update

Author: zhangbk1

Diff for: README.md

@@ -1,6 +1,6 @@
 # 力扣题库（完整版）
 
-> 最后更新日期： **2024.09.19**
+> 最后更新日期： **2024.09.23**
 >
 > 使用脚本前请务必仔细完整阅读本 `README.md` 文件
 

Diff for: leetcode-cn/origin-data.json

@@ -0,0 +1,41 @@
+<p>给你一个字符串数组 <code>message</code> 和一个字符串数组 <code>bannedWords</code>。</p>
+
+<p>如果数组中 <strong>至少</strong> 存在两个单词与 <code>bannedWords</code> 中的任一单词 <strong>完全相同</strong>，则该数组被视为 <strong>垃圾信息</strong>。</p>
+
+<p>如果数组 <code>message</code> 是垃圾信息，则返回 <code>true</code>；否则返回 <code>false</code>。</p>
+
+<p>&nbsp;</p>
+
+<p><strong class="example">示例 1：</strong></p>
+
+<div class="example-block">
+<p><strong>输入：</strong> <span class="example-io">message = ["hello","world","leetcode"], bannedWords = ["world","hello"]</span></p>
+
+<p><strong>输出：</strong> <span class="example-io">true</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>数组 <code>message</code> 中的 <code>"hello"</code> 和 <code>"world"</code> 都出现在数组 <code>bannedWords</code> 中。</p>
+</div>
+
+<p><strong class="example">示例 2：</strong></p>
+
+<div class="example-block">
+<p><strong>输入：</strong> <span class="example-io">message = ["hello","programming","fun"], bannedWords = ["world","programming","leetcode"]</span></p>
+
+<p><strong>输出：</strong> <span class="example-io">false</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>数组 <code>message</code> 中只有一个单词（<code>"programming"</code>）出现在数组 <code>bannedWords</code> 中。</p>
+</div>
+
+<p>&nbsp;</p>
+
+<p><strong>提示：</strong></p>
+
+<ul>
+	<li><code>1 &lt;= message.length, bannedWords.length &lt;= 10<sup>5</sup></code></li>
+	<li><code>1 &lt;= message[i].length, bannedWords[i].length &lt;= 15</code></li>
+	<li><code>message[i]</code> 和 <code>bannedWords[i]</code> 都只由小写英文字母组成。</li>
+</ul>

Diff for: leetcode-cn/originData/count-substrings-that-can-be-rearranged-to-contain-a-string-i.json

@@ -0,0 +1,80 @@
+<p>给你一个整数 <code>mountainHeight</code> 表示山的高度。</p>
+
+<p>同时给你一个整数数组 <code>workerTimes</code>，表示工人们的工作时间（单位：<strong>秒</strong>）。</p>
+
+<p>工人们需要 <strong>同时 </strong>进行工作以 <strong>降低 </strong>山的高度。对于工人 <code>i</code> :</p>
+
+<ul>
+	<li>山的高度降低 <code>x</code>，需要花费 <code>workerTimes[i] + workerTimes[i] * 2 + ... + workerTimes[i] * x</code> 秒。例如：
+
+	<ul>
+		<li>山的高度降低 1，需要 <code>workerTimes[i]</code> 秒。</li>
+		<li>山的高度降低 2，需要 <code>workerTimes[i] + workerTimes[i] * 2</code> 秒，依此类推。</li>
+	</ul>
+	</li>
+</ul>
+
+<p>返回一个整数，表示工人们使山的高度降低到 0 所需的 <strong>最少</strong> 秒数。</p>
+
+<p>&nbsp;</p>
+
+<p><strong class="example">示例 1：</strong></p>
+
+<div class="example-block">
+<p><strong>输入：</strong> <span class="example-io">mountainHeight = 4, workerTimes = [2,1,1]</span></p>
+
+<p><strong>输出：</strong> <span class="example-io">3</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>将山的高度降低到 0 的一种方式是：</p>
+
+<ul>
+	<li>工人 0 将高度降低 1，花费 <code>workerTimes[0] = 2</code> 秒。</li>
+	<li>工人 1 将高度降低 2，花费 <code>workerTimes[1] + workerTimes[1] * 2 = 3</code> 秒。</li>
+	<li>工人 2 将高度降低 1，花费 <code>workerTimes[2] = 1</code> 秒。</li>
+</ul>
+
+<p>因为工人同时工作，所需的最少时间为 <code>max(2, 3, 1) = 3</code> 秒。</p>
+</div>
+
+<p><strong class="example">示例 2：</strong></p>
+
+<div class="example-block">
+<p><strong>输入：</strong> <span class="example-io">mountainHeight = 10, workerTimes = [3,2,2,4]</span></p>
+
+<p><strong>输出：</strong> <span class="example-io">12</span></p>
+
+<p><strong>解释：</strong></p>
+
+<ul>
+	<li>工人 0 将高度降低 2，花费 <code>workerTimes[0] + workerTimes[0] * 2 = 9</code> 秒。</li>
+	<li>工人 1 将高度降低 3，花费 <code>workerTimes[1] + workerTimes[1] * 2 + workerTimes[1] * 3 = 12</code> 秒。</li>
+	<li>工人 2 将高度降低 3，花费 <code>workerTimes[2] + workerTimes[2] * 2 + workerTimes[2] * 3 = 12</code> 秒。</li>
+	<li>工人 3 将高度降低 2，花费 <code>workerTimes[3] + workerTimes[3] * 2 = 12</code> 秒。</li>
+</ul>
+
+<p>所需的最少时间为 <code>max(9, 12, 12, 12) = 12</code> 秒。</p>
+</div>
+
+<p><strong class="example">示例 3：</strong></p>
+
+<div class="example-block">
+<p><strong>输入：</strong> <span class="example-io">mountainHeight = 5, workerTimes = [1]</span></p>
+
+<p><strong>输出：</strong> <span class="example-io">15</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>这个示例中只有一个工人，所以答案是 <code>workerTimes[0] + workerTimes[0] * 2 + workerTimes[0] * 3 + workerTimes[0] * 4 + workerTimes[0] * 5 = 15</code> 秒。</p>
+</div>
+
+<p>&nbsp;</p>
+
+<p><strong>提示：</strong></p>
+
+<ul>
+	<li><code>1 &lt;= mountainHeight &lt;= 10<sup>5</sup></code></li>
+	<li><code>1 &lt;= workerTimes.length &lt;= 10<sup>4</sup></code></li>
+	<li><code>1 &lt;= workerTimes[i] &lt;= 10<sup>6</sup></code></li>
+</ul>

Diff for: leetcode-cn/originData/count-substrings-that-can-be-rearranged-to-contain-a-string-ii.json

@@ -0,0 +1,49 @@
+<p>给你两个字符串&nbsp;<code>word1</code> 和&nbsp;<code>word2</code>&nbsp;。</p>
+
+<p>如果一个字符串 <code>x</code>&nbsp;重新排列后，<code>word2</code>&nbsp;是重排字符串的&nbsp;<span data-keyword="string-prefix">前缀</span>&nbsp;，那么我们称字符串&nbsp;<code>x</code>&nbsp;是&nbsp;<strong>合法的</strong>&nbsp;。</p>
+
+<p>请你返回 <code>word1</code>&nbsp;中 <strong>合法</strong>&nbsp;<span data-keyword="substring-nonempty">子字符串</span>&nbsp;的数目。</p>
+
+<p>&nbsp;</p>
+
+<p><strong class="example">示例 1：</strong></p>
+
+<div class="example-block">
+<p><span class="example-io"><b>输入：</b>word1 = "bcca", word2 = "abc"</span></p>
+
+<p><span class="example-io"><b>输出：</b>1</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>唯一合法的子字符串是&nbsp;<code>"bcca"</code>&nbsp;，可以重新排列得到&nbsp;<code>"abcc"</code>&nbsp;，<code>"abc"</code>&nbsp;是它的前缀。</p>
+</div>
+
+<p><strong class="example">示例 2：</strong></p>
+
+<div class="example-block">
+<p><span class="example-io"><b>输入：</b>word1 = "abcabc", word2 = "abc"</span></p>
+
+<p><span class="example-io"><b>输出：</b>10</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>除了长度为 1 和 2 的所有子字符串都是合法的。</p>
+</div>
+
+<p><strong class="example">示例 3：</strong></p>
+
+<div class="example-block">
+<p><span class="example-io"><b>输入：</b>word1 = "abcabc", word2 = "aaabc"</span></p>
+
+<p><span class="example-io"><b>输出：</b>0</span></p>
+</div>
+
+<p>&nbsp;</p>
+
+<p><strong>解释：</strong></p>
+
+<ul>
+	<li><code>1 &lt;= word1.length &lt;= 10<sup>5</sup></code></li>
+	<li><code>1 &lt;= word2.length &lt;= 10<sup>4</sup></code></li>
+	<li><code>word1</code> 和&nbsp;<code>word2</code>&nbsp;都只包含小写英文字母。</li>
+</ul>

Diff for: leetcode-cn/originData/minimum-number-of-seconds-to-make-mountain-height-zero.json

@@ -0,0 +1,51 @@
+<p>给你两个字符串&nbsp;<code>word1</code> 和&nbsp;<code>word2</code>&nbsp;。</p>
+
+<p>如果一个字符串 <code>x</code>&nbsp;重新排列后，<code>word2</code>&nbsp;是重排字符串的&nbsp;<span data-keyword="string-prefix">前缀</span>&nbsp;，那么我们称字符串&nbsp;<code>x</code>&nbsp;是&nbsp;<strong>合法的</strong>&nbsp;。</p>
+
+<p>请你返回 <code>word1</code>&nbsp;中 <strong>合法</strong>&nbsp;<span data-keyword="substring-nonempty">子字符串</span>&nbsp;的数目。</p>
+
+<p><strong>注意</strong>&nbsp;，这个问题中的内存限制比其他题目要&nbsp;<strong>小</strong>&nbsp;，所以你&nbsp;<strong>必须</strong>&nbsp;实现一个线性复杂度的解法。</p>
+
+<p>&nbsp;</p>
+
+<p><strong class="example">示例 1：</strong></p>
+
+<div class="example-block">
+<p><span class="example-io"><b>输入：</b>word1 = "bcca", word2 = "abc"</span></p>
+
+<p><span class="example-io"><b>输出：</b>1</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>唯一合法的子字符串是&nbsp;<code>"bcca"</code>&nbsp;，可以重新排列得到&nbsp;<code>"abcc"</code>&nbsp;，<code>"abc"</code>&nbsp;是它的前缀。</p>
+</div>
+
+<p><strong class="example">示例 2：</strong></p>
+
+<div class="example-block">
+<p><span class="example-io"><b>输入：</b>word1 = "abcabc", word2 = "abc"</span></p>
+
+<p><span class="example-io"><b>输出：</b>10</span></p>
+
+<p><strong>解释：</strong></p>
+
+<p>除了长度为 1 和 2 的所有子字符串都是合法的。</p>
+</div>
+
+<p><strong class="example">示例 3：</strong></p>
+
+<div class="example-block">
+<p><span class="example-io"><b>输入：</b>word1 = "abcabc", word2 = "aaabc"</span></p>
+
+<p><span class="example-io"><b>输出：</b>0</span></p>
+</div>
+
+<p>&nbsp;</p>
+
+<p><strong>解释：</strong></p>
+
+<ul>
+	<li><code>1 &lt;= word1.length &lt;= 10<sup>6</sup></code></li>
+	<li><code>1 &lt;= word2.length &lt;= 10<sup>4</sup></code></li>
+	<li><code>word1</code> 和&nbsp;<code>word2</code>&nbsp;都只包含小写英文字母。</li>
+</ul>

Diff for: leetcode-cn/originData/report-spam-message.json

@@ -0,0 +1,39 @@
+<p>You are given an array of strings <code>message</code> and an array of strings <code>bannedWords</code>.</p>
+
+<p>An array of words is considered <strong>spam</strong> if there are <strong>at least</strong> two words in it that <b>exactly</b> match any word in <code>bannedWords</code>.</p>
+
+<p>Return <code>true</code> if the array <code>message</code> is spam, and <code>false</code> otherwise.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">message = [&quot;hello&quot;,&quot;world&quot;,&quot;leetcode&quot;], bannedWords = [&quot;world&quot;,&quot;hello&quot;]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">true</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>The words <code>&quot;hello&quot;</code> and <code>&quot;world&quot;</code> from the <code>message</code> array both appear in the <code>bannedWords</code> array.</p>
+</div>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">message = [&quot;hello&quot;,&quot;programming&quot;,&quot;fun&quot;], bannedWords = [&quot;world&quot;,&quot;programming&quot;,&quot;leetcode&quot;]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">false</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>Only one word from the <code>message</code> array (<code>&quot;programming&quot;</code>) appears in the <code>bannedWords</code> array.</p>
+</div>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= message.length, bannedWords.length &lt;= 10<sup>5</sup></code></li>
+	<li><code>1 &lt;= message[i].length, bannedWords[i].length &lt;= 15</code></li>
+	<li><code>message[i]</code> and <code>bannedWords[i]</code> consist only of lowercase English letters.</li>
+</ul>

Diff for: leetcode-cn/problem (Chinese)/举报垃圾信息 [report-spam-message].html

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+<p>You are given an integer <code>mountainHeight</code> denoting the height of a mountain.</p>
+
+<p>You are also given an integer array <code>workerTimes</code> representing the work time of workers in <strong>seconds</strong>.</p>
+
+<p>The workers work <strong>simultaneously</strong> to <strong>reduce</strong> the height of the mountain. For worker <code>i</code>:</p>
+
+<ul>
+	<li>To decrease the mountain&#39;s height by <code>x</code>, it takes <code>workerTimes[i] + workerTimes[i] * 2 + ... + workerTimes[i] * x</code> seconds. For example:
+
+	<ul>
+		<li>To reduce the height of the mountain by 1, it takes <code>workerTimes[i]</code> seconds.</li>
+		<li>To reduce the height of the mountain by 2, it takes <code>workerTimes[i] + workerTimes[i] * 2</code> seconds, and so on.</li>
+	</ul>
+	</li>
+</ul>
+
+<p>Return an integer representing the <strong>minimum</strong> number of seconds required for the workers to make the height of the mountain 0.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">mountainHeight = 4, workerTimes = [2,1,1]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">3</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>One way the height of the mountain can be reduced to 0 is:</p>
+
+<ul>
+	<li>Worker 0 reduces the height by 1, taking <code>workerTimes[0] = 2</code> seconds.</li>
+	<li>Worker 1 reduces the height by 2, taking <code>workerTimes[1] + workerTimes[1] * 2 = 3</code> seconds.</li>
+	<li>Worker 2 reduces the height by 1, taking <code>workerTimes[2] = 1</code> second.</li>
+</ul>
+
+<p>Since they work simultaneously, the minimum time needed is <code>max(2, 3, 1) = 3</code> seconds.</p>
+</div>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">mountainHeight = 10, workerTimes = [3,2,2,4]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">12</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<ul>
+	<li>Worker 0 reduces the height by 2, taking <code>workerTimes[0] + workerTimes[0] * 2 = 9</code> seconds.</li>
+	<li>Worker 1 reduces the height by 3, taking <code>workerTimes[1] + workerTimes[1] * 2 + workerTimes[1] * 3 = 12</code> seconds.</li>
+	<li>Worker 2 reduces the height by 3, taking <code>workerTimes[2] + workerTimes[2] * 2 + workerTimes[2] * 3 = 12</code> seconds.</li>
+	<li>Worker 3 reduces the height by 2, taking <code>workerTimes[3] + workerTimes[3] * 2 = 12</code> seconds.</li>
+</ul>
+
+<p>The number of seconds needed is <code>max(9, 12, 12, 12) = 12</code> seconds.</p>
+</div>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">mountainHeight = 5, workerTimes = [1]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">15</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>There is only one worker in this example, so the answer is <code>workerTimes[0] + workerTimes[0] * 2 + workerTimes[0] * 3 + workerTimes[0] * 4 + workerTimes[0] * 5 = 15</code>.</p>
+</div>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= mountainHeight &lt;= 10<sup>5</sup></code></li>
+	<li><code>1 &lt;= workerTimes.length &lt;= 10<sup>4</sup></code></li>
+	<li><code>1 &lt;= workerTimes[i] &lt;= 10<sup>6</sup></code></li>
+</ul>

Diff for: leetcode-cn/problem (Chinese)/移山所需的最少秒数 [minimum-number-of-seconds-to-make-mountain-height-zero].html

@@ -0,0 +1,47 @@
+<p>You are given two strings <code>word1</code> and <code>word2</code>.</p>
+
+<p>A string <code>x</code> is called <strong>valid</strong> if <code>x</code> can be rearranged to have <code>word2</code> as a <span data-keyword="string-prefix">prefix</span>.</p>
+
+<p>Return the total number of <strong>valid</strong> <span data-keyword="substring-nonempty">substrings</span> of <code>word1</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">word1 = &quot;bcca&quot;, word2 = &quot;abc&quot;</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">1</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>The only valid substring is <code>&quot;bcca&quot;</code> which can be rearranged to <code>&quot;abcc&quot;</code> having <code>&quot;abc&quot;</code> as a prefix.</p>
+</div>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">word1 = &quot;abcabc&quot;, word2 = &quot;abc&quot;</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">10</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>All the substrings except substrings of size 1 and size 2 are valid.</p>
+</div>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">word1 = &quot;abcabc&quot;, word2 = &quot;aaabc&quot;</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">0</span></p>
+</div>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= word1.length &lt;= 10<sup>5</sup></code></li>
+	<li><code>1 &lt;= word2.length &lt;= 10<sup>4</sup></code></li>
+	<li><code>word1</code> and <code>word2</code> consist only of lowercase English letters.</li>
+</ul>