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From: Goyo <goy...@gm...> - 2011-04-23 23:01:15
|
2011/4/23 _olivier_ <ol...@gm...>: > [...] > I have got a matrix 6x500 (so one size is much biggger than the other one) > and I try to expand the shorter axe so that the labels on it are well > displayed (not overlapped. Use the aspect kwarg in matshow. Goyo |
From: _olivier_ <ol...@gm...> - 2011-04-23 21:07:22
|
Not sure this message was sent successfully. So I send it again. Sorry if you receive it twice... Hello, This question has certainly been answered in a previous thread but after searching around I did not find any solution... I have got a matrix 6x500 (so one size is much biggger than the other one) and I try to expand the shorter axe so that the labels on it are well displayed (not overlapped. I am googling/searching on the documentation about subplots_adjust, ... but did not find any solution. Here is the code that present the problem I have. Thanks in advance for any help. Olivier import numpy as np from matplotlib.pylab import * import matplotlib.pyplot as plt sizeX = 6 sizeY = 500 xlabels = [] ylabels = [] for i in range ( 0, sizeX ): xlabels.append( str( i ) ) for i in range ( 0, sizeY ): ylabels.append( str( i ) ) dims = ( sizeX, sizeY ) data = zeros( dims ) for i in range( 0, sizeX ): for j in range( 0, sizeY ): data[ i, j ] = np.random.rand() figure = plt.figure() axes = figure.add_subplot( 111 ) cax = axes.matshow( data, interpolation = 'nearest' ) col = figure.colorbar( cax ) plt.show() -- View this message in context: http://old.nabble.com/Try-to-have-none-overlapping-labels-in-one-axe-using-matshow-tp31456159p31456159.html Sent from the matplotlib - users mailing list archive at Nabble.com. |
From: Goyo <goy...@gm...> - 2011-04-23 12:42:13
|
2011/4/23 jfortiv <jf...@gm...>: > > Hi, > > This actually did not work for me. Can you show me the full code that you > used to successfully produce the time-format x-axis labels? See attached files. Goyo |
From: jfortiv <jf...@gm...> - 2011-04-23 08:48:24
|
Hi, This actually did not work for me. Can you show me the full code that you used to successfully produce the time-format x-axis labels? Thanks, James Sebastian Berg wrote: > > Hello, > > don't know the foo behind it, but using > ax.xaxis.set_major_formatter(mdates.DateFormatter('%Y-%m-%d %H:%M:%S')) > works. > > Regards, > > Sebastian > > On Sun, 2011-04-17 at 19:52 -0700, jfortiv wrote: > >> Hello, >> >> I'm trying to create a bar chart that looks something like a gannt >> chart... >> >> See the simple example here: >> >> http://www.promana.net/making-use-of-gantt-charts/ >> >> I'm trying to utilize barh() and fmt_xdata to accomplish this with the >> following: >> >> #~~~~~~~~~~~~~~~~~~~~~~~ >> >> date1 = datetime.datetime( 2000, 3, 2) >> date2 = datetime.datetime( 2000, 3, 6) >> delta = datetime.timedelta(hours=6) >> dates = mdates.drange(date1, date2, delta) >> >> val = mdates.drange(date1,date2,delta) # the bar lengths >> pos = range(len(val)) # the bar centers on the y axis >> height=0.5 # the bar height >> left=mdates.drange(date1,date2,delta) # the bar starting position >> >> fig = plt.figure() >> ax = fig.add_subplot(111) >> ax.barh(pos,val,height=height,left=left,align='center',alpha=0.3) >> ax.fmt_xdata = mdates.DateFormatter('%Y-%m-%d %H:%M:%S') >> >> #~~~~~~~~~~~~~~~~~~~~~~~ >> >> >> Even with ax.fmt_xdata, I'm simply getting numbers on the x-axis instead >> of >> dates. Can anyone offer some pointers? >> >> Thanks, >> James > > > > ------------------------------------------------------------------------------ > Benefiting from Server Virtualization: Beyond Initial Workload > Consolidation -- Increasing the use of server virtualization is a top > priority.Virtualization can reduce costs, simplify management, and improve > application availability and disaster protection. Learn more about > boosting > the value of server virtualization. http://p.sf.net/sfu/vmware-sfdev2dev > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > -- View this message in context: http://old.nabble.com/Date-format-the-x-axis-of-a-barh%28%29-plot--tp31420395p31460691.html Sent from the matplotlib - users mailing list archive at Nabble.com. |
From: Paul I. <piv...@gm...> - 2011-04-23 01:19:17
|
Hi Xavier, Xavier Gnata, on 2011-04-23 02:33, wrote: > Imagine you have this code: > > import numpy as np > import matplotlib.cm as cm > import matplotlib.mlab as mlab > import matplotlib.pyplot as plt > > delta = 0.25 > x = y = np.arange(-3.0, 3.0, delta) > X, Y = np.meshgrid(x, y) > Z1 = mlab.bivariate_normal(X, Y, 1.0, 1.0, 0.0, 0.0) > Z2 = mlab.bivariate_normal(X, Y, 1.5, 0.5, 1, 1) > Z = Z2-Z1 # difference of Gaussians > > plt.imshow(Z, interpolation='nearest', cmap=cm.gray, origin='lower', extent=[-3,3,-3,3]) > Then you want to change the color of a few pixels to red. > You have a list of coordinates (i,j) and each pixel in this list should > now be red. > > I could play with masked arrays like in: > http://matplotlib.sourceforge.net/examples/pylab_examples/image_masked.html > but I would prefer a simple "display this pixel (i,j) in red whatever > his value is" function. Since you're using a gray color map for that image, you won't be able to set a particular pixel to red. You'll have to either overlay a new image that would be masked out everywhere except for the pixels you want to change, as you mentioned, or create new image patches at the corresponding positions like this: idx2im = lambda i,j: (x[i],x[j+1],y[i],y[j+1] ) plt.imshow([[.9]], extent=idx2im(12,12), cmap =cm.jet, origin='lower',vmin=0,vmax=1) or something like this: plt.Rectangle((x[10],y[10]),width=delta,height=delta,color='red') ax = plt.gca() ax.add_artist(r) plt.draw() best, -- Paul Ivanov 314 address only used for lists, off-list direct email at: http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7 |
From: Xavier G. <xav...@gm...> - 2011-04-23 00:33:29
|
Hi, Imagine you have this code: import numpy as np import matplotlib.cm as cm import matplotlib.mlab as mlab import matplotlib.pyplot as plt delta = 0.25 x = y = np.arange(-3.0, 3.0, delta) X, Y = np.meshgrid(x, y) Z1 = mlab.bivariate_normal(X, Y, 1.0, 1.0, 0.0, 0.0) Z2 = mlab.bivariate_normal(X, Y, 1.5, 0.5, 1, 1) Z = Z2-Z1 # difference of Gaussians plt.imshow(Z, interpolation='nearest', cmap=cm.gray, origin='lower', extent=[-3,3,-3,3]) Then you want to change the color of a few pixels to red. You have a list of coordinates (i,j) and each pixel in this list should now be red. I could play with masked arrays like in: http://matplotlib.sourceforge.net/examples/pylab_examples/image_masked.html but I would prefer a simple "display this pixel (i,j) in red whatever his value is" function. Xavier |