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        |  | >>> A = mat('[1 3 5; 2 5 1; 2 3 8]')
 >>> b = mat('[10;8;3]')
 >>> A.I*b
 Matrix([[-9.28],
        [ 5.16],
        [ 0.76]])
 >>> linalg.solve(A,b)
 array([[-9.28],
        [ 5.16],
        [ 0.76]])
 | 
 
  
                     
                    
                    
                 
            
         
    
      
    
    
    
    
    
        
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