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PaintHouse.java
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package com.leetcode.dynamicprogramming;
/**
* Level: Easy
* Problem Link: https://leetcode.com/problems/paint-house/
* Problem Description:
* There are a row of n houses, each house can be painted with one of the three colors: red, blue or green. The cost
* of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent
* houses have the same color. The cost of painting each house with a certain color is represented by a n x 3 cost matrix.
* <p>
* For example, costs[0][0] is the cost of painting house 0 with color red; costs[1][2] is the cost of painting
* house 1 with color green, and so on... Find the minimum cost to paint all houses.
* <p>
* Companies: LinkedIn.
* Related: {@link PaintHouseII}.
*
* @author rampatra
* @since 2019-07-23
*/
public class PaintHouse {
/**
* Runtime: <a href="https://leetcode.com/submissions/detail/248573066/">1 ms</a>.
*
* @param costs of coloring the houses with red, blue, and green respectively. 1st row represents house 1, 2nd row
* house 2 and so on
* @return the minimum cost to paint all houses such that no two adjacent houses are of same color
*/
public static int minCost(int[][] costs) {
if (costs == null || costs.length == 0) return 0;
for (int i = 1; i < costs.length; i++) {
costs[i][0] += Math.min(costs[i - 1][1], costs[i - 1][2]);
costs[i][1] += Math.min(costs[i - 1][0], costs[i - 1][2]);
costs[i][2] += Math.min(costs[i - 1][0], costs[i - 1][1]);
}
int lastRow = costs.length - 1;
return Math.min(Math.min(costs[lastRow][0], costs[lastRow][1]), costs[lastRow][2]);
}
public static void main(String[] args) {
System.out.println(minCost(new int[][]{
}));
System.out.println(minCost(new int[][]{
{2, 3, 4},
{5, 7, 6},
{8, 7, 2}
}));
}
}