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From: Marcello V. <mar...@bo...> - 2013-02-19 14:33:44
|
When I plot contours in a stereographic south pole plot with a bounding latitude and the rounded clipping Basemap(projection='spaeqd',lat_0=-90,lon_0=180,resolution='l',boundinglat=-40,round=True) I see that the contours are correctly cut-off but not the contour labels. They appear to be plotted according to a rectangular frame and not the rounded one (see attached figure). Is it possible to mask the labels without having to mask the data? This issue may be related to an older topic: http://www.mail-archive.com/mat...@li.../msg02892.html and to a more recent bugfix https://github.com/matplotlib/basemap/pull/89 but I do not see any other clue thanks in advance marcello -- Dr Marcello Vichi Centro Euro-Mediterraneo sui Cambiamenti Climatici (CMCC) Istituto Nazionale di Geofisica e Vulcanologia (INGV) Viale Aldo Moro 44, 40127 Bologna. Italy Tel: +39 051 3782631 Fax: +39 051 3782654 Email: mar...@cm..., mar...@bo... skype: marcello_vichi |
From: patricia <ptr...@ho...> - 2013-02-19 13:33:06
|
Thanks a lot! Works now! -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Problems-to-plot-more-than-9-subplots-tp40440p40444.html Sent from the matplotlib - users mailing list archive at Nabble.com. |
From: Andreas H. <li...@hi...> - 2013-02-19 13:03:23
|
On 02/19/2013 01:52 PM, patricia wrote: > Thanks Andreas, > Yes I usually do the same, but in this case I am not managing to do it due > to the functions being used. It does not allow me to put (7,3, nfig) inside > the "xx = TaylorDiagram(refstd, fig=fig, rect=122, label="xx")". > This is the code that I am using: > http://old.nabble.com/Taylor-diagram-(2nd-take)-p33364690.html > Do you see an easy way of adding more than 9 Taylor diagrams subplots in > test1 for example? >From how I understand the FA.FloatingSubplot docstring (I'm running 1.1.1rc), you could try class TaylorDiagram(object): def __init__(self, refstd, fig=None, rect=(1, 1, 1), label='_', srange=(0,1.5)): ... from matplotlib.projections import PolarAxes import mpl_toolkits.axisartist.floating_axes as FA import mpl_toolkits.axisartist.grid_finder as GF ... ax = FA.FloatingSubplot(fig, rect[0], rect[1], rect[2], grid_helper=ghelper) fig.add_subplot(ax) ... dia = TaylorDiagram(refstd, fig=fig, rect=(3, 7, nrfig, label="EM") FA.FloatingSubplot docstring says: Definition:FA.FloatingSubplot(self, fig, *args, **kwargs) Docstring: *fig* is a :class:`matplotlib.figure.Figure` instance. *args* is the tuple (*numRows*, *numCols*, *plotNum*), where the array of subplots in the figure has dimensions *numRows*, *numCols*, and where *plotNum* is the number of the subplot being created. *plotNum* starts at 1 in the upper left corner and increases to the right. If *numRows* <= *numCols* <= *plotNum* < 10, *args* can be the decimal integer *numRows* * 100 + *numCols* * 10 + *plotNum*. Hope that helps, A. |
From: patricia <ptr...@ho...> - 2013-02-19 12:52:10
|
Thanks Andreas, Yes I usually do the same, but in this case I am not managing to do it due to the functions being used. It does not allow me to put (7,3, nfig) inside the "xx = TaylorDiagram(refstd, fig=fig, rect=122, label="xx")". This is the code that I am using: http://old.nabble.com/Taylor-diagram-(2nd-take)-p33364690.html Do you see an easy way of adding more than 9 Taylor diagrams subplots in test1 for example? Thanks again, Patricia -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Problems-to-plot-more-than-9-subplots-tp40440p40442.html Sent from the matplotlib - users mailing list archive at Nabble.com. |
From: Andreas H. <li...@hi...> - 2013-02-19 12:32:36
|
> The " subplot(111) " works only until 9 subplots, and this function does > not allow me to put rect=(7,3,nrfig). I get the error: > 'Single argument to subplot must be a 3-digit integer') > ValueError: Single argument to subplot must be a 3-digit integer I always do ax = fig.add_subplot(7, 3, nfig) which works. (in list iterations, make sure nfig starts at 1). Andreas. |
From: Patricia T. <ptr...@ho...> - 2013-02-19 12:18:36
|
Hi,I want to make a figure with 21 subplots (7 x 3) but I cannot plot more than 9 in the function I am using. class TaylorDiagram(object): def __init__(self, refstd, fig=None, rect=111, label='_', srange=(0,1.5)): ... from matplotlib.projections import PolarAxes import mpl_toolkits.axisartist.floating_axes as FA import mpl_toolkits.axisartist.grid_finder as GF ... ax = FA.FloatingSubplot(fig, rect, grid_helper=ghelper) fig.add_subplot(ax) ... dia = TaylorDiagram(refstd, fig=fig, rect=111, label="EM") The " subplot(111) " works only until 9 subplots, and this function does not allow me to put rect=(7,3,nrfig). I get the error: 'Single argument to subplot must be a 3-digit integer')ValueError: Single argument to subplot must be a 3-digit integer Can you please help me? Thanks,Patricia |
From: Mark B. <ma...@gm...> - 2013-02-19 09:33:10
|
I found out a \! (negative thin space in Latex) works. xlabel('$m^3\!/d$') On Tue, Feb 19, 2013 at 10:15 AM, Mark Bakker <ma...@gm...> wrote: > Hello List, > > I want to put the following text on a graph, for example along the x-axis: > > xlabel('$m^3/d$') > > This should show the letter m raised to the power 3 and then a slash and > the letter d. > When I do this, there appears a large space after the power 3 and the > slash. > So much so that the copy editor of the journal I am publishing in asked me > to remove the extra white space. > > Any suggestions on how to do that? > > Thanks, > > Mark > |
From: Mark B. <ma...@gm...> - 2013-02-19 09:16:06
|
Hello List, I want to put the following text on a graph, for example along the x-axis: xlabel('$m^3/d$') This should show the letter m raised to the power 3 and then a slash and the letter d. When I do this, there appears a large space after the power 3 and the slash. So much so that the copy editor of the journal I am publishing in asked me to remove the extra white space. Any suggestions on how to do that? Thanks, Mark |