4sum-ii.json

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            "title": "4Sum II",
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            "content": "<p>Given four integer arrays <code>nums1</code>, <code>nums2</code>, <code>nums3</code>, and <code>nums4</code> all of length <code>n</code>, return the number of tuples <code>(i, j, k, l)</code> such that:</p>\n\n<ul>\n\t<li><code>0 &lt;= i, j, k, l &lt; n</code></li>\n\t<li><code>nums1[i] + nums2[j] + nums3[k] + nums4[l] == 0</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2], nums2 = [-2,-1], nums3 = [-1,2], nums4 = [0,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nThe two tuples are:\n1. (0, 0, 0, 1) -&gt; nums1[0] + nums2[0] + nums3[0] + nums4[1] = 1 + (-2) + (-1) + 2 = 0\n2. (1, 1, 0, 0) -&gt; nums1[1] + nums2[1] + nums3[0] + nums4[0] = 2 + (-1) + (-1) + 0 = 0\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [0], nums2 = [0], nums3 = [0], nums4 = [0]\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length</code></li>\n\t<li><code>n == nums2.length</code></li>\n\t<li><code>n == nums3.length</code></li>\n\t<li><code>n == nums4.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 200</code></li>\n\t<li><code>-2<sup>28</sup> &lt;= nums1[i], nums2[i], nums3[i], nums4[i] &lt;= 2<sup>28</sup></code></li>\n</ul>\n",
            "translatedTitle": "四数相加 II",
            "translatedContent": "<p>给你四个整数数组 <code>nums1</code>、<code>nums2</code>、<code>nums3</code> 和 <code>nums4</code> ，数组长度都是 <code>n</code> ，请你计算有多少个元组 <code>(i, j, k, l)</code> 能满足：</p>\n\n<ul>\n\t<li><code>0 &lt;= i, j, k, l &lt; n</code></li>\n\t<li><code>nums1[i] + nums2[j] + nums3[k] + nums4[l] == 0</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,2], nums2 = [-2,-1], nums3 = [-1,2], nums4 = [0,2]\n<strong>输出：</strong>2\n<strong>解释：</strong>\n两个元组如下：\n1. (0, 0, 0, 1) -&gt; nums1[0] + nums2[0] + nums3[0] + nums4[1] = 1 + (-2) + (-1) + 2 = 0\n2. (1, 1, 0, 0) -&gt; nums1[1] + nums2[1] + nums3[0] + nums4[0] = 2 + (-1) + (-1) + 0 = 0\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [0], nums2 = [0], nums3 = [0], nums4 = [0]\n<strong>输出：</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p>&nbsp; <strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length</code></li>\n\t<li><code>n == nums2.length</code></li>\n\t<li><code>n == nums3.length</code></li>\n\t<li><code>n == nums4.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 200</code></li>\n\t<li><code>-2<sup>28</sup> &lt;= nums1[i], nums2[i], nums3[i], nums4[i] &lt;= 2<sup>28</sup></code></li>\n</ul>\n",
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