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1-bit-and-2-bit-characters.json
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{
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"question": {
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"categoryTitle": "Algorithms",
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"title": "1-bit and 2-bit Characters",
"titleSlug": "1-bit-and-2-bit-characters",
"content": "<p>We have two special characters:</p>\n\n<ul>\n\t<li>The first character can be represented by one bit <code>0</code>.</li>\n\t<li>The second character can be represented by two bits (<code>10</code> or <code>11</code>).</li>\n</ul>\n\n<p>Given a binary array <code>bits</code> that ends with <code>0</code>, return <code>true</code> if the last character must be a one-bit character.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> bits = [1,0,0]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> The only way to decode it is two-bit character and one-bit character.\nSo the last character is one-bit character.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> bits = [1,1,1,0]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> The only way to decode it is two-bit character and two-bit character.\nSo the last character is not one-bit character.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= bits.length <= 1000</code></li>\n\t<li><code>bits[i]</code> is either <code>0</code> or <code>1</code>.</li>\n</ul>\n",
"translatedTitle": "1 比特与 2 比特字符",
"translatedContent": "<p>有两种特殊字符:</p>\n\n<ul>\n\t<li>第一种字符可以用一比特 <code>0</code> 表示</li>\n\t<li>第二种字符可以用两比特(<code>10</code> 或 <code>11</code>)表示</li>\n</ul>\n\n<p>给你一个以 <code>0</code> 结尾的二进制数组 <code>bits</code> ,如果最后一个字符必须是一个一比特字符,则返回 <code>true</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> bits = [1, 0, 0]\n<strong>输出:</strong> true\n<strong>解释:</strong> 唯一的解码方式是将其解析为一个两比特字符和一个一比特字符。\n所以最后一个字符是一比特字符。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>bits = [1,1,1,0]\n<strong>输出:</strong>false\n<strong>解释:</strong>唯一的解码方式是将其解析为两比特字符和两比特字符。\n所以最后一个字符不是一比特字符。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= bits.length <= 1000</code></li>\n\t<li><code>bits[i]</code> 为 <code>0</code> 或 <code>1</code></li>\n</ul>\n",
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"code": "class Solution {\npublic:\n bool isOneBitCharacter(vector<int>& bits) {\n\n }\n};",
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