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4ueAj6.json
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{
"data": {
"question": {
"questionId": "1000265",
"questionFrontendId": "剑指 Offer II 029",
"categoryTitle": "LCOF2",
"boundTopicId": 910265,
"title": "排序的循环链表",
"titleSlug": "4ueAj6",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "排序的循环链表",
"translatedContent": "<p>给定<strong>循环单调非递减列表</strong>中的一个点，写一个函数向这个列表中插入一个新元素 <code>insertVal</code> ，使这个列表仍然是循环升序的。</p>\n\n<p>给定的可以是这个列表中任意一个顶点的指针，并不一定是这个列表中最小元素的指针。</p>\n\n<p>如果有多个满足条件的插入位置，可以选择任意一个位置插入新的值，插入后整个列表仍然保持有序。</p>\n\n<p>如果列表为空（给定的节点是 <code>null</code>），需要创建一个循环有序列表并返回这个节点。否则。请返回原先给定的节点。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/01/19/example_1_before_65p.jpg\" style=\"height: 149px; width: 250px;\" /><br />\n </p>\n\n<pre>\n<strong>输入：</strong>head = [3,4,1], insertVal = 2\n<strong>输出：</strong>[3,4,1,2]\n<strong>解释：</strong>在上图中，有一个包含三个元素的循环有序列表，你获得值为 3 的节点的指针，我们需要向表中插入元素 2 。新插入的节点应该在 1 和 3 之间，插入之后，整个列表如上图所示，最后返回节点 3 。\n\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/01/19/example_1_after_65p.jpg\" style=\"height: 149px; width: 250px;\" />\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>head = [], insertVal = 1\n<strong>输出：</strong>[1]\n<strong>解释：</strong>列表为空（给定的节点是 <code>null</code>），创建一个循环有序列表并返回这个节点。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>head = [1], insertVal = 0\n<strong>输出：</strong>[1,0]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= Number of Nodes <= 5 * 10^4</code></li>\n\t<li><code><font face=\"monospace\">-10^6 <= Node.val <= 10^6</font></code></li>\n\t<li><code>-10^6 <= insertVal <= 10^6</code></li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 708 题相同： <a href=\"https://leetcode-cn.com/problems/insert-into-a-sorted-circular-linked-list/\">https://leetcode-cn.com/problems/insert-into-a-sorted-circular-linked-list/</a></p>\n",
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"topicTags": [
{
"name": "Linked List",
"slug": "linked-list",
"translatedName": "链表",
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"code": "/*\n// Definition for a Node.\nclass Node {\npublic:\n int val;\n Node* next;\n\n Node() {}\n\n Node(int _val) {\n val = _val;\n next = NULL;\n }\n\n Node(int _val, Node* _next) {\n val = _val;\n next = _next;\n }\n};\n*/\n\nclass Solution {\npublic:\n Node* insert(Node* head, int insertVal) {\n \n }\n};",
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"code": "/*\n// Definition for a Node.\nclass Node {\n public int val;\n public Node next;\n\n public Node() {}\n\n public Node(int _val) {\n val = _val;\n }\n\n public Node(int _val, Node _next) {\n val = _val;\n next = _next;\n }\n};\n*/\n\nclass Solution {\n public Node insert(Node head, int insertVal) {\n \n }\n}",
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"code": "\"\"\"\n# Definition for a Node.\nclass Node(object):\n def __init__(self, val=None, next=None):\n self.val = val\n self.next = next\n\"\"\"\n\nclass Solution(object):\n def insert(self, head, insertVal):\n \"\"\"\n :type head: Node\n :type insertVal: int\n :rtype: Node\n \"\"\"\n\t\t",
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"code": "/**\n * // Definition for a Node.\n * function Node(val, next) {\n * this.val = val;\n * this.next = next;\n * };\n */\n\n/**\n * @param {Node} head\n * @param {number} insertVal\n * @return {Node}\n */\nvar insert = function(head, insertVal) {\n \n};",
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"lang": "Go",
"langSlug": "golang",
"code": "/**\n * Definition for a Node.\n * type Node struct {\n * Val int\n * Next *Node\n * }\n */\n\nfunc insert(aNode *Node, x int) *Node {\n \n}",
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