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I'm using matplotlib from pylab to generate eye patterns for signal
simulations. My output pretty much looks like this:

http://www.flickr.com/photos/31208937@N06/6079131690/

Its pretty useful as it allows one to quickly see the size of the eye
opening, the maximum/minimum voltage, etc. I'd really like to be able
to create a heat diagram, like these:

http://www.lecroy.com/images/oscilloscope/series/waveexpert/opening-spread2_lg.jpg
http://www.lecroy.com/images/oscilloscope/series/waveexpert/opening-spread1_lg.jpg
http://www.iec.org/newsletter/august07_2/imgs/bb2_fig_1.gif
http://www.altera.com/devices/fpga/stratix-fpgas/stratix-ii/stratix-ii-gx/images/s2gx-rollout-6g-eye.jpg

Is there any way within matplotlib to do that right now?

Στις 21/01/2012 07:05 μμ, ο/η Tony Yu έγραψε:
>
>
> On Sat, Jan 21, 2012 at 11:31 AM, Gousios George 
> <gg...@wi... <mailto:gg...@wi...>> wrote:
>
>     Στις 21/01/2012 04:54 μμ, ο/η Tony Yu έγραψε:
>>
>>
>>     On Sat, Jan 21, 2012 at 9:07 AM, Gousios George
>>     <gg...@wi... <mailto:gg...@wi...>> wrote:
>>
>>         Hello , i have the following code in matlab and trying to do
>>         it in
>>         matplotlib.
>>
>>         I have this code in matlab (in a function showGraphs):
>>         ...
>>         m = size(myList, 3);
>>         for k = 1:m
>>             g = myList(:, :, k);
>>             image(g + 1)
>>             axis off
>>             axis square
>>             M(k) = getframe;
>>         end;
>>
>>         and in another file (another function):
>>         ...
>>         M = showGraphs(grids)
>>         movie(M, 1)
>>
>>
>>
>>         I did so far:
>>
>>         def showGraphs(data):
>>             data=sc.array([data])
>>             n=sc.shape(data)[2]
>>             for k in range(n):
>>                 mydata=data[:,:,k]
>>                 #plt.imshow(mydata+1)    -->> this doesn't work
>>
>>         Also ,in order to do the animation :
>>
>>         grids=...(result from another function)
>>         result=showGraph(grids)
>>         fig=plt.figure()
>>         ani=animation.FuncAnimation(fig,result,interval=30,blit=True)
>>         plt.show()
>>
>>         Right now the program says "TypeError: 'NoneType' object is not
>>         callable" (it has errors in the animation call)
>>
>>         What should be my approach to this in order to have the
>>         animation?
>>
>>         Thank you!
>>
>>
>>     You're getting that error because the second argument to
>>     FuncAnimation (`result` in your example) should be a function
>>     (not always; see example 2 linked below). Right now, if your
>>     `showGraphs` function is defined in full, it returns a value of
>>     None, which gets saved to `result` (hence the error).
>>
>>     You should take a look at some of the image animation examples
>>     (ex1
>>     <http://matplotlib.sourceforge.net/examples/animation/dynamic_image.html>,
>>     ex2
>>     <http://matplotlib.sourceforge.net/examples/animation/dynamic_image2.html>).
>>
>>     -Tony
>>
>
>     I did now :
>
>
>     def showGraphs(data):
>         data=sc.array([data])
>         n=sc.shape(data)[2]
>         ims=[]
>
>         for k in range(n):
>             mydata=data[:,:,k]
>             im=plt.imshow(mydata+1)
>             ims.append([im])
>         return ims
>
>     and now it gives me "TypeError: Invalid dimensions for image data.
>
>
> Please post short, but executable examples when possible. I'm not sure 
> what your data looks like, but your call to `sc.array` is strange (I'm 
> not sure why you have square brackets, which effectively adds an 
> unnecessary dimension to your data).
>
> The code attached below should work.
>
> Cheers,
> -Tony
>
> import numpy as np
> import matplotlib.pyplot as plt
> from matplotlib.animation import ArtistAnimation
>
>
> fig = plt.figure()
>
> def showGraphs(data):
>     data = np.asarray(data) # unnecessary in this example
>     n = np.shape(data)[2]
>
>     ims = []
>     #for mydata in np.rollaxis(data, -1):
>     for k in range(n):
>         mydata = data[:, :, k]
>         im = plt.imshow(mydata)
>         ims.append([im])
>     return ims
>
> # 5 frames of a random 20 x 20 image
> data = np.random.uniform(size=(20, 20, 5))
> ims = showGraphs(data)
>
> ani = ArtistAnimation(fig, ims)
> plt.show()
Now,it gives me 2 figures (why 2?) but empty.(maybe i didn't convert 
right the matlab code below?)
The data in the showGraphs function is the result from this function (in 
matlab):
.........
grids = zeros(n, n, t + 1);
grids(:, :, 1) = rest;
for i = 2:(t + 1)
     Extended = extendLat1(rest);
     rest = applyExtended(Extended);
     grids(:, :, i) = rest;
end;

And i did this in python:

    grids=sc.zeros((area,area,t+1))
     rest=grids[:,:,0]
     for i in range(1,t):
         extended=extend(rest)
         rest=apply_extend(extended)
         grids[:,:,i]=rest
     return grids

Thanks for helping!

Please post a binary .dmg or .egg file for matplotlib for OSX 10.6 and
Python 2.7.

There doesn't appear to be one on the downloads page; the closest I
could find for anything under OSX 10.6 was
http://sourceforge.net/projects/matplotlib/files/matplotlib/matplotlib-0.99.3/
which only includes Python 2.6 support.

On Sat, Jan 21, 2012 at 11:31 AM, Gousios George <gg...@wi...>wrote:

> **
> Στις 21/01/2012 04:54 μμ, ο/η Tony Yu έγραψε:
>
>
>
> On Sat, Jan 21, 2012 at 9:07 AM, Gousios George <gg...@wi...>wrote:
>
>> Hello , i have the following code in matlab and trying to do it in
>> matplotlib.
>>
>> I have this code in matlab (in a function showGraphs):
>> ...
>> m = size(myList, 3);
>> for k = 1:m
>>     g = myList(:, :, k);
>>     image(g + 1)
>>     axis off
>>     axis square
>>     M(k) = getframe;
>> end;
>>
>> and in another file (another function):
>> ...
>> M = showGraphs(grids)
>> movie(M, 1)
>>
>>
>>
>> I did so far:
>>
>> def showGraphs(data):
>>     data=sc.array([data])
>>     n=sc.shape(data)[2]
>>     for k in range(n):
>>         mydata=data[:,:,k]
>>         #plt.imshow(mydata+1)    -->> this doesn't work
>>
>> Also ,in order to do the animation :
>>
>> grids=...(result from another function)
>> result=showGraph(grids)
>> fig=plt.figure()
>> ani=animation.FuncAnimation(fig,result,interval=30,blit=True)
>> plt.show()
>>
>> Right now the program says "TypeError: 'NoneType' object is not
>> callable" (it has errors in the animation call)
>>
>> What should be my approach to this in order to have the animation?
>>
>> Thank you!
>>
>>
> You're getting that error because the second argument to FuncAnimation
> (`result` in your example) should be a function (not always; see example 2
> linked below). Right now, if your `showGraphs` function is defined in full,
> it returns a value of None, which gets saved to `result` (hence the error).
>
> You should take a look at some of the image animation examples (ex1<http://matplotlib.sourceforge.net/examples/animation/dynamic_image.html>,
> ex2<http://matplotlib.sourceforge.net/examples/animation/dynamic_image2.html>
> ).
>
> -Tony
>
>
> I did now :
>
>
> def showGraphs(data):
>     data=sc.array([data])
>     n=sc.shape(data)[2]
>     ims=[]
>
>     for k in range(n):
>         mydata=data[:,:,k]
>         im=plt.imshow(mydata+1)
>         ims.append([im])
>     return ims
>
> and now it gives me "TypeError: Invalid dimensions for image data.
>
>
Please post short, but executable examples when possible. I'm not sure what
your data looks like, but your call to `sc.array` is strange (I'm not sure
why you have square brackets, which effectively adds an unnecessary
dimension to your data).

The code attached below should work.

Cheers,
-Tony

import numpy as np
import matplotlib.pyplot as plt
from matplotlib.animation import ArtistAnimation


fig = plt.figure()

def showGraphs(data):
    data = np.asarray(data) # unnecessary in this example
    n = np.shape(data)[2]

    ims = []
    #for mydata in np.rollaxis(data, -1):
    for k in range(n):
        mydata = data[:, :, k]
        im = plt.imshow(mydata)
        ims.append([im])
    return ims

# 5 frames of a random 20 x 20 image
data = np.random.uniform(size=(20, 20, 5))
ims = showGraphs(data)

ani = ArtistAnimation(fig, ims)
plt.show()

???? 21/01/2012 04:54 ??, ?/? Tony Yu ??????:
>
>
> On Sat, Jan 21, 2012 at 9:07 AM, Gousios George <gg...@wi... 
> <mailto:gg...@wi...>> wrote:
>
>     Hello , i have the following code in matlab and trying to do it in
>     matplotlib.
>
>     I have this code in matlab (in a function showGraphs):
>     ...
>     m = size(myList, 3);
>     for k = 1:m
>         g = myList(:, :, k);
>         image(g + 1)
>         axis off
>         axis square
>         M(k) = getframe;
>     end;
>
>     and in another file (another function):
>     ...
>     M = showGraphs(grids)
>     movie(M, 1)
>
>
>
>     I did so far:
>
>     def showGraphs(data):
>         data=sc.array([data])
>         n=sc.shape(data)[2]
>         for k in range(n):
>             mydata=data[:,:,k]
>             #plt.imshow(mydata+1)    -->> this doesn't work
>
>     Also ,in order to do the animation :
>
>     grids=...(result from another function)
>     result=showGraph(grids)
>     fig=plt.figure()
>     ani=animation.FuncAnimation(fig,result,interval=30,blit=True)
>     plt.show()
>
>     Right now the program says "TypeError: 'NoneType' object is not
>     callable" (it has errors in the animation call)
>
>     What should be my approach to this in order to have the animation?
>
>     Thank you!
>
>
> You're getting that error because the second argument to FuncAnimation 
> (`result` in your example) should be a function (not always; see 
> example 2 linked below). Right now, if your `showGraphs` function is 
> defined in full, it returns a value of None, which gets saved to 
> `result` (hence the error).
>
> You should take a look at some of the image animation examples (ex1 
> <http://matplotlib.sourceforge.net/examples/animation/dynamic_image.html>, 
> ex2 
> <http://matplotlib.sourceforge.net/examples/animation/dynamic_image2.html>).
>
> -Tony
>

I did now :

def showGraphs(data):
     data=sc.array([data])
     n=sc.shape(data)[2]
     ims=[]
     for k in range(n):
         mydata=data[:,:,k]
         im=plt.imshow(mydata+1)
         ims.append([im])
     return ims

and now it gives me "TypeError: Invalid dimensions for image data.

Hello Paul,

Sorry for the late reply I have been away for a couple of days. Thanks for
filing the issue, I would very much appreciate it if you manage to track it
down.

Luke

On Tue, Jan 17, 2012 at 1:47 AM, Paul Hobson <pmh...@gm...> wrote:

> Luke,
>
> I don't have an answer to your question, but I can confirm what your
> seeing with the attached image. I generated this figure with MPL
> 1.1.0, Python 2.7.1, on Windows 7 with ipythonqt and the inline
> backend. I filed an issue here:
> https://github.com/matplotlib/matplotlib/issues/680. If I find time
> tonight, I'll take a stab at tracking this down.
>
> Thanks,
>
> -paul
>
> On Sun, Jan 15, 2012 at 8:17 AM, Luke Jennings
> <ubu...@go...> wrote:
> >
> > Hello
> >
> > I sent this email just after Christmas and would appreciate it if anyone
> has
> > any suggestions. I am unsure if I have missed a parameter or should I
> file a
> > bug?
> >
> > Thanks
> >
> > Luke
> >
> > ---------- Forwarded message ----------
> > From: Luke Jennings <ubu...@go...>
> > Date: Mon, Dec 26, 2011 at 8:52 PM
> > Subject: Polar graph radial labels
> > To: mat...@li...
> >
> >
> > Hello,
> >
> > I am plotting polar graphs for a university project, the data is
> > confidential but I based the work on this
> > example
> http://matplotlib.sourceforge.net/examples/pylab_examples/polar_demo.html
>  and fortunately
> > the same problem occurs with this. If you take that code and change the
> last
> > four lines from:
> >
> > ax.set_rmax(2.0)
> > grid(True)
> >
> > ax.set_title("And there was much rejoicing!", fontsize=20)
> > show()
> >
> > To:
> >
> > ax.set_rmax(3.01)
> > ax.set_rmin(2.91)
> > grid(True)
> > ax.set_title("And there was much rejoicing!", fontsize=20)
> > show()
> >
> > and then run the script.
> >
> > The min and max needs to be very tight so that the data I am looking at
> can
> > be displayed properly. With the tight axis range, the labels end up of to
> > the top right, they are just visible on my screen (1920x1080) when the
> graph
> > is maximised.
> >
> > After some experimenting the smaller the range between the maximum and
> > minimum values the further to the right the labels go. I have not looked
> > into the coding of the polar module as my python knowledge is not great,
> but
> > my guess is that the labels are a set distance from the radial markers.
> >
> > So my question is how do I move the radial labels back to the correct
> > location?
> >
> > I hope I have not missed the answer in the documentation. I have
> installed
> > version 1.1.0 of matplotlib and its still a problem in it, thanks for the
> > good instructions on how to do it on ubuntu.
> >
> > I look forward to any help.
> >
> > Luke
> >
> >
> >
> ------------------------------------------------------------------------------
> > RSA(R) Conference 2012
> > Mar 27 - Feb 2
> > Save $400 by Jan. 27
> > Register now!
> > http://p.sf.net/sfu/rsa-sfdev2dev2
> > _______________________________________________
> > Matplotlib-users mailing list
> > Mat...@li...
> > https://lists.sourceforge.net/lists/listinfo/matplotlib-users
> >
>

On Sat, Jan 21, 2012 at 9:07 AM, Gousios George <gg...@wi...>wrote:

> Hello , i have the following code in matlab and trying to do it in
> matplotlib.
>
> I have this code in matlab (in a function showGraphs):
> ...
> m = size(myList, 3);
> for k = 1:m
>     g = myList(:, :, k);
>     image(g + 1)
>     axis off
>     axis square
>     M(k) = getframe;
> end;
>
> and in another file (another function):
> ...
> M = showGraphs(grids)
> movie(M, 1)
>
>
>
> I did so far:
>
> def showGraphs(data):
>     data=sc.array([data])
>     n=sc.shape(data)[2]
>     for k in range(n):
>         mydata=data[:,:,k]
>         #plt.imshow(mydata+1)    -->> this doesn't work
>
> Also ,in order to do the animation :
>
> grids=...(result from another function)
> result=showGraph(grids)
> fig=plt.figure()
> ani=animation.FuncAnimation(fig,result,interval=30,blit=True)
> plt.show()
>
> Right now the program says "TypeError: 'NoneType' object is not
> callable" (it has errors in the animation call)
>
> What should be my approach to this in order to have the animation?
>
> Thank you!
>
>
You're getting that error because the second argument to FuncAnimation
(`result` in your example) should be a function (not always; see example 2
linked below). Right now, if your `showGraphs` function is defined in full,
it returns a value of None, which gets saved to `result` (hence the error).

You should take a look at some of the image animation examples
(ex1<http://matplotlib.sourceforge.net/examples/animation/dynamic_image.html>,
ex2<http://matplotlib.sourceforge.net/examples/animation/dynamic_image2.html>
).

-Tony

Hello , i have the following code in matlab and trying to do it in 
matplotlib.

I have this code in matlab (in a function showGraphs):
...
m = size(myList, 3);
for k = 1:m
     g = myList(:, :, k);
     image(g + 1)
     axis off
     axis square
     M(k) = getframe;
end;

and in another file (another function):
...
M = showGraphs(grids)
movie(M, 1)



I did so far:

def showGraphs(data):
     data=sc.array([data])
     n=sc.shape(data)[2]
     for k in range(n):
         mydata=data[:,:,k]
         #plt.imshow(mydata+1)    -->> this doesn't work

Also ,in order to do the animation :

grids=...(result from another function)
result=showGraph(grids)
fig=plt.figure()
ani=animation.FuncAnimation(fig,result,interval=30,blit=True)
plt.show()

Right now the program says "TypeError: 'NoneType' object is not 
callable" (it has errors in the animation call)

What should be my approach to this in order to have the animation?

Thank you!