a file.
>
> Thanks for your help,
> Ron
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If you don't care about the aspect ratio at all, you can use
aspect="auto".  Check the thread below.

http://old.nabble.com/Re%3A-Can-I-change-pixel-aspect-with-axes_grid-p32300471.html

Regards,

-JJ


On Sat, Aug 13, 2011 at 5:01 AM, R. O'Gara <ron...@ya...> wrote:
> Hi,
> From the attached figure, you can see that the plots I am trying to show in
> the bottom two "quadrants", are too narrow. That is because the y-axis of
> those two plots is meant to be in the 0-1 range, i.e. much smaller than
> y-axis in the upper two, so the height of the bottom grid boxes is tiny. How
> can I force the heights of all boxes to be the same?
> Much appreciated,
> Ron
>
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