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%I A133525 #11 Jan 01 2024 19:47:37
%S A133525 503,1826,3996,8784,15300,26136,48328,73206,117000,173754,228872,
%T A133525 302904,401128,537586,685060,882000,1091034,1274672,1540730,1811754,
%U A133525 2158812,2682468,3219730,3740670,4260744,4643100,5055696,6011352,7034400
%N A133525 Sum of third powers of four consecutive primes.
%H A133525 Robert Israel, <a href="/A133525/b133525.txt">Table of n, a(n) for n = 1..10000</a>
%F A133525 a(n) = A133530(n) + A030078(n+3). - _Michel Marcus_, Nov 08 2013
%e A133525 a(1)=503 because 2^3+3^3+5^3+7^3=503.
%p A133525 N:= 50: # for a(1)..a(N)
%p A133525 P3:= [0,seq(ithprime(i)^3,i=1..N+3)]:
%p A133525 S:= ListTools:-PartialSums(P3):
%p A133525 seq(S[i+4]-S[i],i=1..N); # _Robert Israel_, Jan 01 2024
%t A133525 a = 3; Table[Prime[n]^a + Prime[n + 1]^a + Prime[n + 2]^a + Prime[n + 3]^a, {n, 1, 100}]
%t A133525 Total/@Partition[Prime[Range[40]]^3,4,1] (* _Harvey P. Dale_, Jan 06 2019 *)
%Y A133525 Cf. A034963, A133524, A133526, A133527, A133528.
%K A133525 nonn
%O A133525 1,1
%A A133525 _Artur Jasinski_, Sep 14 2007

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