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算法题/add-two-numbers.html

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<p>You are given two <strong>non-empty</strong> linked lists representing two non-negative integers. The digits are stored in <strong>reverse order</strong>, and each of their nodes contains a single digit. Add the two numbers and return the sum&nbsp;as a linked list.</p>
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<p>You may assume the two numbers do not contain any leading zero, except the number 0 itself.</p>
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<p>&nbsp;</p>
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<p><strong>Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2020/10/02/addtwonumber1.jpg" style="width: 483px; height: 342px;" />
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<pre>
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<strong>Input:</strong> l1 = [2,4,3], l2 = [5,6,4]
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<strong>Output:</strong> [7,0,8]
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<strong>Explanation:</strong> 342 + 465 = 807.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> l1 = [0], l2 = [0]
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<strong>Output:</strong> [0]
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
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<strong>Output:</strong> [8,9,9,9,0,0,0,1]
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>The number of nodes in each linked list is in the range <code>[1, 100]</code>.</li>
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<li><code>0 &lt;= Node.val &lt;= 9</code></li>
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<li>It is guaranteed that the list represents a number that does not have leading zeros.</li>
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</ul>

算法题/add-two-numbers.json

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<p>Given a string <code>s</code>, return <em>the longest palindromic substring</em> in <code>s</code>.</p>
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<p>&nbsp;</p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> s = &quot;babad&quot;
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<strong>Output:</strong> &quot;bab&quot;
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<strong>Explanation:</strong> &quot;aba&quot; is also a valid answer.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> s = &quot;cbbd&quot;
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<strong>Output:</strong> &quot;bb&quot;
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 &lt;= s.length &lt;= 1000</code></li>
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<li><code>s</code> consist of only digits and English letters.</li>
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</ul>

算法题/longest-palindromic-substring.json

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<p>Given a string <code>s</code>, find the length of the <strong>longest substring</strong> without repeating characters.</p>
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<p>&nbsp;</p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> s = &quot;abcabcbb&quot;
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> The answer is &quot;abc&quot;, with the length of 3.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> s = &quot;bbbbb&quot;
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<strong>Output:</strong> 1
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<strong>Explanation:</strong> The answer is &quot;b&quot;, with the length of 1.
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</pre>
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<p><strong>Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> s = &quot;pwwkew&quot;
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> The answer is &quot;wke&quot;, with the length of 3.
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Notice that the answer must be a substring, &quot;pwke&quot; is a subsequence and not a substring.
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>0 &lt;= s.length &lt;= 5 * 10<sup>4</sup></code></li>
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<li><code>s</code> consists of English letters, digits, symbols and spaces.</li>
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</ul>

算法题/longest-substring-without-repeating-characters.json

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<p>Given two sorted arrays <code>nums1</code> and <code>nums2</code> of size <code>m</code> and <code>n</code> respectively, return <strong>the median</strong> of the two sorted arrays.</p>
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<p>The overall run time complexity should be <code>O(log (m+n))</code>.</p>
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<p>&nbsp;</p>
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<p><strong>Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums1 = [1,3], nums2 = [2]
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<strong>Output:</strong> 2.00000
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<strong>Explanation:</strong> merged array = [1,2,3] and median is 2.
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</pre>
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<p><strong>Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums1 = [1,2], nums2 = [3,4]
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<strong>Output:</strong> 2.50000
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<strong>Explanation:</strong> merged array = [1,2,3,4] and median is (2 + 3) / 2 = 2.5.
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>nums1.length == m</code></li>
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<li><code>nums2.length == n</code></li>
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<li><code>0 &lt;= m &lt;= 1000</code></li>
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<li><code>0 &lt;= n &lt;= 1000</code></li>
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<li><code>1 &lt;= m + n &lt;= 2000</code></li>
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<li><code>-10<sup>6</sup> &lt;= nums1[i], nums2[i] &lt;= 10<sup>6</sup></code></li>
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</ul>
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Adding an item to a hash.</b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n int id; /* we'll use this field as the key */\\r\\n char name[10];\\r\\n UT_hash_handle hh; /* makes this structure hashable */\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>2. Looking up an item in a hash:</b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>3. 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If you need more libraries, you can import it yourself.</p>\\r\\n\\r\\n<p>For Map/TreeMap data structure, you may use <a href=\\\"http://www.grantjenks.com/docs/sortedcontainers/\\\" target=\\\"_blank\\\">sortedcontainers</a> library.</p>\"], \"scala\": [\"Scala\", \"<p><code>Scala 2.13.7</code>.</p>\"], \"kotlin\": [\"Kotlin\", \"<p><code>Kotlin 1.3.10</code>.</p>\"], \"rust\": [\"Rust\", \"<p><code>Rust 1.58.1</code></p>\\r\\n\\r\\n<p>Supports <a href=\\\"https://crates.io/crates/rand\\\" target=\\\"_blank\\\">rand </a> v0.6\\u00a0from crates.io</p>\"], \"php\": [\"PHP\", \"<p><code>PHP 8.1</code>.</p>\\r\\n<p>With bcmath module</p>\"], \"typescript\": [\"Typescript\", \"<p><code>TypeScript 4.5.4, Node.js 16.13.2</code>.</p>\\r\\n\\r\\n<p>Your code is run with <code>--harmony</code> flag, enabling <a href=\\\"http://node.green/\\\" target=\\\"_blank\\\">new ES2020 features</a>.</p>\\r\\n\\r\\n<p><a href=\\\"https://lodash.com\\\" target=\\\"_blank\\\">lodash.js</a> library is included by default.</p>\"], \"racket\": [\"Racket\", \"<p>Run with <code>Racket 8.3</code>.</p>\"], \"erlang\": [\"Erlang\", \"Erlang/OTP 24.2\"], \"elixir\": [\"Elixir\", \"Elixir 1.13.0 with Erlang/OTP 24.2\"]}",
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