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3sum.json
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{
"data": {
"question": {
"questionId": "15",
"questionFrontendId": "15",
"categoryTitle": "Algorithms",
"boundTopicId": 1089,
"title": "3Sum",
"titleSlug": "3sum",
"content": "<p>Given an integer array nums, return all the triplets <code>[nums[i], nums[j], nums[k]]</code> such that <code>i != j</code>, <code>i != k</code>, and <code>j != k</code>, and <code>nums[i] + nums[j] + nums[k] == 0</code>.</p>\n\n<p>Notice that the solution set must not contain duplicate triplets.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> nums = [-1,0,1,2,-1,-4]\n<strong>Output:</strong> [[-1,-1,2],[-1,0,1]]\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> nums = []\n<strong>Output:</strong> []\n</pre><p><strong>Example 3:</strong></p>\n<pre><strong>Input:</strong> nums = [0]\n<strong>Output:</strong> []\n</pre>\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 <= nums.length <= 3000</code></li>\n\t<li><code>-10<sup>5</sup> <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
"translatedTitle": "三数之和",
"translatedContent": "<p>给你一个包含 <code>n</code> 个整数的数组 <code>nums</code>,判断 <code>nums</code> 中是否存在三个元素 <em>a,b,c ,</em>使得 <em>a + b + c = </em>0 ?请你找出所有和为 <code>0</code> 且不重复的三元组。</p>\n\n<p><strong>注意:</strong>答案中不可以包含重复的三元组。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [-1,0,1,2,-1,-4]\n<strong>输出:</strong>[[-1,-1,2],[-1,0,1]]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = []\n<strong>输出:</strong>[]\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [0]\n<strong>输出:</strong>[]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 <= nums.length <= 3000</code></li>\n\t<li><code>-10<sup>5</sup> <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"name": "Array",
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"translatedName": "数组",
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{
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"code": "class Solution {\npublic:\n vector<vector<int>> threeSum(vector<int>& nums) {\n\n }\n};",
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"lang": "Python",
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"code": "class Solution(object):\n def threeSum(self, nums):\n \"\"\"\n :type nums: List[int]\n :rtype: List[List[int]]\n \"\"\"",
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"code": "\n\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** threeSum(int* nums, int numsSize, int* returnSize, int** returnColumnSizes){\n\n}",
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"code": "# @param {Integer[]} nums\n# @return {Integer[][]}\ndef three_sum(nums)\n\nend",
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"code": "class Solution {\n fun threeSum(nums: IntArray): List<List<Int>> {\n\n }\n}",
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"code": "impl Solution {\n pub fn three_sum(nums: Vec<i32>) -> Vec<Vec<i32>> {\n\n }\n}",
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"code": "(define/contract (three-sum nums)\n (-> (listof exact-integer?) (listof (listof exact-integer?)))\n\n )",
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"lang": "Elixir",
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"hints": [
"So, we essentially need to find three numbers x, y, and z such that they add up to the given value. If we fix one of the numbers say x, we are left with the two-sum problem at hand!",
"For the two-sum problem, if we fix one of the numbers, say <pre>x</pre>, we have to scan the entire array to find the next number<pre>y</pre> which is <pre>value - x</pre> where value is the input parameter. Can we change our array somehow so that this search becomes faster?",
"The second train of thought for two-sum is, without changing the array, can we use additional space somehow? Like maybe a hash map to speed up the search?"
],
"solution": null,
"status": null,
"sampleTestCase": "[-1,0,1,2,-1,-4]",
"metaData": "{\n \"name\": \"threeSum\",\n \"params\": [\n {\n \"name\": \"nums\",\n \"type\": \"integer[]\"\n }\n ],\n \"return\": {\n \"type\": \"list<list<integer>>\",\n \"colsize\": 3,\n \"dealloc\": true\n }\n}",
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