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DFPeFJ.json
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{
"data": {
"question": {
"questionId": "1000220",
"questionFrontendId": "LCP 35",
"categoryTitle": "Algorithms",
"boundTopicId": 713325,
"title": "电动车游城市",
"titleSlug": "DFPeFJ",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "电动车游城市",
"translatedContent": "小明的电动车电量充满时可行驶距离为 `cnt`,每行驶 1 单位距离消耗 1 单位电量,且花费 1 单位时间。小明想选择电动车作为代步工具。地图上共有 N 个景点,景点编号为 0 ~ N-1。他将地图信息以 `[城市 A 编号,城市 B 编号,两城市间距离]` 格式整理在在二维数组 `paths`,表示城市 A、B 间存在双向通路。初始状态,电动车电量为 0。每个城市都设有充电桩,`charge[i]` 表示第 i 个城市每充 1 单位电量需要花费的单位时间。请返回小明最少需要花费多少单位时间从起点城市 `start` 抵达终点城市 `end`。\n\n\n**示例 1:**\n>输入:`paths = [[1,3,3],[3,2,1],[2,1,3],[0,1,4],[3,0,5]], cnt = 6, start = 1, end = 0, charge = [2,10,4,1]`\n>\n>输出:`43`\n>\n>解释:最佳路线为:1->3->0。\n>在城市 1 仅充 3 单位电至城市 3,然后在城市 3 充 5 单位电,行驶至城市 5。\n>充电用时共 3\\*10 + 5\\*1= 35\n>行驶用时 3 + 5 = 8,此时总用时最短 43。\n\n\n\n\n\n**示例 2:**\n>输入:`paths = [[0,4,2],[4,3,5],[3,0,5],[0,1,5],[3,2,4],[1,2,8]], cnt = 8, start = 0, end = 2, charge = [4,1,1,3,2]`\n>\n>输出:`38`\n>\n>解释:最佳路线为:0->4->3->2。\n>城市 0 充电 2 单位,行驶至城市 4 充电 8 单位,行驶至城市 3 充电 1 单位,最终行驶至城市 2。\n>充电用时 4\\*2+2\\*8+3\\*1 = 27\n>行驶用时 2+5+4 = 11,总用时最短 38。\n\n**提示:**\n- `1 <= paths.length <= 200`\n- `paths[i].length == 3`\n- `2 <= charge.length == n <= 100`\n- `0 <= path[i][0],path[i][1],start,end < n`\n- `1 <= cnt <= 100`\n- `1 <= path[i][2] <= cnt`\n- `1 <= charge[i] <= 100`\n- 题目保证所有城市相互可以到达",
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"difficulty": "Hard",
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{
"lang": "C++",
"langSlug": "cpp",
"code": "class Solution {\npublic:\n int electricCarPlan(vector<vector<int>>& paths, int cnt, int start, int end, vector<int>& charge) {\n\n }\n};",
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"code": "class Solution {\n public int electricCarPlan(int[][] paths, int cnt, int start, int end, int[] charge) {\n\n }\n}",
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{
"lang": "Python",
"langSlug": "python",
"code": "class Solution(object):\n def electricCarPlan(self, paths, cnt, start, end, charge):\n \"\"\"\n :type paths: List[List[int]]\n :type cnt: int\n :type start: int\n :type end: int\n :type charge: List[int]\n :rtype: int\n \"\"\"",
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"code": "class Solution:\n def electricCarPlan(self, paths: List[List[int]], cnt: int, start: int, end: int, charge: List[int]) -> int:",
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"lang": "C",
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"code": "\n\nint electricCarPlan(int** paths, int pathsSize, int* pathsColSize, int cnt, int start, int end, int* charge, int chargeSize){\n\n}",
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"lang": "C#",
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"code": "public class Solution {\n public int ElectricCarPlan(int[][] paths, int cnt, int start, int end, int[] charge) {\n\n }\n}",
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"code": "class Solution {\n\n /**\n * @param Integer[][] $paths\n * @param Integer $cnt\n * @param Integer $start\n * @param Integer $end\n * @param Integer[] $charge\n * @return Integer\n */\n function electricCarPlan($paths, $cnt, $start, $end, $charge) {\n\n }\n}",
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"lang": "Swift",
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"code": "class Solution {\n func electricCarPlan(_ paths: [[Int]], _ cnt: Int, _ start: Int, _ end: Int, _ charge: [Int]) -> Int {\n\n }\n}",
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"lang": "Kotlin",
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"code": "class Solution {\n fun electricCarPlan(paths: Array<IntArray>, cnt: Int, start: Int, end: Int, charge: IntArray): Int {\n\n }\n}",
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"lang": "Dart",
"langSlug": "dart",
"code": "class Solution {\n int electricCarPlan(List<List<int>> paths, int cnt, int start, int end, List<int> charge) {\n\n }\n}",
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"lang": "Go",
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"code": "# @param {Integer[][]} paths\n# @param {Integer} cnt\n# @param {Integer} start\n# @param {Integer} end\n# @param {Integer[]} charge\n# @return {Integer}\ndef electric_car_plan(paths, cnt, start, end, charge)\n\nend",
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"lang": "Scala",
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"code": "object Solution {\n def electricCarPlan(paths: Array[Array[Int]], cnt: Int, start: Int, end: Int, charge: Array[Int]): Int = {\n\n }\n}",
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{
"lang": "Rust",
"langSlug": "rust",
"code": "impl Solution {\n pub fn electric_car_plan(paths: Vec<Vec<i32>>, cnt: i32, start: i32, end: i32, charge: Vec<i32>) -> i32 {\n\n }\n}",
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"lang": "Erlang",
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"code": "-spec electric_car_plan(Paths :: [[integer()]], Cnt :: integer(), Start :: integer(), End :: integer(), Charge :: [integer()]) -> integer().\nelectric_car_plan(Paths, Cnt, Start, End, Charge) ->\n .",
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"lang": "Elixir",
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"code": "defmodule Solution do\n @spec electric_car_plan(paths :: [[integer]], cnt :: integer, start :: integer, end :: integer, charge :: [integer]) :: integer\n def electric_car_plan(paths, cnt, start, end, charge) do\n\n end\nend",
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