My data is almost in its function but I am having difficulties with the
final step. Goal: To get the array data into a textbox window on line 406
and 407 of -> http://pastie.org/4742333 But I am getting this error
http://pastie.org/4742347 and I have tried a few different versions of
passing the argument but no success.
Brad
From: bibigiu [mailto:bi...@al...]
Sent: Monday, September 17, 2012 11:30 AM
To: Brad
Subject: Re: [Dev-C++] how to pass a string array to another function
Il 17/09/2012 14:40, Brad ha scritto:
That's the problem, my function is not in main() and this is where the
errors get weird is when I pass the same arguments in a function outside of
main.
Brad
From: bibigiu [mailto:bi...@al...]
Sent: Monday, September 17, 2012 8:04 AM
To: Brad
Subject: Re: [Dev-C++] how to pass a string array to another function
Il 17/09/2012 13:40, Brad ha scritto:
My situation is this, I have a string array that I am trying to get the data
to another function but have issues with the return type conflicting with
either the function definition or the array data being passed.
std::array Array[2]
std::string f()
{
array[0]=ted
array[1]=bundy
return Array[2];
}};
void printarray (int arg[], int length) {
for (int n=0; n<length; n++)
cout << Array[n] << endl;
}
int main ()
{
printarray();
return 0;
}
try this :
#include <iostream>
using namespace std;
void PrintArray(std::string str[],int length)
{
for(int a=0;a<length;a++)
{
cout<< str[a].c_str() << endl;
}
}
int main()
{
std::string str[2];
str[0] = "hello";
str[1] = "bye";
PrintArray(str,2);
return 0;
}
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ops... try this
void PrintArray(std::string *str,int length)
{
for(int a=0;a<length;a++)
{
cout<< str[a].c_str() << endl;
}
}
string* CreateStrArray(int size)
{
std::string *str = new std::string[size];
for(int a=0;a<size;a++)
str[a] = "name";
return str;
}
int main( )
{
std::string *str = CreateStrArray(2);// you must use pointer allocation
with new(on the heap) for return object from a function... local variable
created in the function are destroyed when return from the function!!!!
PrintArray(str,2);
return 0;
}
is that what you want?
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