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SsGoHC.json
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{
"data": {
"question": {
"questionId": "1000338",
"questionFrontendId": "剑指 Offer II 074",
"categoryTitle": "LCOF2",
"boundTopicId": 910332,
"title": "合并区间",
"titleSlug": "SsGoHC",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "合并区间",
"translatedContent": "<p>以数组 <code>intervals</code> 表示若干个区间的集合，其中单个区间为 <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> 。请你合并所有重叠的区间，并返回一个不重叠的区间数组，该数组需恰好覆盖输入中的所有区间。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,3],[2,6],[8,10],[15,18]]\n<strong>输出：</strong>[[1,6],[8,10],[15,18]]\n<strong>解释：</strong>区间 [1,3] 和 [2,6] 重叠, 将它们合并为 [1,6].\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,4],[4,5]]\n<strong>输出：</strong>[[1,5]]\n<strong>解释：</strong>区间 [1,4] 和 [4,5] 可被视为重叠区间。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= intervals.length <= 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>0 <= start<sub>i</sub> <= end<sub>i</sub> <= 10<sup>4</sup></code></li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 56 题相同： <a href=\"https://leetcode-cn.com/problems/merge-intervals/\">https://leetcode-cn.com/problems/merge-intervals/</a></p>\n",
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"code": "class Solution {\npublic:\n vector<vector<int>> merge(vector<vector<int>>& intervals) {\n\n }\n};",
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"code": "class Solution(object):\n def merge(self, intervals):\n \"\"\"\n :type intervals: List[List[int]]\n :rtype: List[List[int]]\n \"\"\"",
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"code": "\n\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** merge(int** intervals, int intervalsSize, int* intervalsColSize, int* returnSize, int** returnColumnSizes){\n\n}",
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