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UEcfPD.json
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{
"data": {
"question": {
"questionId": "1000434",
"questionFrontendId": "LCP 51",
"categoryTitle": "Algorithms",
"boundTopicId": 1425581,
"title": "烹饪料理",
"titleSlug": "UEcfPD",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "烹饪料理",
"translatedContent": "欢迎各位勇者来到力扣城，城内设有烹饪锅供勇者制作料理，为自己恢复状态。\n\n勇者背包内共有编号为 `0 ~ 4` 的五种食材，其中 `materials[j]` 表示第 `j` 种食材的数量。通过这些食材可以制作若干料理，`cookbooks[i][j]` 表示制作第 `i` 种料理需要第 `j` 种食材的数量，而 `attribute[i] = [x,y]` 表示第 `i` 道料理的美味度 `x` 和饱腹感 `y`。\n\n在饱腹感不小于 `limit` 的情况下，请返回勇者可获得的最大美味度。如果无法满足饱腹感要求，则返回 `-1`。\n\n**注意：**\n- 每种料理只能制作一次。\n\n\n**示例 1：**\n>输入：`materials = [3,2,4,1,2]`\n>`cookbooks = [[1,1,0,1,2],[2,1,4,0,0],[3,2,4,1,0]]`\n>`attribute = [[3,2],[2,4],[7,6]]`\n>`limit = 5`\n>\n>输出：`7`\n>\n>解释：\n>食材数量可以满足以下两种方案：\n>方案一：制作料理 0 和料理 1，可获得饱腹感 2+4、美味度 3+2\n>方案二：仅制作料理 2， 可饱腹感为 6、美味度为 7\n>因此在满足饱腹感的要求下，可获得最高美味度 7\n\n**示例 2：**\n>输入：`materials = [10,10,10,10,10]`\n>`cookbooks = [[1,1,1,1,1],[3,3,3,3,3],[10,10,10,10,10]]`\n>`attribute = [[5,5],[6,6],[10,10]]`\n>`limit = 1`\n>\n>输出：`11`\n>\n>解释：通过制作料理 0 和 1，可满足饱腹感，并获得最高美味度 11\n\n**提示：**\n+ `materials.length == 5`\n+ `1 <= cookbooks.length == attribute.length <= 8`\n+ `cookbooks[i].length == 5`\n+ `attribute[i].length == 2`\n+ `0 <= materials[i], cookbooks[i][j], attribute[i][j] <= 20`\n+ `1 <= limit <= 100`\n",
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"difficulty": "Easy",
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"username": "LeetCode",
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"code": "class Solution {\npublic:\n int perfectMenu(vector<int>& materials, vector<vector<int>>& cookbooks, vector<vector<int>>& attribute, int limit) {\n\n }\n};",
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"code": "class Solution(object):\n def perfectMenu(self, materials, cookbooks, attribute, limit):\n \"\"\"\n :type materials: List[int]\n :type cookbooks: List[List[int]]\n :type attribute: List[List[int]]\n :type limit: int\n :rtype: int\n \"\"\"",
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"code": "\n\nint perfectMenu(int* materials, int materialsSize, int** cookbooks, int cookbooksSize, int* cookbooksColSize, int** attribute, int attributeSize, int* attributeColSize, int limit){\n\n}",
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"code": "/**\n * @param {number[]} materials\n * @param {number[][]} cookbooks\n * @param {number[][]} attribute\n * @param {number} limit\n * @return {number}\n */\nvar perfectMenu = function(materials, cookbooks, attribute, limit) {\n\n};",
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"code": "class Solution {\n\n /**\n * @param Integer[] $materials\n * @param Integer[][] $cookbooks\n * @param Integer[][] $attribute\n * @param Integer $limit\n * @return Integer\n */\n function perfectMenu($materials, $cookbooks, $attribute, $limit) {\n\n }\n}",
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"code": "# @param {Integer[]} materials\n# @param {Integer[][]} cookbooks\n# @param {Integer[][]} attribute\n# @param {Integer} limit\n# @return {Integer}\ndef perfect_menu(materials, cookbooks, attribute, limit)\n\nend",
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"code": "object Solution {\n def perfectMenu(materials: Array[Int], cookbooks: Array[Array[Int]], attribute: Array[Array[Int]], limit: Int): Int = {\n\n }\n}",
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"code": "impl Solution {\n pub fn perfect_menu(materials: Vec<i32>, cookbooks: Vec<Vec<i32>>, attribute: Vec<Vec<i32>>, limit: i32) -> i32 {\n\n }\n}",
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"code": "(define/contract (perfect-menu materials cookbooks attribute limit)\n (-> (listof exact-integer?) (listof (listof exact-integer?)) (listof (listof exact-integer?)) exact-integer? exact-integer?)\n\n )",
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"lang": "Erlang",
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"code": "-spec perfect_menu(Materials :: [integer()], Cookbooks :: [[integer()]], Attribute :: [[integer()]], Limit :: integer()) -> integer().\nperfect_menu(Materials, Cookbooks, Attribute, Limit) ->\n .",
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"lang": "Elixir",
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"code": "defmodule Solution do\n @spec perfect_menu(materials :: [integer], cookbooks :: [[integer]], attribute :: [[integer]], limit :: integer) :: integer\n def perfect_menu(materials, cookbooks, attribute, limit) do\n\n end\nend",
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"sampleTestCase": "[3,2,4,1,2]\n[[1,1,0,1,2],[2,1,4,0,0],[3,2,4,1,0]]\n[[3,2],[2,4],[7,6]]\n5",
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